Hello...thank you for your interest in my UA-cam site. It was put together a while ago with an interest in reaching out to those interested in power systems. I have since expanded these as part of 14 courses related to electrical power and they are located on EEP - (Electrical Engineering Portal). My courses may be found by going to: academy.electrical-engineering-portal.com/courses...and selecting Graham Van Brunt P. Eng., B.Sc. after hovering over the "Authors" heading. The costs look expensive, but they are always heavily discounted. You will not be disappointed in any of them.
The equations are not messed up...each component has an A, B & C phase. The Positive sequence A, B & C phases are separated by 120 degrees as the Negative sequence A, B & C phases are separated by 120 degrees. The 0 sequence A, B & C phases are in phase with each other. The A phases of each component will vary relative to each other as do the B & C phases of each component.
If you plug in the phasors into the expressions, you cannot possibly arrive at the results. Your results are correct, but you have displayed the expressions incorrectly
Hello Sir...thank you for your interest in my UA-cam site. It was put together a while ago with an interest in reaching out to those interested in power systems. I have since expanded these as part of 14 courses related to electrical power and they are located on EEP - (Electrical Engineering Portal). My courses may be found by going to: academy.electrical-engineering-portal.com/courses...and selecting Graham Van Brunt P. Eng., B.Sc. after hovering over the "Authors" heading. The costs look expensive, but they are always heavily discounted. You will not be disappointed in any of them.
Hello Sir...thank you for your interest in my UA-cam site. It was put together a while ago with an interest in reaching out to those interested in power systems. I have since expanded these as part of 14 courses related to electrical power and they are located on EEP - (Electrical Engineering Portal). My courses may be found by going to: academy.electrical-engineering-portal.com/courses...and selecting Graham Van Brunt P. Eng., B.Sc. after hovering over the "Authors" heading. The costs look expensive, but they are always heavily discounted. You will not be disappointed in any of them.
Very intuitive explanations and very profesional. Can you just explain further on the start of 39:08, on how a to power negative2 become simply a, thanks.
From 16:40 u can see that a^(-1) = a^2, from this we understand that a^2=1/a hence while finding a^(-2) we substitute 1/a instead of a^2 in the equation a^(-2)=1/a^2 therefore we get a^(-2)=1/(1/a) which is nothing but 'a'
Hello...thank you for your interest in my UA-cam site. It was put together a while ago with an interest in reaching out to those interested in power systems. I have since expanded these as part of 14 courses related to electrical power and they are located on EEP - (Electrical Engineering Portal). My courses may be found by going to: academy.electrical-engineering-portal.com/courses...and selecting Graham Van Brunt P. Eng., B.Sc. after hovering over the "Authors" heading. The costs look expensive, but they are always heavily discounted. You will not be disappointed in any of them.
I don't think you realize how much of a life saver you are, appreciate it man.
Thanks for the video. Studying for Power PE exam and this helps out a lot understanding the relationship between each phase.
Thanks for wonderful lecture!!! This video makes me to understand symmetrical components completely!
Thank you! We appreciate it! great way to simple things! Well done! 👍👍👍
Thank you sir. You help me a lot.
wounderful explanation. thanks
Thanks dear its helpful
Thank you sir! Very well 👌 explained the topic
Thank you very much, excellent review for the PE electrical test
Very very good explanation! Thanks for the video!!
thanks a lot
Hi Graham, I like your lecture.Thanks
Hello...thank you for your interest in my UA-cam site. It was put together a while ago with an interest in reaching out to those interested in power systems. I have since expanded these as part of 14 courses related to electrical power and they are located on EEP - (Electrical Engineering Portal). My courses may be found by going to: academy.electrical-engineering-portal.com/courses...and selecting Graham Van Brunt P. Eng., B.Sc. after hovering over the "Authors" heading. The costs look expensive, but they are always heavily discounted. You will not be disappointed in any of them.
Great explanation.
at 32:05, the equations are messed up. ie, to work out the +ve seq comp, you need to rotate by 0, 120 and 240
The equations are not messed up...each component has an A, B & C phase. The Positive sequence A, B & C phases are separated by 120 degrees as the Negative sequence A, B & C phases are separated by 120 degrees. The 0 sequence A, B & C phases are in phase with each other. The A phases of each component will vary relative to each other as do the B & C phases of each component.
@@pspt
Are you confirming if the 3 expressions on the left hand side of the screen are correct, refer timeline 32:05?
If you plug in the phasors into the expressions, you cannot possibly arrive at the results.
Your results are correct, but you have displayed the expressions incorrectly
Hi Graham, I like your lecture
Hello Sir...thank you for your interest in my UA-cam site. It was put together a while ago with an interest in reaching out to those interested in power systems. I have since expanded these as part of 14 courses related to electrical power and they are located on EEP - (Electrical Engineering Portal). My courses may be found by going to: academy.electrical-engineering-portal.com/courses...and selecting Graham Van Brunt P. Eng., B.Sc. after hovering over the "Authors" heading. The costs look expensive, but they are always heavily discounted. You will not be disappointed in any of them.
thank you very much
I hope from you add the link of paper ❤️
Hello Sir...thank you for your interest in my UA-cam site. It was put together a while ago with an interest in reaching out to those interested in power systems. I have since expanded these as part of 14 courses related to electrical power and they are located on EEP - (Electrical Engineering Portal). My courses may be found by going to: academy.electrical-engineering-portal.com/courses...and selecting Graham Van Brunt P. Eng., B.Sc. after hovering over the "Authors" heading. The costs look expensive, but they are always heavily discounted. You will not be disappointed in any of them.
Very intuitive explanations and very profesional. Can you just explain further on the start of 39:08, on how a to power negative2 become simply a, thanks.
From 16:40 u can see that a^(-1) = a^2, from this we understand that a^2=1/a hence while finding a^(-2) we substitute 1/a instead of a^2 in the equation a^(-2)=1/a^2 therefore we get a^(-2)=1/(1/a) which is nothing but 'a'
Can I get the ppt presentation file please?
Love it
error in 32:15
Hello...thank you for your interest in my UA-cam site. It was put together a while ago with an interest in reaching out to those interested in power systems. I have since expanded these as part of 14 courses related to electrical power and they are located on EEP - (Electrical Engineering Portal). My courses may be found by going to: academy.electrical-engineering-portal.com/courses...and selecting Graham Van Brunt P. Eng., B.Sc. after hovering over the "Authors" heading. The costs look expensive, but they are always heavily discounted. You will not be disappointed in any of them.
Yes, i noticed it too. I was smh when saw it and did not agree with what I had written down
@@psptwebsite is not working?
....
Thank you sir! Very well 👌 explained the topic