S3 KTU 2019 Scheme QP Solution | EEE | CIRCUITS AND NETWORKS | EET 201 | Module 2 - DEC 2022

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  • Опубліковано 15 січ 2025

КОМЕНТАРІ • 6

  • @shaikahammedyaseen5907
    @shaikahammedyaseen5907 Рік тому +2

    35:50 5/3s+2.5 alle

  • @Lzzxcvbnm
    @Lzzxcvbnm Рік тому

    Mam, ithil initial state le 2 ( L × 1A) Laplace edkumbol 2/s aakullee?

    • @ONESCOACHING
      @ONESCOACHING  Рік тому +1

      When we convert inductor to S-domain the equivalent is written as
      L[SI(S)-I(0)]. so alreary laplace equivalent is taken initial condition will remain as 2 only not 2/s, because thats the inductor with initial condion in laplace domain.

  • @scariathomas1460
    @scariathomas1460 Рік тому

    Capacitor entha 0 aaye

    • @ONESCOACHING
      @ONESCOACHING  Рік тому

      switch was closed initially which means capacitor was short circuit. hence initial capacitor voltage is zero