You make a superb point here. I just tried CAS "solve(3*x-1=1.03^x)" on the HP Prime and got two valid answers. 0.67336... and 219.51151... On the HP 48GX, using the solver, I had to put in 157 before it would find the 219.51151... answer. Any lower and it would find 0.67336... I did not try using CAS on it. Even when I used 219.5115 as a starting point on my DM42, it finds 0.67336. Not as "smart" as the HP 48GX, it seems. But super accurate w/ the solution it does find. Thanks for the useful and interesting comment, Arjunaidi.
Good catch. You are the second person to catch my oversight. Helpful info for me and for anyone who watches the video. Thanks for taking the time to point this out. Take care.
I have since improved somewhat on my approach shown in this video, but it will serve as a starting point for you to learn how you might use the CST menu: ua-cam.com/video/pvofVRnH1ws/v-deo.html
GREAT point. Yes, indeed there are two solutions as I probably should have realized. Does the TI-89 automatically find both solutions, or did you enter two different starting values? I'm guessing that because it is has a CAS (computer algebra system), it actually "solves" the problem, finding both solutions, rather than iterating the solution as I'm doing in the video. Thanks for the feedback.
Hi, Leandro. Thanks for the feedback. When you say "get the roots" do you mean like the "cube root of 27" and the "square root of 5"? As far as "shortcuts", do you mean how to create your own shortcuts that appear in the custom menu? If so, I definitely could do that -- what type of shortcut are you thinking of?
@@leandrosueldo9247 The calculator is rewarding, but definitely takes some time to figure out how to use it. To find roots of the polynomial "x^3 + 2x^2 - 29x + 42": Enter coeff onto stack: [1 2 -29 42] Enter "Poly Roots" command: PROOT You should get the answer: [2 3 -7] These are the 3 roots
I guess I wanted to show something that I had found helpful, but I can see why it would be frustrating in your situation where you are just trying to use it without any modifications. Were you able to get the solver working yet? If not, I could see if I can find info to help or possibly even make my own short video. Let me know.
@@scottcollins7513 Thank you for replying. My feedback is that many people watch your videos to learn, so keeping the standard settings is important for them to replicate the steps and understand how it works. Thanks.
![Why you didn't learn tetration in school[Tetration]](/img/n.gif)
It is easier to use the CAS button on the HP Prime to solve for x. Great video, as always.
You make a superb point here. I just tried CAS "solve(3*x-1=1.03^x)" on the HP Prime and got two valid answers. 0.67336... and 219.51151...
On the HP 48GX, using the solver, I had to put in 157 before it would find the 219.51151... answer. Any lower and it would find 0.67336... I did not try using CAS on it.
Even when I used 219.5115 as a starting point on my DM42, it finds 0.67336. Not as "smart" as the HP 48GX, it seems. But super accurate w/ the solution it does find.
Thanks for the useful and interesting comment, Arjunaidi.
Completely off topic, but what is that white e-ink tablet looking thing you have the equation written on?
It is called "reMarkable" tablet.
@@scottcollins7513 Thanks!
Is there a command on the 48GX to evaluate log base x of a number y? ie log base 9 of 81 which of course is 2...
www.hpcalc.org/hp48/docs/faq/48faq-5.html
This says NO, but you can create a small program to make it easier.
@@scottcollins7513 isn't odd that this operation was not programmed into the 48 gx.
Except...that's only 1 answer..there is a 2nd solution at 219.511.. Try the prime 'solve' function(CAS mode)..or plot the function out to x=240
Good catch. You are the second person to catch my oversight. Helpful info for me and for anyone who watches the video. Thanks for taking the time to point this out. Take care.
Hey, could u please explain to me how do I find the command RREF?
Sebastian, it took me a while to get out my old manual.
The command can be found under MTH > MATR > FACTR > RREF
please i cant find any thing when i push cst button ,how can i install this features
I have since improved somewhat on my approach shown in this video, but it will serve as a starting point for you to learn how you might use the CST menu: ua-cam.com/video/pvofVRnH1ws/v-deo.html
Ti 89 says that 219.5 is also a solution
GREAT point. Yes, indeed there are two solutions as I probably should have realized. Does the TI-89 automatically find both solutions, or did you enter two different starting values? I'm guessing that because it is has a CAS (computer algebra system), it actually "solves" the problem, finding both solutions, rather than iterating the solution as I'm doing in the video. Thanks for the feedback.
@@scottcollins7513 Yes, the 89 found both solutions automatically. Actually, it also warned that more solutions may exist.
@@perfectman3077 That is impressive.
@@perfectman3077 Sorry to ask, how? the nsolve() just give you one answer.
@@franz2383 I used just "solve()"
Can you make a video explaining how to get the roots and shortcuts?
Hi, Leandro. Thanks for the feedback.
When you say "get the roots" do you mean like the "cube root of 27" and the "square root of 5"?
As far as "shortcuts", do you mean how to create your own shortcuts that appear in the custom menu? If so, I definitely could do that -- what type of shortcut are you thinking of?
Or do you mean "find the roots (zeros) of a polynomial" equation?
Scott Collins roots of a polynomial. I know it’s really basic but I cant understand this calculator haha
@@leandrosueldo9247 The calculator is rewarding, but definitely takes some time to figure out how to use it.
To find roots of the polynomial "x^3 + 2x^2 - 29x + 42":
Enter coeff onto stack: [1 2 -29 42]
Enter "Poly Roots" command: PROOT
You should get the answer: [2 3 -7]
These are the 3 roots
I rewatched the video and understand the "shortcut" you are talking about. I will do a video on this at some point.
WHY you didn't explain how to use solve?! WHY this personal "shortcut"? I just want to learn how to use the solve with the standard parameters.
I guess I wanted to show something that I had found helpful, but I can see why it would be frustrating in your situation where you are just trying to use it without any modifications. Were you able to get the solver working yet? If not, I could see if I can find info to help or possibly even make my own short video. Let me know.
@@scottcollins7513 Thank you for replying. My feedback is that many people watch your videos to learn, so keeping the standard settings is important for them to replicate the steps and understand how it works. Thanks.
@@JohnUsp Good point, John. I may make a video showing this if I cannot easily find one already made on youtube. Take care.