Graphing Rational Functions Using Transformations With Vertical and Horizontal Asymptotes

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  • Опубліковано 1 січ 2025

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  • @TheOrganicChemistryTutor
    @TheOrganicChemistryTutor  Рік тому +6

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  • @Salvation1984
    @Salvation1984 5 років тому +23

    Amazing! Thanks a bunch, I have a quiz tonight, and this video helped me understand fraction translations!

  • @georgesadler7830
    @georgesadler7830 3 роки тому +15

    MR. Organic Chemistry Tutor, this is another solid explanation of Graphing Rational Functions Using Transformations with Vertical and Horizontal Asymptotes. These concepts are fairly easy to understand. Over the years, I tutor this class at the Community College of Baltimore County in Catonsville, Maryland. I really learned this class by teaching it to many different students.

  • @ThanhLe-gh2qx
    @ThanhLe-gh2qx 4 роки тому +53

    Great explanation! I wish my teacher is half of as good as you are

    • @amanuelgedekubrom8052
      @amanuelgedekubrom8052 3 роки тому +2

      It is you that you have to work hard to solve your problem,don't waite all your problems are going to be solved by your teacher

  • @raofficial5607
    @raofficial5607 Рік тому +2

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    @ketlins3970 5 років тому +192

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    @advilproductions6561 8 місяців тому +2

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  • @Relaxing_Music-w6e
    @Relaxing_Music-w6e Рік тому +1

    Thanks, I can now ace the exam and get full marks thank you 😊

  • @Dudeotter
    @Dudeotter Рік тому +1

    thanks so much for this video! I have my algebra 2 exam tomorrow and I'm using this as review haha

  • @mutalecharles6856
    @mutalecharles6856 Рік тому

    Am having a quiz today and this video has really helped me alot

  • @Wxldcat
    @Wxldcat Рік тому +1

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  • @mrk.8448
    @mrk.8448 2 роки тому

    thank yoou so much youre saving me in college for pre calculus!!

  • @BrightAcademy12
    @BrightAcademy12 3 роки тому

    very clear and easy to understand teaching. i alway love your videos. thank

  • @elviraigorevna5206
    @elviraigorevna5206 3 роки тому +1

    Incredible! Thank you so much for this content!

  • @sandarlynn3843
    @sandarlynn3843 Рік тому

    Me patiently waiting to skip the ads so that I can watch your lectures :)

  • @Muhammad_Waleed
    @Muhammad_Waleed 2 роки тому +1

    Thank you Soo much
    Huge Respect ❤️🔥

  • @frutchiedeen9902
    @frutchiedeen9902 6 років тому +26

    How would you graph this kind of function if it has a numerator greater than one? That’s my only question. The rest of the video was extremely helpful, thank you!

    • @thatsenoughoutofyou
      @thatsenoughoutofyou 6 років тому +6

      For a rough sketch, not particularly different. More accurately, the curved parts wouldn't be as close to the asymptotes, especially at the places where vertical and nonvertical asymptotes meet. The numerical numerator is a stretching factor, we can say.

    • @Leviathan12
      @Leviathan12 2 роки тому

      @@thatsenoughoutofyou Would y=1/x -> y=3/x be a vertical shrink or stretch?

  • @Boreality_
    @Boreality_ 6 років тому +2

    Excellent video!

  • @victorychannel7776
    @victorychannel7776 3 роки тому +5

    can you do more explanation about how to draw asymptotes

  • @tamtam284
    @tamtam284 5 років тому +1

    It was so helpful thank u 🙏

  • @arisyaazizi7735
    @arisyaazizi7735 3 роки тому +1

    Thank you i love you omg

  • @p1judo
    @p1judo 3 роки тому +1

    Gracias profe dieter

  • @ey992
    @ey992 4 роки тому +15

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  • @SpinzzIsCracked
    @SpinzzIsCracked 10 місяців тому +2

    not ne learning this 4 years prior and still needing help bc school don't teach you to memorize this stuff

  • @futbolyou4129
    @futbolyou4129 5 років тому +1

    at 8:20 why is the horizintal Asymptote 0?

    • @Eth4ron
      @Eth4ron Місяць тому

      Because n > m. When n is greater than m, the horizontal asymptote is 0 most of the time.

  • @liluzi2036
    @liluzi2036 6 років тому +6

    thank youuuuu

  • @igorm8706
    @igorm8706 4 роки тому +4

    17:55 count me in

  • @sumitdutta4512
    @sumitdutta4512 Рік тому

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  • @mortezaarbabi
    @mortezaarbabi Рік тому

    Amazing tnx

  • @curry845
    @curry845 3 роки тому

    thank you very much!!!

  • @ayansuleymanova03
    @ayansuleymanova03 3 роки тому

    Thanks a bunch!!!!!

  • @astroxanime3963
    @astroxanime3963 2 роки тому +1

    Thankyou sir

  • @homeofmartialartnbi2647
    @homeofmartialartnbi2647 5 років тому +2

    Great, , and thanks

  • @gleidyscarpio7709
    @gleidyscarpio7709 3 роки тому

    hey, your las exercise, I thought when you have the difference of two squares you make x=2 and x=-2 making two vertical asymptotes instead of one

  • @zachadolphe3633
    @zachadolphe3633 5 років тому +4

    for y = (1/x^2) -3 shouldn't the graph show going to negative infinity as x approaches zero from the left and be below the -3 HA?

  • @proggapaul5776
    @proggapaul5776 Рік тому

    y = 1/(1 - x)
    What is the graph of this equation?

  • @zombiegd1969
    @zombiegd1969 3 роки тому

    11:41 Ignore this

  • @techhub_
    @techhub_ 4 роки тому

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    @theboremaker9683 2 роки тому

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    @se0sm0 11 місяців тому

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  • @limit.broken6371
    @limit.broken6371 3 роки тому

    4:54 shouldn't it be (0, negative infinity)?

    • @susa9786
      @susa9786 3 роки тому +1

      Negative numbers are on the left side of zero, so it's (-infinity,0)

    • @ImHezer
      @ImHezer 3 місяці тому

      Negative numbers are smaller than zero

  • @av7389
    @av7389 Рік тому

    9:32

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    @Vivianna-peacenluv 2 місяці тому

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    @samiulislamdurjoy 4 роки тому

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    @iamadamselindistress4969 2 роки тому

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    @Sun-gs6hq 11 місяців тому

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    @bugi9309 4 роки тому +1

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      @xpdoesevents4642 3 роки тому +1

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    @bbgr9239 2 роки тому

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