If you need a Grashof crank rocker: 0) Draw A, A', B, B' 1) Find the *rotopole* aka the intersection of the perpendicular bisectors between A-A' and B-B' 3) Create the link(s) that will bring A and B to A' and B' Simultaneously 4) Use the method of creating a Grashof non-quickreturn crank rocker (wiper) on the special link 5) Profit If you prefer to get the coupler to hit three positions at A and B: 0) Draw A, A' A'', B, B', B'' 1) Find the A *rotopole*: the intersection of the perpendicular bisector of A-A'-A'' 2) Find the B rotopole: Same thing but for B-B'-B'' 3) Create links from the A rotopole to A and the B rotopole to B 4) Profit
I need more videos of him , please!
If you need a Grashof crank rocker:
0) Draw A, A', B, B'
1) Find the *rotopole* aka the intersection of the perpendicular bisectors between A-A' and B-B'
3) Create the link(s) that will bring A and B to A' and B' Simultaneously
4) Use the method of creating a Grashof non-quickreturn crank rocker (wiper) on the special link
5) Profit
If you prefer to get the coupler to hit three positions at A and B:
0) Draw A, A' A'', B, B', B''
1) Find the A *rotopole*: the intersection of the perpendicular bisector of A-A'-A''
2) Find the B rotopole: Same thing but for B-B'-B''
3) Create links from the A rotopole to A and the B rotopole to B
4) Profit
We are gonna get Distinctions 💪!
Awesome. Very Informative video Sir.
It's from Dr Robert
@@DrSohailMalik yep, in black and white, but very detailed and impressive.
Another i Shall upload on quick return in black and white
@@DrSohailMalik could you post more videos about linkage sythensis. linkage or mechanism is very fun,
mechanism designing from one position to another. good!
Thanks
Why is it necessary for the Grashoff condition to be satisfied?
To avoid toggle between start and end in both directions.
the person is Norton himself?
Yes,he is.
Qu? Anyone?