PROJECTION OF SOLIDS SOLVED PROBLEM 6 IN HINDI IN ENGINEERING DRAWING
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- Опубліковано 9 вер 2024
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TODAY WE WILL STUDY 6TH PROBLEM ON PROJECTION OF SOLIDS.
QUE : DRAW THE PROJECTION OF A CUBE OF 40MM LONG EDGES RESTING ON HP ON ONE OF ITS CORNER WITH A SOLID DIAGONAL PARALLEL TO HP AND PERPENDICULAR TO VP.
👉 BASICS OF PROJECTION OF SOLID PART 1 :
• PROJECTION OF SOLIDS I...
👉 BASICS OF PROJECTION OF SOLID PART 2 :
• PROJECTION OF SOLIDS I...
PLEASE WATCH THE COMPLETE VIDEO TO CLEAR ALL YOUR DOUBTS.
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#planeofprojection
#projectionofstraightline
#projectionofpoints
#engineeringdrawing
#engineeringgraphics
#isometricprojection
#orthographicprojection
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#projectionofplanes
#projectionofsolids
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Thanku so much sir
Mujhe ye bahut ache se clear ho gya
Thanku again ☺☺👍
Dhanyawad Guruji 🙏 🙏🙏🙏🙏
Sir your my god❤️!!!
Good english very
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@@NakulSonkusare-01😂😂😂
Thank for teaching this....
I have started watching your lectures today...
And i have already watched for 5-6 hrs....
Great teacher...
Bro.. just play it in 1.75x playback speed..it will help .you will understand for more and time will be saved too..
Thank you so much Sir for clearing every doubts and give concept to solve drawing problems.
Sir aapka padhane ka tarika bahut aacha hai
Thanks for watching
Thank you sir. Your videos are very helpful for me
Thank you so much sir that i could do well in exams because of these videos
thank you sir
Thanks for watching
God bless you
Thank you so much sir
very good video sir but this is not how we do it , we donot do middle drwaings , so please donot waste your important time by teaching middle drawings it is of no use . Sir your suite is nice.
❤❤❤ superb
Thenk you so much sir 🎉❤
Thank you so much sir❤️✨
You helped me alot❤️✨
hexagonal pyramid, side of the base 25 mm long and height 70 mm, has one
of its triangular faces perpendicular to the H.P. and inclined at 45° to the V.P.
The base-side of this triangular face is parallel to the H.P. Draw its projections. By auxillary method
Can u pls ans this question
Thank you sir 🙏this is helpful 🙏
Great explaining sir ❤️❤️❤️❤️
Tysir 🙏🙏
❤
🎉🎉🎉
1no
Thank you sir ❤️
Nice video sar
Thanks for watching
Draw the projection of a cube 25 mm when it is resting on one of its corners of base in such a way that base makes an angle 45° with the H.P. and vertival edges are parallel to the V.P.
Super sir
Thanks for watching
thank you sir 👍
Sir some u draw on xy some below xy why?
Sir, angle between diagonal and base is 40°
90°+35°+55° = 180°. It's correct. 14:58
Sir ab group 2 ke liye graphics ke videos banaye sir
Group 2 me aapko kya syllabus hai batao.
Sir second semester me humlogo ko Graphics padhna h or syllabus ye h
Unit 1- Drawing instrument and their uses.
Unit 2 - Engineering curves and loci for point
Unit 3 - Orthographic projection
Unit 4- isometric projection
Unit 5 - line inclined to one reference plane only and limited to both ends in one qyadrant
Out of these,
1) Orthographic Projection,
2) Isometric Projection,
3) Engineering Curves,
4) Straight Line
Are already available on my UA-cam channel with number of solved problems. Please visit the playlist of all these topics on my UA-cam channel.
&
Loci of Points will come soon..... please wait and keep in touch.
Also more videos will come on above all the topics.
Zin of engineering world 🌍😊
Draw the projections of a cube of 25 mm long edges resting on the H.P on
one of its corners with a solid diagonal perpendicular to the V.P.
Development surface ke uppar video banav
How the third figure is perpendicular to vp??
exctly
Sir is problem mai reduced length nahi ayega kya??
Sir how can we know that the given angle is beta or true length's inclination sir..?
I will answer this question in my 5th DOUBTS SESSION in Sunday's video.
@@TIKLESACADEMY please provide the video sir
Agar sir is question me parallel to HP nhi diya ho to kese bnayege
😮
Reply me