Graph the reciprocal function with a reflection and translations

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  • Опубліковано 4 січ 2025

КОМЕНТАРІ • 18

  • @rippedewok2653
    @rippedewok2653 Рік тому +3

    6:18 bros like "ur joking right"

  • @JoshDoes
    @JoshDoes 6 років тому +10

    Pretty good teacher, if I was in the class I would still probably be a little slow but when it's in a video form you can re-watch.

  • @MrCOOKIEMONSTA4
    @MrCOOKIEMONSTA4 11 років тому +7

    Thanks a lot this video was very helpful.

  • @oddandoddities3885
    @oddandoddities3885 6 років тому +3

    This is glorious. So much better than my teacher!

    • @brianmclogan
      @brianmclogan  6 років тому +1

      you are very welcome! happy to be there for you !

  • @hadihpballah8366
    @hadihpballah8366 6 років тому +2

    very good you would give my teacher a run for her money

  • @KM-lm8vt
    @KM-lm8vt 5 років тому +1

    Great video, it’s really helpful I’ve been watching a couple other ones too!! Thanks!!! 🙏👍🏻

  • @raindad6681
    @raindad6681 6 років тому +2

    What happens when you have a number in front the denominator?
    Like 3(x+1) is on the bottom of the fraction, what does the 3 do?
    Or if your fraction has a fraction? Like one over one-eights?

  • @adrianaraujo7236
    @adrianaraujo7236 3 роки тому +2

    Thank you for saving my ass 🙏🏻🙏🏻

  • @brianmclogan
    @brianmclogan  11 років тому +7

    ahhh they are just students. Video was kinda long

  • @imejandiskate
    @imejandiskate 11 років тому +7

    dude. good video. your students seem kinda jerky. good job keeping the cool.

  • @noussanezzar2699
    @noussanezzar2699 7 років тому +1

    can u help me i need this answer
    lim(x+sinx)/(x²+1) when x approach to +inf
    i get it =0 tel me if it's false or not

    • @brianmclogan
      @brianmclogan  7 років тому +2

      what grows faster x or x^2, whenever the denominator grows faster than the numerator then the limit will be zero as it approaches infinity and negative infinity

    • @noussanezzar2699
      @noussanezzar2699 7 років тому

      THANK U

  • @batsi__m7558
    @batsi__m7558 7 років тому +1

    Don't we have to multiply the y-coordinates by 3 since the function is -3f(x-1)-4

    • @brianmclogan
      @brianmclogan  7 років тому +1

      no it is f(x)=-3(1/x-1)-4 or multiplying the negative 3 in you obtain f(x)=(-3/x-1)-4