Linearity and nonlinear theories. Schrödinger's equation

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  • Опубліковано 4 лип 2017
  • MIT 8.04 Quantum Physics I, Spring 2016
    View the complete course: ocw.mit.edu/8-04S16
    Instructor: Barton Zwiebach
    License: Creative Commons BY-NC-SA
    More information at ocw.mit.edu/terms
    More courses at ocw.mit.edu

КОМЕНТАРІ • 194

  • @StaffordGreen
    @StaffordGreen 7 років тому +156

    I appreciate these lectures being online.

  • @mrsulaman9901
    @mrsulaman9901 5 місяців тому +7

    I would like to compliment the camera man for his fine work. Also whoever is responsible for recording the sound did a great job. It's so important to be able to hear and see these lectures clearly. My thanks also to MIT for making this content available.

  • @stephenanastasi748
    @stephenanastasi748 3 роки тому +21

    I love this form of explanation. It is so complete. And I love that the facts and reasoning are explained in a human-centric simple form, where so many others throw a bunch of fact at the screen. Thank you! I will use this information in the most powerful way. I have tried to wrap my head around the supposedly simple idea of linearity for a long time. Somehow this shifted me over my preconceptions.

  • @mjackstewart
    @mjackstewart 3 роки тому +21

    There are some people who are perfect communicators of complex subjects.
    My calculus teacher, Martha Kasting, was one such person. She would smile the entire time as she described Green’s Theorem, or she would say, “Isn’t that a pretty equation?”
    Dr. Zwiebach is another.

  • @SanDiego_J
    @SanDiego_J 6 років тому +35

    Thank you MIT OCW and all MIT staff!

  • @chrisl3987
    @chrisl3987 4 роки тому +53

    As someone who works in (classical) fluid mechanics, I can confirm that it's very very nonlinear.

    • @chuuuu1131
      @chuuuu1131 4 роки тому

      Can you give an example?

    • @frun
      @frun 4 роки тому

      Does it look like electromagnetism? I think he meant classical mechanics.

    • @LifeForAiur
      @LifeForAiur 4 роки тому +3

      @@chuuuu1131 Not him, but in fluid mechanics, to quantify the deformation of a fluid particle in a continuous medium you need something called a stress tensor, which is a 3 by 3 matrix describing the direction of the stress imposed and on which "face" of the fluid particle it is acting on. Check out the Navier Stokes Equation expanded out.

    • @MrMathjordan
      @MrMathjordan 4 роки тому

      Agreed.

    • @user-fb4zo8wd5n
      @user-fb4zo8wd5n 3 роки тому +1

      True. Many applied mathematicians research in the field of fluid mechanics.

  • @cidorodrigues6087
    @cidorodrigues6087 4 роки тому +9

    I'm Sido Rodrigues Brazil I really like Quantum Physics Classes. Very important to know quantum physics. Teach everything the universe knows and you gain self-knowledge about everything. Great series of really useful lectures on quantum mechanics. I am also very grateful to MIT OpenCourseWare and Barton Zwiebach... etc...

  • @axis_8
    @axis_8 6 місяців тому +1

    I feel illuminated. A clear and concise lecture by a lecturer who comes across having an authentic passion for learning and understanding. Thank you 🙏

  • @homerodaniel_007
    @homerodaniel_007 Рік тому +4

    This is actually an excellent class. It worth's its length in Gold. Thank you very much

  • @anywallsocket
    @anywallsocket 2 роки тому +11

    First time I’ve ever heard the process of QM explained outright, every professor I’ve ever had on the subject just jumps right in and it’s hard to grip without foundational information.

  • @MikeDbean420
    @MikeDbean420 4 роки тому +10

    Thank you. Great teacher. Easy to follow.

    • @Anb-ng2ou
      @Anb-ng2ou 4 роки тому

      How is called this teacher pelase?

    • @ZapytajRedditPolska
      @ZapytajRedditPolska Рік тому

      @@Anb-ng2ou what are you doing here if you have problems with reading description?

    • @nichokind5233
      @nichokind5233 2 місяці тому

      @@Anb-ng2ou Dr. Barton Zwiebach

  • @mohammednour1534
    @mohammednour1534 6 років тому +1

    MUCH THANKS MIT

  • @yordygarciamalca3487
    @yordygarciamalca3487 4 роки тому +1

    Thank you so much!

  • @TheFenny
    @TheFenny 4 роки тому +25

    Nearly 200,000 views on the first video, and the second video only has a quarter of that? Shame so many people gave up already

    • @HighestRank
      @HighestRank 4 роки тому +2

      Brandon Smith maybe it was just a review which they needed, I myself got this only as a recommendation even though I’m not a subscriber to OCW, and wouldn’t have expected anyone who didn’t realize there is a second part because they weren’t told in the video to go looking for it or to recognize it if it had bit them in the nose.

    • @MegaFunkysoul
      @MegaFunkysoul 3 роки тому

      They were looking for pseudoscience

    • @abrarfaiyaz6503
      @abrarfaiyaz6503 3 роки тому

      Maybe they moved on to the ocw site.

  • @ramonasosna
    @ramonasosna 7 місяців тому

    Great teaching ❤

  • @java_Marcelo-xx5nw
    @java_Marcelo-xx5nw Місяць тому

    Thank you for share!

  • @khaledal-homam6482
    @khaledal-homam6482 4 роки тому +1

    You are great.

  • @fujiexia2515
    @fujiexia2515 3 роки тому +2

    Very excellent open course on QM, thanks MIT professor!

  • @beenishmuazzam
    @beenishmuazzam 4 роки тому +1

    Thanks

  • @karthigamanivannan7922
    @karthigamanivannan7922 3 роки тому +2

    thank you MIT AND ALL FACULTIES FOR PROVIDING INTERESTING LECTURES ON QUANTUM MECHANICS...

  • @abdulbaqui9499
    @abdulbaqui9499 3 роки тому

    Good lecture

  • @emersonfranzuaaldanagavarr231
    @emersonfranzuaaldanagavarr231 3 роки тому

    thank you

  • @prabudeva2547
    @prabudeva2547 4 місяці тому

    I'm from India.... great thank you mit gives the online courses...little tweak are arises...but most of the phenomenal are not predicted..which means my life time scenario is the one of the examples...some atoms are vibrated...but no losses. After some times the illusion are visible... 🤔

  • @nikhilgoyal7814
    @nikhilgoyal7814 4 роки тому +4

    This professor is amazing.. Though my stream is not linked with this subject but then also i have seen the whole video :)

  • @deepakkumarravi9217
    @deepakkumarravi9217 4 роки тому

    Thnx to mit n your staff to spread your valuable contribution in enhancing the concept in worldwide.. Respect n love to you all guys.....

  • @antoniolewis1016
    @antoniolewis1016 7 років тому +5

    @MITOCW Is this the same room where they did the old 2013 QM course, but renovated??

    • @mitocw
      @mitocw  7 років тому +10

      Good eyes! Yes, this is the same room where they did the 2013 version of the course. :)

  • @arushaacharyya6376
    @arushaacharyya6376 3 роки тому +2

    Where and how does the non-linearity get introduced in classical mechanics when quantum mechanics is all linear?

  • @retepredlef5212
    @retepredlef5212 Місяць тому

    Phantastic lecture!

    • @lepidoptera9337
      @lepidoptera9337 4 години тому

      Not really. I am beginning to wonder how this guy made professor at MIT. ;-)

  • @tarunpurohit6522
    @tarunpurohit6522 2 роки тому

    What a great intro

  • @geoffrygifari3377
    @geoffrygifari3377 2 роки тому +1

    If schrodinger's equation is linear in any case by default, is it not possible to observe nonlinear behavior in quantum system?

  • @i.m.Q.2
    @i.m.Q.2 Рік тому

    Thanks for confirming something I've been wonderimg about for some time now! You've got no idea what you just helped me out with. 👍😁

  • @user-fc3wx7bp4i
    @user-fc3wx7bp4i 5 років тому

    Good

  • @123string4
    @123string4 2 роки тому +2

    Why is the Schrodinger equation linear when the Hamiltonian depends on V(x), and earlier he said that V(x) can be arbitrary? The quantum harmonic oscillator is a perfect example of a nonlinear potential and as far as I know you need special techniques like Hermite polynomials to solve it.

    • @commonlistener87
      @commonlistener87 2 дні тому

      Linearity depends on the dynamical variable you’re solving for.
      In the example the lecturer presents for Newton’s equations, you are solving a second-order differential equation for the “variable” x (which is a function of time). The equation is nonlinear *with respect to x* whenever V’(x) is nonlinear with respect to x.
      In the case of Schrödinger’s equation, by contrast, you are solving a partial differential equation for psi (the wavefunction), not for x. You’re right that the Hamiltonian has a potential term V that depends on x (often nonlinearly), but V doesn’t depend on psi, and it’s psi that you’re solving for.

  • @geoffrygifari3377
    @geoffrygifari3377 2 роки тому +1

    hmmm i guess quantum mechanics is linear because the potential operator is applied ("multiplied") to the wavefunction, instead of the potential being an arbitrary function *of* the wavefunction, as in classical mechanics

  • @FreezerBurn.
    @FreezerBurn. 4 роки тому +9

    I think I am going to treat myself to hotdogs in my mac and cheese tonight.

    • @spencersabet8601
      @spencersabet8601 3 роки тому +1

      I respect that. Have fun

    • @ProgressiveTeen
      @ProgressiveTeen 2 роки тому

      How evil. Torturing animals for your tongue's evil delight.

    • @FreezerBurn.
      @FreezerBurn. 2 роки тому

      @@ProgressiveTeen ... kind Sir, sadly you are mistaken. Mac and Cheese is not an animal.

  • @Mystic0Dreamer
    @Mystic0Dreamer 3 роки тому

    @ 9:30 he talks about Schrodinger not knowing what the wave function is. How did Schrodinger come up with this equation in the first place. Professor Zwiebach doesn't offer an explanation of how Schrodinger came up with this equation. But Schrodinger must have had reasons.

  • @farahsalam1887
    @farahsalam1887 4 роки тому +3

    thanks sir for this amazing lectures
    but can any one give me the notes of the course please?

    • @mitocw
      @mitocw  4 роки тому +13

      The lecture notes are available on MIT OpenCourseWare at: ttp://ocw.mit.edu/8-04S16. Best wishes on your studies!

    • @abubakarejaz5539
      @abubakarejaz5539 3 роки тому

      Hey U a physics student too?

  • @gustavodeoliveira702
    @gustavodeoliveira702 2 роки тому

    In what extent can someone assert that classical mechanics or quantum mechanics is linear or not? Is in regarding to the description of fundamental interactions and not merely idealized models?
    Because a classical harmonic oscillator is a linear system inside classical mechanics and systems that respect Ginzburg-Landau equation are non linear examples in quantum mechanics. Why those aren't consider counter-examples to the thesis defended in the video?

  • @debanujchatterjee2768
    @debanujchatterjee2768 4 роки тому

    The Hamiltonian operator may contain a potential term. So how is the Hamiltonian always linear?

  • @rezokobaidze8501
    @rezokobaidze8501 3 роки тому +1

    hamiltonian has potential energy inside and why it is linear?

    • @AbhishekSachans
      @AbhishekSachans 2 роки тому +1

      Because potential energy is not a function of the 'wave function'- the independent variable in schrodinger's wave equation (or its derivatives); unlike in Newton's equation of motion in which P.E. WAS a function the independent variable(s) e.g. x in general.

  • @FredBakker
    @FredBakker 4 роки тому +2

    Mister Zwiebag, you absolutely rock! Explaining complex stuff simple is a trait of true genius!

  • @sagarwadhwani1610
    @sagarwadhwani1610 4 роки тому

    Can't we use linear qm to solve 3 body problem

  • @nayemabdullah7627
    @nayemabdullah7627 3 роки тому

    I am from Bangladesh
    Love Quantum mechanic

  • @cedriccappelle2036
    @cedriccappelle2036 4 роки тому +1

    For some reason I keep watching this guy even though I don't understand ßhit of this

  • @pmcate2
    @pmcate2 3 роки тому

    Aren't maxwell's equations only linear for some materials?

  • @kaushaljain5999
    @kaushaljain5999 4 роки тому +1

    5:13 how is Hamiltonian operator linear? Since it also contains potential energy term which need not to be linear.

    • @zacharythatcher7328
      @zacharythatcher7328 4 роки тому +7

      Kaushal Jain the potential in the Hamiltonian can be thought of as a set of values that span relevant space (a normal line or surface over space) that the wave function will be multiplied by at every single one of those points individually. So the wave equation (the input) will be transformed in essentially a multiplication style operation. Multiplication is linear, and so is the “potential operator”. If the potential was somehow squaring or logging the wave equation, that would be nonlinear, but that is impossible. The potential isn’t that weird. It just multiplies the wave equation by its own predetermined values, which you could do before or after multiplying by a constant and get the same result.

    • @aryasingh8173
      @aryasingh8173 3 роки тому

      @@zacharythatcher7328 wow

  • @pranjalsharma3370
    @pranjalsharma3370 3 роки тому

    Amazing👍
    Can anyone say whether these are graduation or postgraduation classes? Or anything else?

  • @nsudhir_here
    @nsudhir_here 4 роки тому +1

    Can someone explain what is potential V of x? I'm noob in quantum physics. Does it mean a kind of potential which is providing force?

    • @bencegabor9228
      @bencegabor9228 3 роки тому +2

      Potential V(x) is a classical quantity, whose negative derivative is force. For example: en.wikipedia.org/wiki/Gravitational_potential or en.wikipedia.org/wiki/Electric_potential#Electric_potential_due_to_a_point_charge

    • @nsudhir_here
      @nsudhir_here 3 роки тому +2

      @@bencegabor9228 thank you sir

  • @eternapesadilla2355
    @eternapesadilla2355 4 роки тому

    Arent you the dean of the university of architecture in copenhagen?

  • @AlexBlade27
    @AlexBlade27 Рік тому +1

    I have a question, isn't Hamiltonian operator also a non linear operator, because it also contains Potential term which may be quadratic or cubic depending on the condition. Thus, isn't then Quantum mechanics also, non linear in nature. Please, explain if I am wrong.

    • @sylvenara
      @sylvenara Рік тому +3

      While the potential energy term in the Hamiltonian operator of quantum mechanics can be nonlinear, the dynamics of quantum mechanics are fundamentally described by a linear equation, the Schrödinger equation. Therefore, quantum mechanics is considered a linear theory.

    • @AlexBlade27
      @AlexBlade27 Рік тому +1

      @@sylvenara ok understood. Thanks for the help😊

  • @gamalf123
    @gamalf123 6 років тому +4

    Why can we assume the Hamiltonian is a linear operator? Isn't it another measure of potential, and theoretically could be made some non-linear result?

    • @LusidDreaming
      @LusidDreaming 4 роки тому +2

      I don't know enough about the Hamiltonian to directly answer this, but in general an operator is linear if it satisfies the following two conditions (O is an operator):
      1.) O(f + g) = O(f) + O(g)
      2.) O(c*f) = c*O(f)

    • @frun
      @frun 4 роки тому

      @@LusidDreaming yes. I think that's the definition.

    • @fredrikj8491
      @fredrikj8491 4 роки тому +5

      The difference is previously your solution was in terms of x(t) and the potential depends explicitly on x. Now your solution is in terms of the wave function, of which the potential is not a function. The Hamiltonian is a linear operator on the space where the wave function lives. The potential is not a function of your wave function.

    • @ericsmith1801
      @ericsmith1801 4 роки тому +1

      @@LusidDreaming So there cannot be time compression to satisfy linearity... experiments seem to suggest that in addition to spatial nonlocality there is temporal nonlocality involved in entanglement. I doubt that changing the inertial frame of reference will get rid of such nonlinearity.

  • @forheuristiclifeksh7836
    @forheuristiclifeksh7836 5 місяців тому

    Dynamic quantum variable, wave function

  • @hadlevick
    @hadlevick 5 років тому

    Can you catch the sensation of simultaneity, can you do 1+1...

  • @infinity-and-regards
    @infinity-and-regards 4 роки тому +2

    9:35 How did Schrodinger come up with his equation before there was any physical interpretation for the wave function? What did he try to derive? What was his starting point?

    • @durgeshgaikwad741
      @durgeshgaikwad741 4 роки тому +3

      When de Broglie proposed the idea of matter waves, Schrödinger tried to find an equation which could describe these matter waves and hence came up with the famous Schrödinger equation

    • @lambda2693
      @lambda2693 2 роки тому

      it is quite easy. you just have to prove that what the classical operators become in qm. like p=-ihbar d/dx or E=ihbar del/del t

    • @infinity-and-regards
      @infinity-and-regards 2 роки тому

      @Lambda that doesn't sound easy at all, could you elaborate?

    • @lambda2693
      @lambda2693 2 роки тому

      @@infinity-and-regards look finding the operators is tough but the derivation of the equation is very easy if you know the operators. okay look i will derive it for you but i will assume the operators if you want the proof for why the operators are equal to what i am assuming you will have to look it up as the proof is very long.
      E=KINETIC ENERGY + POTENTIAL ENERGY
      KE= P^2/2M. PE=V(X,)
      LET US QUANTIZE THIS
      EΨ=P^2/2M Ψ +VΨ
      NOW EΨ=Ih/2π dΨ/dt. and p=-ih/2πd/dx
      Ih/2π dΨ/dt=(-ih/2πd/dx)^2/2m Ψ+VΨ
      Ih(ΒΑR)dΨ/dt=-h(BAR)^2/2m d^Ψ/dx^2+VΨ
      AND YOU HAVE DERIVED THE SE. YOU CAN DERIVE ITIN OTHER FORMS BUT THE PROCESS IS SAME. THE REAL CHALLENGE COMES IN PROVING THE ASSUMPTIONS AND YOU TO USE BRA'S AND KET'S FOR THAT. ALTHOUGH THE PROOFS ARE GIVEN IN SOME TEXTBOOKS BUT ARE VERY COMPLEX. EVEN GRIFFITHS DOES NOT GIVE THE PROOF

  • @kaushaljain5999
    @kaushaljain5999 4 роки тому

    9:22. Why is one wave function unable to explain both spin up and down state of e-?

  • @hadlevick
    @hadlevick 5 років тому

    Hamilton?

  • @SarojKumar-lt8qy
    @SarojKumar-lt8qy 6 років тому +2

    Sir can a wavefuntion determine the dynamics of a macrobody?????or it is just applicable in cases of microbodies

    • @farooq8897
      @farooq8897 6 років тому +2

      It can.. But Classical Mechanics is a good approximation and easy to use..

  • @ahmedafifkhan
    @ahmedafifkhan 4 роки тому

    Can anyone elaborate a bit from @2:20 to @2:33. What did he mean? Where did that graph came from?

    • @NoName-vq6cg
      @NoName-vq6cg 4 роки тому

      Graph of potential energy over time. (Potential energy meaning the work that force has to do. Force × distance) The derivative is the force acting on it at a specific time. Like if a ball is rolling down a hill, hes basically just saying that because there's mass, gravity would be pulling it down, and it loses potential energy as it gets closer to its destination and force is used. So the force is the negative of the derivative of potential energy.(someone correct me if I'm wrong)

  • @surendrakverma555
    @surendrakverma555 2 роки тому

    Excellent lecture Sir. Thanks 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

  • @kaushaljain5999
    @kaushaljain5999 4 роки тому

    4:39 Is time is dynamical variable? what is definition of dynamical variable?

    • @friendlyone2706
      @friendlyone2706 3 роки тому

      @@damariscalleros4631 but time changes, sometimes

  • @kostasargiris748
    @kostasargiris748 Рік тому

    Very good teacher!! I have a question : 3:34 Why x squared is not a linear function?

    • @mateusmarinho72
      @mateusmarinho72 Рік тому +2

      f(x) = x²
      f(a + b) = a² + 2ab + b²
      f (a) + f (b) = a² + b²
      So f(a+b) is not equal to f(a) + f(b), therefore it's not additive. So it's not linear.

    • @kostasargiris748
      @kostasargiris748 Рік тому +1

      @@mateusmarinho72 yes, okey, thank you very much!

    • @urpisarmiento5385
      @urpisarmiento5385 2 місяці тому

      ​@@mateusmarinho72muchas gracias, entendí la explicación.

  • @forheuristiclifeksh7836
    @forheuristiclifeksh7836 5 місяців тому

    3:49

  • @ZEROCARTOO
    @ZEROCARTOO 2 роки тому

    I didnt know i had spedup the videos (to 1.5x) until I read the comments. Oh man, he speaks too slow to the point that his class could be boring. Thankfully it is an online course where you can set the speed, and also for some people that are not familiar with the language and might want to slow it down ;) Greetings from Peru

  • @hadlevick
    @hadlevick 5 років тому

    (Reproduction/Feed/Reasoning) decanted selfover hexagon...

  • @kaushaljain5999
    @kaushaljain5999 4 роки тому

    Explain 0:56 to 1:05 by example

  • @kaushaljain5999
    @kaushaljain5999 4 роки тому

    explain 0:53 to 1:07 by example

  • @ryogakaydc7017
    @ryogakaydc7017 4 роки тому +1

    Ojala algun dia regrese Barton a la Fiee para para una clase de estado solido 🙌

  • @brandomiranda6703
    @brandomiranda6703 3 роки тому

    Why is 2nd law for newton not linear wrt Potential? Partial derivatives are linear and so are the normal derivatives...

    • @AbhishekSachans
      @AbhishekSachans 2 роки тому

      Because, say for one dimension, x is an independent variable of which potential energy is generally a function so that gives you a non-linear differential equation. That's it!

  • @mattmurdock2259
    @mattmurdock2259 4 роки тому +3

    free knowledge hooray

    • @Adam-cn5ib
      @Adam-cn5ib 4 роки тому

      why pay when you can not pay? right?

  • @timmy18135
    @timmy18135 4 роки тому +1

    It is linear iff a linear relationship exists

  • @RonPaulOrDie
    @RonPaulOrDie 5 років тому

    Whatever it is it's non-linear, and it is the easier explanation. Maybe he says this later Im 30 seconds in.

  • @LRahmanGrandUnifiedModelLRahma
    @LRahmanGrandUnifiedModelLRahma 11 місяців тому

    L. Rahman Grand Unified Model

  • @riturajanand7133
    @riturajanand7133 4 роки тому

    sir how force is equal to the derivative of potential...Sir as I know the force is equal to -du/dx (rate of change of potential ENERGY W.R.T X) not potential.....

    • @mysteriouspandey3450
      @mysteriouspandey3450 4 роки тому

      Pehle basics clear karo Bhai baadme quantum ki lectures samjhoge

    • @riturajanand7133
      @riturajanand7133 4 роки тому

      @@mysteriouspandey3450 Thanks sir for your advice, please answer to bta dete doubt ka

  • @CharlesSmith-vk8co
    @CharlesSmith-vk8co 4 роки тому +1

    You can aquire all thie knowledge for free.You may even sit down in the lecture und visit all classes and pass the exam.But if you want that piece of paper which says that you did all of that you have to pay thousands of dollars.

  • @hadlevick
    @hadlevick 5 років тому

    The size of simultaneity...

  • @leonidasloquendero
    @leonidasloquendero 2 роки тому +1

    Orgullo peruano

  • @hassanbaqer9280
    @hassanbaqer9280 6 років тому +1

    👍👍👍👍👍👍👌👌👌👌

  • @suteguma0
    @suteguma0 4 роки тому +1

    Can anyone help me understand what the T-like symbol really means in the derivative equation?

  • @timetostudy6443
    @timetostudy6443 3 роки тому

    Yes professor, I found the tutorial irrelevant since I’m no where near being a physician.

  • @wassupari2294
    @wassupari2294 Місяць тому +4

    benedict cumberbatch in disguise

  • @chandrusekar9575
    @chandrusekar9575 4 роки тому

    Hi

  • @ejoe7938
    @ejoe7938 6 років тому

    Where is the teacher from?

    • @carloveable1
      @carloveable1 4 роки тому +3

      He studied at my University in Peru (well known in Peru as UNI) at the same Faculty than me and he finished (Electrical Engineer career) I believe in 1977, then he came to America to follow Master and PhD. degrees.

  • @p0lv0jack_
    @p0lv0jack_ 2 роки тому

    👁️

  • @sharptongue2972
    @sharptongue2972 4 роки тому

    Han Solo is now a physicist? Damn...

  • @achintyajai2934
    @achintyajai2934 2 роки тому

    alright he reminds me of dr. peyam

  • @SarojKumar-lt8qy
    @SarojKumar-lt8qy 6 років тому

    Sir . I wanted to ask .............we know that a theory has numerous equations in it working all together to state one point .Now if we say that a theory is linear then does it state all the equations of that theory to be linear or there is a possibility for only a few to be linear ???????

    • @friendlyone2706
      @friendlyone2706 3 роки тому

      The moment a non linear factor is introduced, everything affected by that nonlinear factor becomes nonlinear.

  • @abhijeetbhattacharjee6185
    @abhijeetbhattacharjee6185 17 днів тому

    3:31 What is V(x) ?

  • @MS_PrithwirajMaity
    @MS_PrithwirajMaity 2 роки тому

    CLASSICAL MECHANICS IS NONLINEAR AND QUANTUM MECHANICS IS LINEAR THEN HOW CLASSICAL MECHANICS IS APPROXIMATON OF QUANTUM MECHANICS.

  • @dougiev9287
    @dougiev9287 4 роки тому

    Newton's is non-linear because potential could be non-linear function; ok! But Maxwell's is linear...couldn't potentials A and V be non-linear?

    • @HighestRank
      @HighestRank 4 роки тому

      dougie v yes, Aa is easy to see, but Vv will always be made using straight lines.

  • @czitels1856
    @czitels1856 2 роки тому

    Interesting thing. First video has 2x more views than second :D

  • @posthocprior
    @posthocprior Рік тому

    Somewhat vague definition of the difference between linear and non linear.

  • @schrodingerscat3912
    @schrodingerscat3912 4 роки тому

    (steepled hands)

  • @uTubeNoITube
    @uTubeNoITube 2 роки тому

    You don't need any of this. Just go to Vegas on weekends and play black jack.

    • @Greato_
      @Greato_ 10 місяців тому

      Wtf

  • @mohammadaminmasoomi3597
    @mohammadaminmasoomi3597 2 роки тому

    I'm from Iran.I love quantum physics and the other parts of physics and absolutely I go to the MIT university.

  • @diegofernando4277
    @diegofernando4277 5 років тому +3

    I don't get it, he says that classical mechanics ain't linear because of the potential energy, but the Hamiltonian it's the sum of the kinetic and potential energy, so, how can the classical mechanics be non linear, but the wave function that also depends of V(x, t) be linear?

    • @ogoshi
      @ogoshi 5 років тому

      Yeah, I'm also a little confused by this argument

    • @andrewstallard6927
      @andrewstallard6927 5 років тому +2

      Notice in the classical equation, m x'''(t)=-V(x'(t)), the potential is a function of the derivative of the position. While the derivative itself is linear, we don't know what the unknown potential function "V" is so we can not say with certainty that V(x'(k*t))=k*V(x'(t)). By contrast, in the Schrodinger equation the potential V is multiplied by the wavefunction psi, so V*k*psi=k*V*psi

    • @UnknownBeast41
      @UnknownBeast41 5 років тому

      The potential function is arbitrary, in most scenarios we approximate it to be harmonic (proportional to x^2) but it can be generally non linear. Alternatively H-hat is the Hamiltonian operator which is basically a constant time the 2nd derivative with respect to position i.e its linear. Its not the Hamiltonian itself, its an operator named after the Hamiltonian.

    • @mike4ty4
      @mike4ty4 4 роки тому

      The quantum Hamiltonian operator acts on the state variable differently than the potential/kinetic energy (classical Hamiltonian) does in Newtonian mechanics. In particular, "x" in the potential energy function is just a parameter, not the present particle state being plugged into the function like it is in the Newtonian case with Newton's second law or Hamilton's equations, because in quantum mechanics position, momentum, etc. are not actually numbers, but "fuzzy" quantities described by probability distributions (which corresponds to reduced information, as per Shannon), and they are all wrapped up in the linear state vector, |psi>. That state vector is not a real number, but (effectively) an infinite number of them, and hence could not be inserted into the potential energy function anyways, which is expecting only one real number as input.
      Instead, the potential energy function _becomes_ an operator on the state vector by first considering it in the form of the positional wave function psi_x(x), which is a "basis expansion" (effectively the same thing as vector components of ordinary vectors, but with infinitely many components) and then you multiply this wave function by the potential energy function to get another wave function (i.e. form psi'_x(x) = U(x) psi_x(x)), which then represents, by going backwards through that expansion, the resulting new state vector. Since multiplication is distributive, hence linear, you get a linear action of this operator.

  • @atmonotes
    @atmonotes 2 роки тому

    for a second there i thought he was Harrison Ford

  • @ahmedessam1426
    @ahmedessam1426 6 років тому +7

    this continuous montages and cuts through the video made my upset because i want to know everything he says like the real lecture :(

  • @ryanyi8900
    @ryanyi8900 5 років тому +1

    I have some doubt about the view that professor mentioned in the lecture about the relation between the many body equation solving difficulty and the linearity of equation.And I think the linearity of shrodinger equation provide us a possible way to solve the superposition problem, which is a one body problem! So, I do not agree the view that the nonlinearity of Newton mechanic equation make three body problem hard to solve.I have not tried to solve many body problem by shrodinger equation or newton mechanic equation, so my point might be wrong.I hope somebody could help me to figure this out.Thank you:)!

  • @justinji431
    @justinji431 4 роки тому

    2:14 FUNNY

  • @smartscience5305
    @smartscience5305 3 роки тому +2

    Wow , great lesson Sir. I am 12 years old and I am learning quantum gravity,string theory , Electromagnetism, thermodynamics and other lessons . but your lesson was great also the another lesson of relativity

    • @lamaquinadelainformacion826
      @lamaquinadelainformacion826 Рік тому +1

      At your age I was learning basic astronomy, you know where I ended up, studying geological engineering, I'm in my first cycle, I like physics although it's a bit difficult to understand, but what I don't understand much is chemistry, I'm from Peru.