I have been using transformerless power supplies since a long time for various purposes. I can suggest you some points if you don't mind: 1) always connect the live(phase) to the open end of the pf...then the output will not give shock...to remember either write L on the live side of the two pin plug,else use a 3 pin top(earth pin remains unused) where the L and N always remain fixed, 2) secure the entire unit in a plastic box/customised box made of mdf or pvc sheet 3) add an indicator for ac using a 100 K 1/4 W in series with a red LED 4) use 1 M 1/2 W as discharge resistor for pf and 22-56 K 1/4 W as discharge resistor for filter 5) use a 10-100 ohm 2 W resistor as fuse with phase of the ac line 6)since the output dc amperage is low limit the use of such supplies for low current requiring loads only 7)check regularly the electrolytic capacitor for any bulge or fluid leak. Thank you,best of luck for your forthcoming projects.👍
Nice that the mains input connections are protected with heatshrink, but the rest is just hanging in a VERY dangerous way! Plus, there is NO isolation from the mains which is even more lethal!!
You should post the formula for calculating the parts according to the power and voltage needed. Added: C = I / (U * 2 * Pi * f) -> C = I / ( U * 6.28 * f ) Example if you have 230V / 50Hz on your mains and a 10W / 3V LED ( P = U² * I -> I = 1.1 A ) C = 1.1 / ( 230 * 6.26 * 50 ) -> 15.231 µF for full brightness and that's a lot, I would not recommend such a simple power supply for such high power LEDs. If you are using 20mA LEDs instead you will get this: C = 0.2 / ( 230 * 6.26 * 50 ) -> 0.276 µF -> 276nF for full brightness and this is much easier to achieve, if you are using a lot of LEDs in serial you should do your math with the voltage drop over this LEDs. If you are using a high power LEDs with a 22nF condenser (like it was used in the video) you are only using a fraction of the power such a LEDs could deliver.
The hidden side is not in terms of good efficiency, but in the value of consumption energy , as this method leads you to consume all voltage energy, 220 volts, as if you dissipating it in air and even reducing and taking just from it, 5 or 10 volts, but you still factured by the summe of consumption of 220 volts in the bill, but on the opposite side. If you use the transformer using the magnetic induction method, you will consume only what you converted by transferring electrons with magnetic induction at 5 or 10 volts, and you will be charged and factured only this amount in the bill. Engineers in this field do not neglect this method, but in this field nothing is valid except the correct one that gives a good efficiency of All sides the safety and even economic sides of important consuption of energy and facturisation too . This is the probability that I concluded
This is good for destroying almost any device powered by it, then to risk being electrocuted and eventually even setting the house on fire. Congratulations,it is a multi-purpose circuit really.
Cảm ơn bạn! Nhưng bạn thật xấu xa khi không cảnh báo cho mọi người ! Mình bị giật điện vì ngỡ dòng dc không bị giật điện khi vô tình chạm vào. Cũng may tai qua nạn khỏi nên nghi ngờ và hỏi lại nếu không phải mua đồng hồ khác rồi. Xin hãy chia sẽ bằng tấm lòng bạn nhé! Chúc bạn gặp may mắn. Mong sao mọi người làm theo bạn không xảy ra chuyện gì đáng tiếc. Nhưng mình cũng vẫn cảm ơn bạn vì đã chia sẽ kiến thức này dù mình thoát chết trong gan tấc. Cám ơn bạn
What is dangerous? AC is converted to DC , supply dropped. Only thing is you should not touch anywhere in the circuit while given supply. That's all. Nothing is dangerous.
first off we see the output resistor is getting toastie , start with device to power , then using knowledge of current for output and cap and resistor for voltage , lower cap yields lower voltage with smaller caps with less capacity with higher resistance
Hello the difference between transformer and capacitive reactance is about the amperage so the capacitove reactance is limited in amperage you can use it to small comsuption of amper to charge a low device cosumption but if you use it to charge a devices with high value of amper it will not be enough and take lots time i think so you find the result by using the calculation . V = i ×R and i = V/R >>> V / 1÷ ( 2π fc)
إذا قمت بتركيب محول سيكون في البدأ ثم الذي يعمل بالحث المغناطيسي ثم تختار عدد دورات الملف الثانوي بما يناسب الفولطية التي تريدها وهذا ما يسمى الشوبر كما في الباور سوبلاي ولكن بما أنك تريد استعمال محول في البدأ حتى تخفض الفولطية ممكن كما في شواحن الهاتف كذلك تم تقوم بعدها بتوحيد التيار المتردد لتحويله الى تيار مستمر عبر أربع دايودات أو واحد الأمن هو أربعة دايودات مع إضافة بعض المكثفات للفلترة وجعله بدون نويز أي نقي ومفلتر وكذلك تنعيمه أما ما ذكرت سابقا عن الشوبر فهو قد يخرج أكثر من فولطية واحدة ويستعمل الدايود شوتكي وهذا بالنسبة للباور سوبلاي أما عن نموذج في الفيديو فهو مختلف فلا تستعمل المكثف في هذه الحالة لان هنا يستعمل حالة الممانعة السعوية وكأنها مقاومة كبيرة في التيار المتردد وليس المستمر أما دوره المكثف يختلف عن دوره في التيار المستمر فإذا استعملت المحول لاداعي أن تستعمل الممانعة السعوية أو المفاعلة السعوية
We use the resistance in parallele with capacitor to descharge the capacitors from the voltage stored inside we calculate xc = 1devided by 2πfc and if we add resistance that will be empedance (z) = racine of √R^2 + (1/2πfc )^2= ......ohm the f means fréquence and π= 3.14 and c = farad
Dangerous to life, you must isolate the mains voltage from low voltage. If the diode bridge short-circuits, there is mains voltage on the low voltage side.
It will not burn because of the Capacitive impedance with resistance (z) and this capacitor must support more than 400 hundred volts to make a impedance with resistance in the alternative current also must calculate the result of gathering resistance and farad together. With base (z)
You assemble the subject circuit in good manner but the values of all components you have not told neither you zoom that might be readable or color code.so this is useless
Because of when using a device or somthing to suplying dc voltage in out put it will be decreasing to the just 3 volt or less than what you expect 12 volt also by a few time it will be very hot and the component wil be damaged
انا لم استوعب بعد هذه الدائرة يجب ان اقوم بيعض الحسابات لأنه من غير الممكن ان يمرر المكثف كل ذالك التيار خصوصا انه صغير السعة 0.1 ميكرو لا ينتج عنه سوى 1.5 فولت اي تيار صغير
آسف .. انا قلت مكثف سعة 0.1 ميكرو وهو في الحقيقة 1 ميكرو يعني ينتج عنه تيار عالي وقد قمت بتجربة هذه الدارة على برنامج الساركت ويزارد ولم تنجح ولا يمكنه اشعال لاد بدون ان يحترق ....حتى ان جهد الخرج هو 100 فولت وهو عالي جدا .!!! ..ربما هو ينجح فقط مع مكثف 0.1 ميكرو لكن بدون وضع احمال كبيرة لأن التيار يكون صغير عكس مكثف 1 ميكرو . @@UltimateElectronics
Yes sir you can do this with proper make proper isolated cover otherwise you don't please if you have any knowledge Thank You for watching.have a great day.
Thank you so much आप कम पैसे में बनाना सिखाया ❤
Thank you 🙏
I have been using transformerless power supplies since a long time for various purposes. I can suggest you some points if you don't mind: 1) always connect the live(phase) to the open end of the pf...then the output will not give shock...to remember either write L on the live side of the two pin plug,else use a 3 pin top(earth pin remains unused) where the L and N always remain fixed, 2) secure the entire unit in a plastic box/customised box made of mdf or pvc sheet 3) add an indicator for ac using a 100 K 1/4 W in series with a red LED 4) use 1 M 1/2 W as discharge resistor for pf and 22-56 K 1/4 W as discharge resistor for filter 5) use a 10-100 ohm 2 W resistor as fuse with phase of the ac line 6)since the output dc amperage is low limit the use of such supplies for low current requiring loads only 7)check regularly the electrolytic capacitor for any bulge or fluid leak. Thank you,best of luck for your forthcoming projects.👍
You are right sir very good think
Nice that the mains input connections are protected with heatshrink, but the rest is just hanging in a VERY dangerous way! Plus, there is NO isolation from the mains which is even more lethal!!
Yes sir be carefull to make this one other wise it is very useful
How to discover hot water again !
The key is mylar capacitor , add and minus the AC And low volts at filter
A simple and workable scheme . Great. 🤝 👍
Thank you sir
@@UltimateElectronics 🤝🤝👍👍
अप्रतिम अजून काय म्हणु धन्यवाद
Thank you
You should post the formula for calculating the parts according to the power and voltage needed.
Added:
C = I / (U * 2 * Pi * f) -> C = I / ( U * 6.28 * f )
Example if you have 230V / 50Hz on your mains and a 10W / 3V LED ( P = U² * I -> I = 1.1 A )
C = 1.1 / ( 230 * 6.26 * 50 ) -> 15.231 µF for full brightness and that's a lot, I would not recommend such a simple power supply for such high power LEDs.
If you are using 20mA LEDs instead you will get this:
C = 0.2 / ( 230 * 6.26 * 50 ) -> 0.276 µF -> 276nF for full brightness and this is much easier to achieve, if you are using a lot of LEDs in serial you should do your math with the voltage drop over this LEDs.
If you are using a high power LEDs with a 22nF condenser (like it was used in the video) you are only using a fraction of the power such a LEDs could deliver.
Thank you
Güzel devre teşekkür ederim çalışıyor ❤Elhamdülillah
Thank you sir 🙏
Very nice luar biasa sekali
Thank you sir
The hidden side is not in terms of good efficiency, but in the value of consumption energy , as this method leads you to consume all voltage energy, 220 volts, as if you dissipating it in air and even reducing and taking just from it, 5 or 10 volts, but you still factured by the summe of consumption of 220 volts in the bill, but on the opposite side. If you use the transformer using the magnetic induction method, you will consume only what you converted by transferring electrons with magnetic induction at 5 or 10 volts, and you will be charged and factured only this amount in the bill. Engineers in this field do not neglect this method, but in this field nothing is valid except the correct one that gives a good efficiency of All sides the safety and even economic sides of important consuption of energy and facturisation too . This is the probability that I concluded
Thanks for watching
360' disco light bulb mein a circuit Laga sakte hain
Laga to sakte ho lekin a circuit isolated nahi hai to shock lag sakta hai thoda dhayan rakkhe . Thanks for watching 🙏
@@UltimateElectronics ok
Einfach nur Lebensgefährlich .☠💀☠💀⚡⚡⚡
Yes sir interesting but Be careful sir
yes
Aapka project bahut Sundar hai led bulb k alawa aapko multimeter se current naap kar dikhana chahiye jisase jyada bharosa ho sake baki to thik hai❤
Thank you sir
Dusra video me try karunga
I am waiting for your new video
Bhai yeh driver ko speed controller circuit ke inputt me lagane se work karega speed controller.
Karega but transformerless hone ka bajaise electrical shock lag sakta hai plz don't try this for your speed controller Thanks for watching Sir
Спасибо! Работает.
Thank you sir
This auto voltage work only for lamp?
Yes thanks for watching
This is good for destroying almost any device powered by it, then to risk being electrocuted and eventually even setting the house on fire. Congratulations,it is a multi-purpose circuit really.
😂 Thanks for watching sir ! this is used for operating led light only not for other device
I only have 105j 630 volt .will that be sufficient for this? Cool video 😁👍
Yes it will ,Thanks for watching
Nếu dùng đồng hồ vạn năng số đo điện áp led đầu ra thì có hư đồng hồ không?
If you measure the output volt without load then it may damage the multimeter ,Thanks for watching sir
Cảm ơn bạn! Nhưng bạn thật xấu xa khi không cảnh báo cho mọi người ! Mình bị giật điện vì ngỡ dòng dc không bị giật điện khi vô tình chạm vào. Cũng may tai qua nạn khỏi nên nghi ngờ và hỏi lại nếu không phải mua đồng hồ khác rồi. Xin hãy chia sẽ bằng tấm lòng bạn nhé! Chúc bạn gặp may mắn. Mong sao mọi người làm theo bạn không xảy ra chuyện gì đáng tiếc. Nhưng mình cũng vẫn cảm ơn bạn vì đã chia sẽ kiến thức này dù mình thoát chết trong gan tấc. Cám ơn bạn
Thank you. Good information. I have subscribed.
Thank you sir
As always very interesting but could you also incude schematics, please?
Thank you sir
How do you determine which of these specific voltages is set? What output voltage is this cir unit producing? As others noted, it is not isolated.
Yes sir this circuit is not isolated so please handle it carefully and this circuit produces very low current Thanks for watching
You burned your 470 ohm resistor @@UltimateElectronics
Does it work for to make a #110v ac to 3v,6v,12v,24v,48v,60v,98v LED driver?
First you step down the volt 220v to 110v ac then you will put it
Bro one doubt how to change it 60v please tell me❤️❤️❤️
Very good question bro this is a automatic circuit when you use to glow a 60v led lamp the circuit automatically works on it
Bom trabalho valeu gostei
Thank you sir
Dangerous circuite
Be careful sir
What is dangerous? AC is converted to DC , supply dropped. Only thing is you should not touch anywhere in the circuit while given supply. That's all. Nothing is dangerous.
@@amarendrag1178 thank you sir
it can use at ampliflier 1000w
att 12volts?or just for minimal watts only
Just upto 30watt
12v led strip glow ho gi naa
Hoga sir
Thanks for watching Sir
Maybe isolated transformer will be better ! 😂
Yes sir but you can make this one with carefully it is very unique and useful
Kya 80V,100W ka led panel chalega kya bhai
Itna Jada watt to nahi jalega bro upto 30 watt Tak full glow hota hai
15V 2A bana sakte hai kya ese me.?
15v to Kam karega lekin amps bohut Kam ayega ok please keep watching I will try my best to the next videos
Ampere auto set?
Fixed low amps just 500mili amps
@@UltimateElectronics sir ager ampere kam ziada kerna ho to
@@UltimateElectronics formula?
220 alternative volts passing from capacitors and resistance reducing significantly the voltage by calculate the empedance with (z) ohm that may
Appreciate
good job. what need change if for 110 VAC? can it drive a 5VDC relay?
Yes you can. And no need to connect 470 ohms r । Sir you don't connect 5v relay because there is an electrical Hazard and not proper isolation .
@@UltimateElectronics thanks.
what amp comes in output?
500 mili amps thanks for watching
@@UltimateElectronics how to increase it upto 2 amp?
first off we see the output resistor is getting toastie , start with device to power , then using knowledge of current for output and cap and resistor for voltage , lower cap yields lower voltage with smaller caps with less capacity with higher resistance
❤️
💯 nice 💯
Thank you for great support sir
I need to convert 220 volt ac to 110 volt dc.can this one wark
Video apko bohut jaldi mil jayega . Thanks For Watching Sir! Plz stay with us
هل تصلح هذه الدارة للتشغيل المستمر ٢٤ ساعة
Yes sir you can use this for long time
Ja, und sie kann von dem verstorbenen Nutzer an den nächsten vererbt werden.
...
Patna se
Patna ! I love patna
Nice 👌 😘
Thank you sir
How much mah load this circuit can deliver.
A K Goel
Sir this circuit is used for only led and there are only upto 2to3 amps current
@@UltimateElectronicsin mA
the 470 ohm resistor will get hot like a sun, you need at least 2W, but preferably at least 5W.
You can use 1 watt or 2 watt 470 Ohms Resistor to solve this issue
@@UltimateElectronics yeaaaa but it means that this circuit loses a lot of power for nothing. Without solving this problem, it's basically crap.
Yes must be 2W power dessipation ) of resistance
You can't find resistance 5W
Nice bhai 😘🎉😍
Thank you so much
Your video is good but you to mention parts list ok then it easy to understand
Ok sir thanks for watching
এটা কত দিন কাজ করবে? 😊
Great question about longevity, it works for a long time , Thanks for watching Sir! I think you can make it at home for your needs.
Good good ok thank
Thanks for watching sir
Welcome 👍
Hello the difference between transformer and capacitive reactance is about the amperage so the capacitove reactance is limited in amperage you can use it to small comsuption of amper to charge a low device cosumption but if you use it to charge a devices with high value of amper it will not be enough and take lots time i think so you find the result by using the calculation . V = i ×R and i = V/R >>> V / 1÷ ( 2π fc)
Yes you are right sir Thanks for watching
А можно его использовать как зарядка 5В? Can it be used as a 5V charger?
@@АлександрКолесниченко-б8я thanks
ncie👍
Thank you sir
هل استطيع تركيب محول في الدارة لتأمين العزل وما هي القيمة المناسبة للمحول في حال كان ذلك ممكنا...شكرا
No sir I will try my best to the next video thank you
إذا قمت بتركيب محول سيكون في البدأ ثم الذي يعمل بالحث المغناطيسي ثم تختار عدد دورات الملف الثانوي بما يناسب الفولطية التي تريدها وهذا ما يسمى الشوبر كما في الباور سوبلاي ولكن بما أنك تريد استعمال محول في البدأ حتى تخفض الفولطية ممكن كما في شواحن الهاتف كذلك تم تقوم بعدها بتوحيد التيار المتردد لتحويله الى تيار مستمر عبر أربع دايودات أو واحد الأمن هو أربعة دايودات مع إضافة بعض المكثفات للفلترة وجعله بدون نويز أي نقي ومفلتر وكذلك تنعيمه أما ما ذكرت سابقا عن الشوبر فهو قد يخرج أكثر من فولطية واحدة ويستعمل الدايود شوتكي وهذا بالنسبة للباور سوبلاي أما عن نموذج في الفيديو فهو مختلف فلا تستعمل المكثف في هذه الحالة لان هنا يستعمل حالة الممانعة السعوية وكأنها مقاومة كبيرة في التيار المتردد وليس المستمر أما دوره المكثف يختلف عن دوره في التيار المستمر فإذا استعملت المحول لاداعي أن تستعمل الممانعة السعوية أو المفاعلة السعوية
Multimeter say isska output kaise cheek kare
Load Dene ke bad iska output check kariye to thik rahega ,multimeter me DC section me deke check kare lekin circuit me hat mat lagana dhanyabad.
hi, need convert 110v DC to 12v DC, any video thet con help me?
Ok sir I will try our best to the next video
We use the resistance in parallele with capacitor to descharge the capacitors from the voltage stored inside we calculate xc = 1devided by 2πfc and if we add resistance that will be empedance (z) = racine of √R^2 + (1/2πfc )^2= ......ohm the f means fréquence and π= 3.14 and c = farad
Appreciate
Good
Thank you sir
Dangerous to life, you must isolate the mains voltage from low voltage. If the diode bridge short-circuits, there is mains voltage on the low voltage side.
Thanks for watching sir the circuit is not isolated so handle it carefully with proper knowledge and safety
Зачем так громка музыка ,мои ушки свернулись в трубочка
❤️
Its dangerous...non isolated
Try but be careful sir 🙏
How much current we can carry out
Just limit to 5mA
Maybe ?? 500 - 700 mA, then burn first the resistors (1/2 watts) then the diodes (1000v / 1A)
এটা দিয়ে কি ব্যাটারি চার্জ করা যাবে
Yes sir you can charge up to 4v battery ( lead acid , lithium ion) Low Amps, You can see another charging circuit in this channel . Thank for watching
Este circuito da choque ?
Be careful sir there is no electrical Hazzard protection so circuits give you shock
Kya ye 48v ceiling fan chala lega
Ager wattage Kam hai to chalega bro app try karke dekh sakte ho ! Thank for watching
ठीक है
Thank you sir
It will not burn because of the Capacitive impedance with resistance (z) and this capacitor must support more than 400 hundred volts to make a impedance with resistance in the alternative current also must calculate the result of gathering resistance and farad together. With base (z)
The role of capacitors in the altenative current is different of its roles in the direct current
Thank for great opinion
Thanks for watching
You assemble the subject circuit in good manner but the values of all components you have not told neither you zoom that might be readable or color code.so this is useless
All components mentioned in the video plz see the full video without skip of any part ,Thanks for watching.
На воду і електрику можно поставити неодиновий магніт який тримає 9о кг. Все робить
Thanks for watching sir 😀 it's imagine
The 470 Ohm resistor burned out. Probably you can’t give such a load. The first LED is 3 Watt, about 700 mA? Like for the video.
Without use this resistor the circuit will run smoothly Thanks a lot sir for great comment
2:29 resistor overload :D
You need to connect high watt resistor like 1 watt or 2 watt
What is the names of the tools used
Sir all tools mentioned in description
Reactance capcitive xc = 1/ 2πfc
I really like it
toto zapojeni se pouziva v led blikajicich svetel
Thank you sir
Capacitor type ( x rated ) and ziner 12 v breaking voltage in the out put as a serie not parallel with resistance 2.5 kilo ohm
Because of when using a device or somthing to suplying dc voltage in out put it will be decreasing to the just 3 volt or less than what you expect 12 volt also by a few time it will be very hot and the component wil be damaged
Thanks for watching
Pl mention or write the concept of this ,then only we can understand and accept and subscribe and promote
Thank you
схема интересная но не рабочая при подключении 3свтд на 12в горит резистор +.
The circuit working you should try 100 Ohms 1 watt resistor to the output section have a great day thank you
Please add drawing
Sir I think you understand everything if you see the full video thank you
Show us, the measurement of output voltage and amp.
Thanks for watching I Will try my best Thank You
otimo
Thank you sir
Diagram Please..! 😊
Diagram inside of video
normal radio amateurs always draw a diagram
Thank you
Baut die Schaltung NICHT nach. LEBENSGEFAHR
You should make it carefully if you do not have any experience with electronics please don't try this at home
Not sure to run long..
There is no doubt it is working , Thanks for watching
It will blast and burnt very fast if it take a load... Not useful... i meant it cannot be use.
Thanks for watching
А схемы рисовать не учили?
Thanks for watching
انا لم استوعب بعد هذه الدائرة يجب ان اقوم بيعض الحسابات لأنه من غير الممكن ان يمرر المكثف كل ذالك التيار خصوصا انه صغير السعة 0.1 ميكرو لا ينتج عنه سوى 1.5 فولت اي تيار صغير
This is a universal output circuit that has low current output
آسف .. انا قلت مكثف سعة 0.1 ميكرو وهو في الحقيقة 1 ميكرو يعني ينتج عنه تيار عالي وقد قمت بتجربة هذه الدارة على برنامج الساركت ويزارد ولم تنجح ولا يمكنه اشعال لاد بدون ان يحترق ....حتى ان جهد الخرج هو 100 فولت وهو عالي جدا .!!! ..ربما هو ينجح فقط مع مكثف 0.1 ميكرو لكن بدون وضع احمال كبيرة لأن التيار يكون صغير عكس مكثف 1 ميكرو . @@UltimateElectronics
الممانعة السعوية في التيار المتردد وليس التيار المستمر المكتفات تلعب دور آخر غير التيار المستمر
من تكلم على التيار المستمر هنا ؟ @@super_vrais1
it's not safe
Yes sir you can do this with proper make proper isolated cover otherwise you don't please if you have any knowledge Thank You for watching.have a great day.
у чувака сгорело резистор 470 ом на первом же св.диоде ногты у него крашенные. противно
Oh thanks
470k resistor watt please
Sir 470 Ohms and you can use 1 watt or 2 watt resistor
in this video he is using 1/4watt
@@james-bond-007 the 470 ohm resistor will get hot like a sun, you need at least 2W, but preferably at least 5W.
@@orange11squares sure u r right orange
Can you show ac input I think this video is fake
No sir this is not fake if you have any confusion please try this at home our channel don't publish any fake video thank you for visit
P F ka value nahi bataya
450v 105j
Very dangerous.😮
Be careful
😂
Thanks
Sem regulagem kkk
Thank you
U
Thanks for watching sir
Nonsense vdo
Thank you sir
Fake video
Not fake you can try this at home this channel don't publish any fake content thanks for watching
Bro one doubt how to change it 60v please tell me❤️❤️❤️
Thanks for watching