Thanks for your comment, your appreciation always motivate us to do such kind work. Join Telegram Channel : t.me/mathsbygpsir Instagram Handle : instagram.com/dr.gajendrapurohit/ Facebook Page : facebook.com/Dr-Gajendra-Purohit-453775988491992/ Unacademy : unacademy.com/@Dr-GajendraPurohit Link to B.Sc. Maths Playlist : bit.ly/34tTTdc Link to Engineering Maths Playlist : bit.ly/2OQ7Uvd Link to IIT-JAM Maths Playlist : bit.ly/2sh9pei Link to GATE (Engg.) Maths Playlist : bit.ly/35EAPct Link to IAS Optional Maths Playlist : bit.ly/2rwkOqj Link to CSIR NET Maths Playlist : bit.ly/2R8sUjV Link to Aptitude Playlist : bit.ly/3ewDR7z Link to Mathematical Physics Playlist : bit.ly/2NvRHLJ Link to Abstract Algebra Playlist : bit.ly/2A70LUb Link to General Aptitude For CSIR NET : bit.ly/2ZeWpma Follwing Topics are also Available 1. Differential Calculus : bit.ly/2OTYXB0 2. Integral Calculus : bit.ly/34rLA1R 3. Differential Equation : bit.ly/37IOlO1 4. Partial Differential Equation : bit.ly/2OM5iyA 5. Complex Analysis : bit.ly/2OP8hGp 6. Numerical Analysis : bit.ly/2QYVQuy 7. Integral Transform (Laplace, Fourier & Z-Transform) : bit.ly/37HRKg9 8. Statistics & Probability : bit.ly/2DmOt7Z 9. Operation Research : bit.ly/2pYYRjp 10. Matrices (Linear Algebra) : bit.ly/2OOBSzO 11. Fourier Series : bit.ly/34u7iC9 12. Vector Calculus : bit.ly/2qICwXO 13. Theory Of Equation : bit.ly/2XU9y33 14. Special Function & Series Solution : bit.ly/2XRSU4l 15. Infinite Series : bit.ly/37K6gUI 16. Group Theory : bit.ly/3ieUze2 Please share it with your Friends Thanks Dr.Gajendra Purohit
Sir plz start any topic with basic lavel and said all topic significant and real life example?? so we will understand easyly.Plz relate physics with real life . Sir plz don't underestimate my opinion.
If 75% of all purchases at a certain store is made with a credit card and X is the number among the ten randomly selected purchases made with credit card. Then find P(μ- 2σ< x < µ +2σ) where is µ the mean and σ is the standard deviation of the distribution Hello please ye question explain krdi jiya
In our country where everyone doesn't have enough resources to get paid tuitions, you are really doing a brilliant job to serve the society. Especially in this covid time, such online content is very important. Please keep it up and we all wish that one day you will have highest number of subscribers.....
Sir your videos are the only place I understand stuff at once. Nearly every student in my hostel is studying maths from your videos. The math profs at our college aren't bad but they just don't teach as good as you do. Big thanks for uploading this material free of cost on youtube! Never stop the great work! A huge THANK YOU from my side! DESERVES MILLIONS OF VIEWS
Sir, at 20:29 direct putting the value of x(let 1.5) in commulative distribution function will give the the value of P(x=1.5) and Thank you so much for this nice content.
thanks sir for explaining so well .. but attention everyone .. i think at 20:40 there i think sir missed a point that P(x>=1.5) will be equal to {1-P(x
00:11 Dr. Gajendra Purohit explains continuous random variable and its PDF and CDF 02:39 The video discusses solving mean and variance of discrete and random variables. 05:41 Technique to solve questions involving time intervals 08:29 A list of numerical values with increasing order. 11:14 Cumulative distribution system explained with examples 13:48 A list of timestamp ranges is given. 16:20 A list of numerical values 18:59 A tutorial on solving a question using mathematical expectation and moments.
@Raj Goswami at 8:38 sir calculated the p(x< = 1.5 ) which is written in the definition Cdf = p(X=1.5) so we can find through this method like p(x>=1.5) = 1 -p(x
Nice lecture sir!... Aapka padhane ka speed bhi sahi hai, mei jo bhi lecture dekhta hu usko 1.5 ya 1.75 speed pr hi dekhta hu...aapke lecture speed badhane ka jarurt bhi nhi padha....
Sir your explanation is really Awesome but your hand writing are total Opposite to your explanation. Some time it'd really give hard time to understand what you write. Thank you so much for this wonderful explanation . It helps me to prepare for my examination.
It's really very good and well defined content. Respect you sir and you're really doing good for us. Its a hope for us those topics which is really very tough to understand is now easy and interesting for me. Thankyou thanks a lot sir please keep doing 😊😊😊😊😊😊
Hello Priyanka Rath Thanks for Subscribing!, your appreciation always motivate us to do such kind work. Preparing CSIR NET ? Then Follow me on Unacademy Link:-unacademy.com/user/Dr-GajendraPurohit Please Share it With Your Friends Want to get notes and link of videos with latest update then Connect me on Whasapp Group Link:- chat.whatsapp.com/Fck1k8gzunMLVL70DdG4eK Keep Watching OUR latest video. Topic:-IIT-JAM Mathematics ua-cam.com/video/eTp5wq-cSXY/v-deo.html Topic:-GATE (Engineering Mathematics) ua-cam.com/video/p5rBJj5CKCg/v-deo.html Topic:-B.Sc. Mathematics ua-cam.com/video/WX6O9TiFYsA/v-deo.html Topic:-IAS Optional Mathematics ua-cam.com/video/p5rBJj5CKCg/v-deo.html Topic:-Engineering Mathematics ua-cam.com/video/p5rBJj5CKCg/v-deo.html Please share it with your Friends Thanks Dr.Gajendra Purohit
SIR ,YOU ARE DOING VERY MUCH EFFORT FOR US AND YOUR VIDEO'S ARE VERY HELPFUL FOR US BUT SOME TIME SIR YOU HAVE TO MAKE 2 PART OF THE ANY TOPIC WHICH IS LIKE THIS SO THAT YOU CAN EXPLAIN IT VERY EASY AND SUFFICIENTLY.
Hello Patel Smit Thanks for Subscribing!, your appreciation always motivate us to do such kind work. Preparing CSIR NET ? Then Follow me on Unacademy Link:-unacademy.com/user/Dr-GajendraPurohit Please Share it With Your Friends Want to get notes and link of videos with latest update then Connect me on Whasapp Group Link:- chat.whatsapp.com/Fck1k8gzunMLVL70DdG4eK Keep Watching OUR latest video. Topic:-IIT-JAM Mathematics ua-cam.com/video/eTp5wq-cSXY/v-deo.html Topic:-GATE (Engineering Mathematics) ua-cam.com/video/p5rBJj5CKCg/v-deo.html Topic:-B.Sc. Mathematics ua-cam.com/video/WX6O9TiFYsA/v-deo.html Topic:-IAS Optional Mathematics ua-cam.com/video/p5rBJj5CKCg/v-deo.html Topic:-Engineering Mathematics ua-cam.com/video/p5rBJj5CKCg/v-deo.html Please share it with your Friends Thanks Dr.Gajendra Purohit
00:12 Introduction to continuous random variable and probability distribution function. 02:19 Solving mean and variance of discrete random variables 05:13 Understanding Random Variables and Distribution Functions 08:15 Solving questions using random variable and probability distributions 11:06 Understanding cumulative distribution function 13:48 Random variable represents outcomes of a random phenomenon 16:43 Random variables and probability functions 19:14 Solving questions using probability concepts
If 75% of all purchases at a certain store is made with a credit card and X is the number among the ten randomly selected purchases made with credit card. Then find P(μ- 2σ< x < µ +2σ) where is µ the mean and σ is the standard deviation of the distribution
@@deathcureyt344if a function is given means f(x)=f(-x) then the limit of f(x) from -a to a is same as 2f(x) limit from 0 to a .even functions r symmetrical about y axis so calculating area form -3to 3 is same as 2 time from 0 to 3 .I hope it helps
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5. Complex Analysis : bit.ly/2OP8hGp
6. Numerical Analysis : bit.ly/2QYVQuy
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9. Operation Research : bit.ly/2pYYRjp
10. Matrices (Linear Algebra) : bit.ly/2OOBSzO
11. Fourier Series : bit.ly/34u7iC9
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Sir plz start any topic with basic lavel and said all topic significant and real life example?? so we will understand easyly.Plz relate physics with real life . Sir plz don't underestimate my opinion.
Sir ji fumble karte ho aap thoda other than that u are tooo gooood
Sarey formula milkar koi ek super formula hain Kya jo sure bata dein???
Shares market main Kya probability for sure formula hain????
If 75% of all purchases at a certain store is made with a credit card and X is the number among the ten randomly selected purchases made with credit card. Then find P(μ- 2σ< x < µ +2σ) where is µ the mean and σ is the standard deviation of the distribution
Hello please ye question explain krdi jiya
In our country where everyone doesn't have enough resources to get paid tuitions, you are really doing a brilliant job to serve the society. Especially in this covid time, such online content is very important.
Please keep it up and we all wish that one day you will have highest number of subscribers.....
Thank you for explaining so nicely.I also wanted to say that around 20:40 ,P(x>=1.5) !=F(1.5).Actually it should be 1-F(1.5).(CORRECTION)
Thank u bhai💛💛
Yeah thnx someone said it
Bro, Can u explain to me why and what is the next step.
Can u please elaborate??
@@rakeshranjanprabhat9218 P(x>=1.5)=1-P(x
Sir your videos are the only place I understand stuff at once. Nearly every student in my hostel is studying maths from your videos. The math profs at our college aren't bad but they just don't teach as good as you do.
Big thanks for uploading this material free of cost on youtube!
Never stop the great work!
A huge THANK YOU from my side!
DESERVES MILLIONS OF VIEWS
Yes 👍 videos are very good
very knowledgeable person ! respect from my side
In my college , even teachers are not able to clearify our concepts, Thank you , G.P. sir ...
Sir, at 20:29 direct putting the value of x(let 1.5) in commulative distribution function will give the the value of P(x=1.5) and Thank you so much for this nice content.
I guess it should have been 1-P(x
Correct
thanks i got confused here , bcz i try to calculate the value as sir said but i am not getting 0.125 as answer.
Exactly
thanks sir for explaining so well ..
but attention everyone .. i think at 20:40 there i think sir missed a point that P(x>=1.5) will be equal to {1-P(x
nope !!!!
i calculated it and , integration from 1.5 to 2 = 0.125.
YYour are right mate it is indeed {1-P(x
Your lecture very helpful for exam thanks sir .❤❤❤
00:11 Dr. Gajendra Purohit explains continuous random variable and its PDF and CDF
02:39 The video discusses solving mean and variance of discrete and random variables.
05:41 Technique to solve questions involving time intervals
08:29 A list of numerical values with increasing order.
11:14 Cumulative distribution system explained with examples
13:48 A list of timestamp ranges is given.
16:20 A list of numerical values
18:59 A tutorial on solving a question using mathematical expectation and moments.
Helped me to clear my concepts and doubts. Thank You
Sir, at 20:40 for calculating P(X>=1.5), which is 1 - P(X
👍🏻👍🏻👍🏻👍🏻👍🏻👍🏻👍🏻👍🏻
Yhi hota h jab teachers ko khud ko kuch ata na ho or book se dekh dekh k bol rhe ho
@Daredevil no
bhai ye x>2 keliye 20:40 mein integration kerne per value 1 nhi aarhi plz help
@Raj Goswami at 8:38 sir calculated the p(x< = 1.5 ) which is written in the definition Cdf = p(X=1.5) so we can find through this method like p(x>=1.5) = 1 -p(x
So helpful
you are explaining perfectly sir!!!!keep helping us and stay safe!!!!!!
This video helped me a lot sir.Thank you so much
Thank you so much Sir...
Now I'm completely learned...
Love from kpk Malakand 🇵🇰
You reminded me of my favourite math lecturer sir. Thank you!! 🙏
Happy Teacher's day sir, will always be pleased to you for the last minute help.🎉🎉🎉❤❤
Thank you sir for your contributions, I will be grateful forever 🙏. You are helping me shape my future and I can't thank you enough.
Probably the best video so far on random variables . THANKS SIR
Sir I have question
18:19 time for ( x >2 ) we have take from -infinite to +infinite or 2 to +infinite
Cause (x
it should be 2 to infinity. It will become zero
Nice lecture sir!... Aapka padhane ka speed bhi sahi hai, mei jo bhi lecture dekhta hu usko 1.5 ya 1.75 speed pr hi dekhta hu...aapke lecture speed badhane ka jarurt bhi nhi padha....
Sir Your teaching methodology is too good
kaash ye video do saal pehle upload huyi hoti, mere ek backlog km hote😂😂
Bhai 2 year ago hi hai yeh
@Indian viewer nahi bhai, woh toh 9 months pehele comment kiya hai
Bhai is baar meri hai backlog ki exam 6 taarikh se 😂😂😂
Mere toh ekdm time pe uploaded h firbi padhne ka mann na karne ki wajah se nhi ho pa rha h😭😭😭
Bhai jaypee se hai kya??😢😢
You're best teacher I've ever come across
Sir your way of teaching is 🔥🔥 .
Sir , your explanation is good. Could you pls increase the amount of ques..
Atleast 2-3 different type ques.
Sir all yours video are too good and you explain it very nicely 😊 but in this topic i am confuse 😢
Very Helpful for Data Science also...👍
Thank you for explaining such nicely. Your videos are really helpful for understanding a concept .
First calculate for x
🙃
If u r calculating x
Sir I understand everything you taught ❤️❤️❤️
what an explanation sir !!!!!!!!!! wow
Hats off to you sir ji. Very well explained even better than my college🖒🖒
Sir you have played a huge role in my selection in IISER BHOPAL through JAM .
Thank you ❤️ so much from deep of my 💖💓 heart.
Thank u sir best sir for maths...🙏
Sir your explanation is really Awesome but your hand writing are total Opposite to your explanation. Some time it'd really give hard time to understand what you write.
Thank you so much for this wonderful explanation . It helps me to prepare for my examination.
Sir you're best teacher
It's really very good and well defined content.
Respect you sir and you're really doing good for us. Its a hope for us those topics which is really very tough to understand is now easy and interesting for me.
Thankyou thanks a lot sir please keep doing 😊😊😊😊😊😊
9:46 sir f(x) to interval -3
Thank you sir your video is very helpful for me.
Great sir! i am watching from pakistan
genius, superb, fantastic....
It is really helpful for GATE DS paper
love your videos sir🥰🥰🥰🥰
Great.
Thank you Sir. Your classes are very interesting. 😊🙏🙏🙏
Excellent sir 💯
Thanks❤❤
Great!
Great moment with you sir
This video helped a lot...
Your voice is very pleasing
college m samaj nhi aaya tha , yahan aa gya , thanks !!!!
Thankyou sir aap ki waja se mera probability ka paper bach gaya
thanks for the knowledge sir....😇
Superb explanation Sir Maza aa gaya
Kash thora Visible or achhe se hota joh board p likha hai!!
Grt explanation sir !
Thank you so much!
Sir you are such a gem 💎
Thanks a lot, Sir. The content is really Amazing.
Thank you so much sir for this video
Thanks sir I expect I will pass my exam
Thank you very much. This series of videos were very helpful :)
Series ka playlist bna hua hai?
Very simple,detailed and easy to learn explanation thank you so much sir
Thank you soo muchhhh sir...🙏🙏🙏....
Sir plz make a vedio about "function of Random Variables"plz plz plz
Hello Priyanka Rath
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Sir 💖Your style of explanation is Awesome 👏👏👏
such a nice lecture well describe highly efficient...
Sir your teaching good
clear cut concept delivering...No bakwas
wah sir kya udaya hai,.........
Thanks sir.
Appreciate your efforts 👏
SIR ,YOU ARE DOING VERY MUCH EFFORT FOR US AND YOUR VIDEO'S ARE VERY HELPFUL FOR US BUT SOME TIME SIR YOU HAVE TO MAKE 2 PART OF THE ANY TOPIC WHICH IS LIKE THIS SO THAT YOU CAN EXPLAIN IT VERY EASY AND SUFFICIENTLY.
Hello Patel Smit
Thanks for Subscribing!, your appreciation always motivate us to do such kind work.
Preparing CSIR NET ? Then Follow me on Unacademy Link:-unacademy.com/user/Dr-GajendraPurohit
Please Share it With Your Friends
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Keep Watching OUR latest video.
Topic:-IIT-JAM Mathematics
ua-cam.com/video/eTp5wq-cSXY/v-deo.html
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Topic:-B.Sc. Mathematics
ua-cam.com/video/WX6O9TiFYsA/v-deo.html
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❤Amazing
Sir you are gr8 actually
Sir god aapko bhot success de 🤲
Aap bhot accha se concept clear krte hai
THANK YOU SIR ! LOTS OF LOVE TO YOU
00:12 Introduction to continuous random variable and probability distribution function.
02:19 Solving mean and variance of discrete random variables
05:13 Understanding Random Variables and Distribution Functions
08:15 Solving questions using random variable and probability distributions
11:06 Understanding cumulative distribution function
13:48 Random variable represents outcomes of a random phenomenon
16:43 Random variables and probability functions
19:14 Solving questions using probability concepts
Sir please thoda slow padaya kro aap hume pada rahe h na ki khud pad rahe h
Toh kahi aur se padhlo. Be respectful to sir. He is legit giving GOLD content for FREE.
@@RituJaat-nt5hr ap apna video speed Kam kr lo......sir to thik he speed mein padha rhe h
Love you sir ❤
Very good explanation sir.....
Continue like these videos.....sir
If 75% of all purchases at a certain store is made with a credit card and X is the number among the ten randomly selected purchases made with credit card. Then find P(μ- 2σ< x < µ +2σ) where is µ the mean and σ is the standard deviation of the distribution
Sir one suggeetion - after solving whole question pl provide full view of green board so that we can take screen shot of whole answer
Sir at 8:44, how have you taken the value 2k outside the integration parentheses, I'm confused
because of even and odd integration of function
@@LapCreativeStudio how?
@@LapCreativeStudio can you explain?
@@deathcureyt344if a function is given means f(x)=f(-x) then the limit of f(x) from -a to a is same as 2f(x) limit from 0 to a .even functions r symmetrical about y axis so calculating area form -3to 3 is same as 2 time from 0 to 3 .I hope it helps
@@Anuragmishra208 tnx so much
GP Rocks!!!!!!!
Thank you so much sir
It really helped to get the concepts celarly.
Yeah that celarly* seen from your comment. 😂
Thanks a lot sir....U are the greatest teacher
Bhai Guruji Mauuj Kardi
thank you sir really helpful
20:03 ...Before it was correct Sir when we are writting distribution function then we can't write in separate interval ...
Sir U are amazing bus ek prob hai handwritting ki. And everything is just perfect and amazing.... Thank u.
After two sessions my right ear got justice 😂😂
Great thanks
awesome content
18:34
Isme to x>2 lena h na
To limits sirf 2 se infinite nhi lenge? 🤔
it will be x < 2, he did a mistake ig
Thank you.
Sir, thank you very much,.
thanku
لاجواب سر جی
nice lectures
Sir at 20:20 you have calculated P( X>= 1.5), but the calculation you have done it is for P( X
Yes issko aap explain kr dejiye ,mujhe bhi nhi smjh aaya hai
bro plz can u explain it for me
For P(X>=1.5) =1- P(X
@@SD_YT_2 Thanx
Sir you are great.