What is a Constellation Diagram?

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  • Опубліковано 4 жов 2024
  • Explains the Constellation Diagram in Digital Communications and how it relates to real transmitted signals.
    Note that the "average power" term at the bottom is actually the average energy (it would be the average power if I'd included at 1/T term). It's just a scaling of T between the two, so sometimes the final equation for the measured signal y_k is written with P's (Power) and sometimes with E's (Energy). Depending on which is put there, the variance of the noise term n_k is either N_0 (for the Power version) or N_0W (for the energy version). This video has more details: "What are SNR and Eb/No?" • What are SNR and Eb/No?
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КОМЕНТАРІ • 99

  • @GinMichelangelo
    @GinMichelangelo Рік тому +3

    For a non-engineer doing research about 5G and telecom, these videos have been a god-sent. Thank you so very much.

    • @iain_explains
      @iain_explains  Рік тому

      That's great to hear. I'm so glad you've found the videos to be helpful.

  • @MaxeEricsson
    @MaxeEricsson Рік тому +2

    I am a RF Radio System Engineer in Ericsson. I like your radios and thanks for your sharing !!!!! Great explanation for every detailed sub aspects of the whole communication system!

    • @iain_explains
      @iain_explains  Рік тому

      Thanks for your nice comment. I'm glad you like the level of detail I put into the videos.

  • @asssheeesh2
    @asssheeesh2 3 роки тому +46

    UA-cam algorithm is truly messed up. So much crap just floats on top with hundreds of thousands of views and golden channels like yours become hard to find. But I am so glad that i finally found it. I hope more people subscribe to you. BTW great video and explained really clearly,

    • @iain_explains
      @iain_explains  3 роки тому +4

      Thanks for your comment. I'm glad you like the videos.

    • @n....8666
      @n....8666 5 місяців тому

      Cant agree more .

  • @Soho9111
    @Soho9111 2 роки тому +3

    You make the hard stuff that blows our mind off as simple as drinking water
    Thumbs up as usual 👍🏼🫡

    • @iain_explains
      @iain_explains  2 роки тому +1

      That's great to hear. Glad you like the explanations.

  • @beepbeep8374
    @beepbeep8374 3 роки тому +5

    Thank you, easy and concise, some things I just can’t understand from the textbook

    • @iain_explains
      @iain_explains  3 роки тому +1

      Glad you found it helpful.

    • @TheMekkyfly02
      @TheMekkyfly02 3 роки тому

      @@iain_explains 00he 00years were 0in to 00⁰000

  • @stevekim6923
    @stevekim6923 2 роки тому +1

    Your video made me so clear to understand how QAM works! Thank you very much!!!

    • @iain_explains
      @iain_explains  2 роки тому

      That's great. I'm glad you found the video helpful.

  • @exaltant2464
    @exaltant2464 3 роки тому +2

    Great explanation but if you make all the topics and if you order the lectures in a playlist according to any standard textbook(proakis or haykin) it will be really helpful.

    • @iain_explains
      @iain_explains  3 роки тому +5

      It sounds like you haven't discovered my web page yet. iaincollings.com

  • @zewei98
    @zewei98 3 роки тому

    Very clear explanation, thank you so much!!!

  • @tank_tales
    @tank_tales Рік тому

    Hungrily waiting for your videos on binary phase shift keying, code division multiple access cdma, binary offset carrier wave modulation

    • @iain_explains
      @iain_explains  Рік тому +1

      I've got this video on CDMA: "How does DS CDMA Work?" ua-cam.com/video/U_uOrrLBKz4/v-deo.html plus others comparing the standards, like this one: "Mobile Standards Evolution: FDMA, TDMA, CDMA, OFDMA" ua-cam.com/video/bm53RpK-S2k/v-deo.html Have you seen my webpage? I has all the videos listed in categories. iaincollings.com

  • @ilyavladimirov152
    @ilyavladimirov152 3 роки тому

    Thanks! You are making a good video. And good explain and make complex things simple, accessible and understandable. It would be nice if there was a video about EVM and MER. And about the influence of various factors on the EVM (for example phase noise)

    • @iain_explains
      @iain_explains  3 роки тому +2

      Thank s, I'm glad you like the videos. And thanks for the topic suggestions, I've added them to my "to do" list.

  • @puffio3773
    @puffio3773 3 роки тому +1

    thank u sir

  • @udutiy
    @udutiy 6 місяців тому

    Great job!

    • @iain_explains
      @iain_explains  6 місяців тому

      Thanks. I'm glad you liked the video.

  • @mehedimanon62
    @mehedimanon62 Рік тому

    very helpful sir. Thank you.

  • @Nadine23000
    @Nadine23000 Рік тому

    Thank you so much mister, easy and clear 🤍🤍👏

    • @iain_explains
      @iain_explains  Рік тому

      You are very welcome. I'm glad you liked it.

  • @proton7113
    @proton7113 6 днів тому

    Thank you for this video. What is the difference between a constellation diagram and an IQ plot? Best

    • @iain_explains
      @iain_explains  6 днів тому +1

      The Constellation Diagram is plotted on an IQ plot. The output of the demodulator will be a trace on the IQ plot. If you only sample that trace at the symbol times, then you get the output constellation diagram.

  • @analysislearning9179
    @analysislearning9179 3 роки тому

    Best Explanation Since my graduation.

    • @iain_explains
      @iain_explains  3 роки тому

      Thanks.

    • @analysislearning9179
      @analysislearning9179 3 роки тому

      @@iain_explains
      Will you be doing any video on Maximum Likelihood Estimation?

    • @iain_explains
      @iain_explains  3 роки тому +1

      Have you seen this video on my channel: "What are Maximum Likelihood (ML) and Maximum a posteriori (MAP)?" ua-cam.com/video/9Ahdh_8xAEI/v-deo.html

    • @analysislearning9179
      @analysislearning9179 3 роки тому +1

      @@iain_explains
      Yes I did. I bookmarked it and liked it too. Thankyou for great work and remarkable presentation style and insights.

  • @bijoyroychowdhuryprinon6768
    @bijoyroychowdhuryprinon6768 2 роки тому

    great video..appreciated..

  • @maazawan7629
    @maazawan7629 Рік тому

    Greetings sir!
    What a wonderful explanation!
    Just curious as to why the normalization factor is square root of average power of all symbols and not just the average power?
    Looking forward

    • @iain_explains
      @iain_explains  Рік тому +1

      Power = (voltage)^2 / resistance , and the constellation diagram is essentially showing voltage (normalised for a unit resistor).

  • @tuongnguyen9391
    @tuongnguyen9391 3 роки тому

    Thank you !

  • @ΚΩΝΣΤΑΝΤΙΝΟΣΒΛΥΣΝΑΚΗΣ

    Just a correction (If i remeber it correctly!!!). It is φ not Θ since it is phase which in greek is φάση.

    • @iain_explains
      @iain_explains  3 роки тому +2

      No, not true. I could have used any symbol I liked. It didn't even need to be a greek letter. I could have made up my own symbol. It is just a label. In any case I think it is better to focus on the content and understanding. That's much more important.

  • @longpham4205
    @longpham4205 2 роки тому

    Thank you sir! I was reading that book of Goldsmith and felt like it was written in alien's language. You save me!

    • @iain_explains
      @iain_explains  2 роки тому

      I'm glad the video helped. Have you seen my webpage with a full categorised listing of all the topics? iaincollings.com

  • @bobbaberson3654
    @bobbaberson3654 2 роки тому

    I understand why @8:45 the integration is the same for all I but the amplitude is not so clear. For QAM vs 16 QAM would be: (18+18+18+18)=72 vs 4x(2+10+10+18)/16=10. I assumed the amp for QAM is (sqr (3^2+3^2)).

    • @bobbaberson3654
      @bobbaberson3654 2 роки тому

      @Iain Explains Signals, Systems, and Digital Comms it would be great if you take a look at this question.

  • @성민욱-y6c
    @성민욱-y6c 3 місяці тому

    Thank you for explaining!
    I have a question in 10:30. My english skill is not good so i don't understand the 'h' and 'root p' in equation.
    Could you tell me more detail about that..?

    • @iain_explains
      @iain_explains  3 місяці тому

      The 'h' is the channel gain (which will be a complex number with magnitude between 0 and 1), and the "root p" is the square root of the transmit power.

  • @arafathabib4020
    @arafathabib4020 3 роки тому

    Thank youuuu sooo much professor. Love you.

  • @amdPeek
    @amdPeek 2 роки тому

    damn finally a useful video, thanks !

    • @iain_explains
      @iain_explains  2 роки тому

      Glad you found it helpful. If you're looking for other useful videos, you might like the others on my channel. You can find a categorised list here: iaincollings.com

  • @vishalmishra7568
    @vishalmishra7568 3 роки тому +1

    Hello Sir, Please make a video on OQPSK and MSK !!

    • @iain_explains
      @iain_explains  3 роки тому +1

      Thanks for the suggestion, I've added them to my "to do" list.

  • @sumit1412
    @sumit1412 Рік тому

    Thank You Iain, for making learning easier :)
    Is this factor 'sqrt(p)' that you have used to normalize the X_k, is the average power of all possible symbols?
    What is it mathematically?

    • @iain_explains
      @iain_explains  Рік тому

      Yes, p is the average power. To calculate it, you simply add up the powers of all the symbols and divide by the number of symbols. In the 16-QAM example shown, it is (1^2 + 2*(3^2+1^2)+(3^2+3^2))/4 ... you only need to work out the powers of the 4 symbols in the top right quadrant and divide by 4, since the constellation is symmetric ... and I've just used Pythagoras to calculate the powers of each constellation point.

  • @alexsidorkin4871
    @alexsidorkin4871 10 місяців тому

    Good day. I have a remark related to "terminology". Why do you speak about mean power of the costellation when you write the integral. A^2*T = E. It should be mean energy, isn't it?

    • @iain_explains
      @iain_explains  10 місяців тому

      Power and Energy are related by a constant, T (the time duration of the symbol), so it's just a simple scaling between the two.

    • @alexsidorkin4871
      @alexsidorkin4871 10 місяців тому

      For sure. I think wordplay happens because transmitting and receiving constellations should be considered separately and may even have different measured units. What do you think about it?

  • @aarzoosingh8316
    @aarzoosingh8316 2 роки тому

    sir @ 7:04 whether it would be energy as we are transmitting the signal for only Tb duration and signal which we are sending is energy signal i think ??
    anyhow a great video sir now i can visualize the waveforms thanks for this

    • @iain_explains
      @iain_explains  2 роки тому

      Sorry, I'm not sure what you mean by "energy signal". But in any case, I'm glad you found the video helpful.

  • @tulsEE87
    @tulsEE87 Рік тому

    Sir Thank you for sharing the knowledge. I am from electrical background and I am now exploring digital communication. Can you please explain is it possible to plot constellation diagram for passband communication with out using filters as figure 6.8, page 359 ,fourth edition of Simon Haykin shows that we don't need filter to extract data?

    • @iain_explains
      @iain_explains  Рік тому

      I don't have the book handy, but I'm guessing you're referring to a correlation receiver with a mixer and a sampler. That's just a different way to implement the matched filter.

    • @tulsEE87
      @tulsEE87 Рік тому +1

      Okay Thank you Sir.@@iain_explains

  • @mohitkulkarni2183
    @mohitkulkarni2183 2 роки тому

    so can we say The larger the SNR, the more constellation points can be used in a symbol ?

    • @iain_explains
      @iain_explains  2 роки тому +1

      Yes, assuming you're wanting to keep the same bit error rate.

  • @soumyaneogy9522
    @soumyaneogy9522 3 роки тому

    at 10:06 in your video you say "so this gives you a power of 1 " . [1] I did not understand this part . [2] how does that scaling of dividing by square root of average power is making the comparison across different constellation easy ?

    • @iain_explains
      @iain_explains  3 роки тому

      There is always a limit on the transmit power (due to either government regulations or simple battery limitations in the device). To choose which modulation format to use, we need to make sure they are compared under the same power constraints. It is not acceptable to add more constellation points at the outside of a constellation (ie. to use a higher modulation order, and thus send more data per symbol) without scaling back all the points so that the overall average power remains the same.

  • @CSTerminalTech
    @CSTerminalTech 2 роки тому

    The phase at 1:17 is 90 not 0 and at 1:23 it is 270 not 180 . Right?

    • @iain_explains
      @iain_explains  2 роки тому

      Sorry, but the video is correct. cos(0) = 1. Also cos(2pi f t) is the Real part of e^(j 2pi f t), and so it is along the horizontal axis (theta = 0).

  • @himanshukumarshekhar2711
    @himanshukumarshekhar2711 3 роки тому

    Sir, nice video, sir I have one doubt, constellation diagrams is used to demodulate the symbol?

    • @iain_explains
      @iain_explains  3 роки тому +2

      The constellation diagram is used to visualise all the symbols. It shows where the decision boundaries could be placed in a demodulator to decide which symbol was sent.

  • @hrachya_khachatryan
    @hrachya_khachatryan 2 роки тому +1

    Hi Iain, thanks for the nice video. One question: Are the carrier frequency fc and the symbol duration time T related to each other? Looking on the plot at 1:11 , I can see that fc equals to 2/T. So I guess in general we can pick fc as an integer multiple of 1/T. But is there any reason for doing so?

    • @iain_explains
      @iain_explains  2 роки тому +1

      In general yes, the maths all works best when we pick fc as an integer multiple of 1/T, but in practice it's not necessary. In passband communications, the carrier frequency is so much higher than the bandwidth, that the fractional extra part of the "final" wavelength in the symbol has negligible effect compared to all the other "whole" wavelengths in the symbol (if you know what I mean).

    • @hrachya_khachatryan
      @hrachya_khachatryan 2 роки тому +1

      @@iain_explains Thanks so much for the answer !

  • @strategy_TR
    @strategy_TR 8 місяців тому

    sir, can we plot a frequency variation signal's like MFSK using the constellation diagram?
    like making the x axis for 'a' frequency and the y axis for the '2a' frequency ...... and how can we find the absolute value for the vector in this case?

    • @iain_explains
      @iain_explains  8 місяців тому +1

      Yes, that's right. Each symbol (frequency) in FSK is orthogonal to the others, so each constellation point can be represented by a point on an orthogonal vector (in a multi-dimensional space). Then it's just the same as for any other constellation diagram (except in higher dimensions). The decision boundaries are still equidistant between each neighbouring pair of points.

    • @strategy_TR
      @strategy_TR 8 місяців тому +1

      @@iain_explains
      Ok, thank you.

  • @63maurizios
    @63maurizios 3 роки тому

    I am bit confused in the part where average power is defined (around time 8:00). If value is integrated over time would not be an average energy (at least dimensionally)?

    • @iain_explains
      @iain_explains  3 роки тому

      The term "average power" means "averaged over the different possible constellation points (transmission signals)" assuming that the data is equally likely 1's and 0's (ie. assuming that each constellation point is equally likely.)

    • @63maurizios
      @63maurizios 3 роки тому

      @@iain_explains thanks for the reply but my doubt is not about the fact that we are "averaging" but rather on the quantity we are averaging. I see we are integrating over given time (the period) the square of signal value; so it looks to me we are averaging an energy rather than power. Could you please clarify to me this point? Thanks

    • @iain_explains
      @iain_explains  3 роки тому

      Ah, sorry, I see now. Yes, I should have called it energy (sorry about that). It's just a scaling of T between the two, so sometimes the final equation is written with P's (Power) and sometimes with E's (Energy). Depending on which is put there, the variance of the noise term n_k is either N_0 (for the Power version) or N_0W (for the energy version). This video has more details: "What are SNR and Eb/No?" ua-cam.com/video/bNYvXr6tzXQ/v-deo.html

  • @demetriusdemarcusbartholom8063

    ECE 485, UofA.

  • @hemantsharma2416
    @hemantsharma2416 2 роки тому

    could you please tell me, how the pulse shaping will come into the picture with constellation?

    • @iain_explains
      @iain_explains  2 роки тому

      If you've seen my video on pulse shaping ("Pulse Shaping and Square Root Raised Cosine" ua-cam.com/video/Qe8NQx4ibE8/v-deo.html) then you'll know about pulse shaping of a single real-valued data sequence. Then this video on how to send complex baseband signals will show you how to extend to the complex-valued data sequence case: "How are Complex Baseband Digital Signals Transmitted?" ua-cam.com/video/0lkRJgnywkg/v-deo.html

  • @sagarrawat7203
    @sagarrawat7203 6 місяців тому

    I have doubt in constellation points. How it works?

    • @iain_explains
      @iain_explains  6 місяців тому

      See: "What is a Constellation Diagram?" ua-cam.com/video/kfJeL4LQ43s/v-deo.html

    • @sagarrawat7203
      @sagarrawat7203 6 місяців тому +1

      @@iain_explains ❤️ got it sir

  • @rishabhkumar1050
    @rishabhkumar1050 2 роки тому

    sir can you please tell me the difference between the average power and transmitted power i mean i am not able to figure out the difference , are they same?
    and secondly @10:07 what do you mean by unity power (Xk/sqrt(p'))= 1?

    • @iain_explains
      @iain_explains  2 роки тому +2

      "Transmitted power" is the power at the output of the transmit amplifier that is connected to the UTP/Coax cable (for wireline channels), or as it goes into the antenna (for wireless), or laser (for optical channels). Typically the "average" value is quoted. "Instantaneous power" goes up and down at the carrier frequency, since it is defined as being the square of the voltage. If you want to compare two different modulation formats, you need to make sure you are doing a fair comparison, and so you scale the constellations (ie. the actual transmit waveforms) so that they have the same average power. The clearest way is to scale them to unity (ie. so the power equals 1).

    • @rishabhkumar1050
      @rishabhkumar1050 2 роки тому +1

      @@iain_explains ok I got it now thankyou sir for looking into it

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    @BilâlOkur-b9f 26 днів тому

    Swaniawski Springs

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    @90k13xx 2 роки тому

    I’m in 5th learning Algebra :(

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    @SamSabrina-w3p 16 днів тому

    Dayne Stream

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    @Zachsnotboard Рік тому

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