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It is for me an appraciated fresh-up. Much better than Sudoko. Can you please problems with derivate and integral solve. Some lim. problema too. Thank you.
Factorize the sums of cubics in numerator and denominator. Then you get the solution almost immediately.
Factorize the cubics in numerator and denominaor and you get the solution almost immediately (without substitutions)
Beautifully systematic evaluation technique
Here is another alternative way to solve it, maybe little easier. Let a = (29³ + 15³)/(29³ + 14³). Add -1 (minus 1) to both sides. So that (a - 1) = [(29³ + 15³)/(29³ + 14³)] - 1 = [(29³ + 15³) - (29³ + 14³)]/ (29³ + 14³) = (15³ - 14³)/(29³ + 14³) = [(15-14)(15² + (15)(14) + 14²)] / [(29+14)(29² - 29.14 + 14²)] = (15² + (15)(14) + 14²) / (43 (29² - 29.14 + 14²)) = (225 +210 +196)/(43. (841 - 406 +196)) = 631/(44.631) = 1/43. Therefore a = 1 + (1/43) = 44/43
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Very nice. Thank you!
Good
Я гораздо быстрее умножил всё в столбик))
Can you explain it again using interpretive dance?
It is for me an appraciated fresh-up. Much better than Sudoko. Can you please problems with derivate and integral solve. Some lim. problema too. Thank you.
Nice I want them too
Would you do the easy way
1.6