why we cant transmit the B frame in [t - Tfr, t] time slot and A frame in [t, t+ Tfr] ?? why the entire [t - Tfr to t] time slot shoul be free in order to avoid collision??
I never have understood a single lecture by Tutorials Point. He should either speak in Hindi or if he chooses to speak in English then that should be clear. *पता नहीं क्या हि बोलता है* |
at 10:49 you told that to avoid a collision the previous frame should also be free but the forward time should also be free for it to avoid the collision in future then the Vulnerable time should be V=3*Tfr right???
The next Tfr will be taken into account by the next station who has to transmit data next. Next Tfr will be counted in vulnerable time for next station.
why we cant transmit the B frame in [t - Tfr, t] time slot and A frame in [t, t+ Tfr] ?? why the entire [t - Tfr to t] time slot shoul be free in order to avoid collision??
00:01 Pure Aloha is a random access protocol for wireless LAN and shared medium. 01:34 Collision occurs when multiple stations transmit data at the same time. 03:05 Pure Aloha allows stations to transmit frames on a shared medium. 04:39 Pure Aloha enables any station to transmit data at any point of time, leading to collision possibilities. 06:05 Pure Aloha uses a strategy called waiting for a random amount of time to prevent collision. 07:31 The throughput of Pure Aloha is maximized when frames are of uniform size. 09:04 In Pure Aloha, collisions occur when multiple frames are transmitted simultaneously. 10:37 Pure Aloha is a multiple access protocol
why we cant transmit the B frame in [t - Tfr, t] time slot and A frame in [t, t+ Tfr] ?? why the entire [t - Tfr to t] time slot shoul be free in order to avoid collision??
I hope you know how adored you are by us CS and ECE students. I've talked to random other students who definitely use your channel as a huge resource.
Definitely
why we cant transmit the B frame in [t - Tfr, t] time slot and A frame in [t, t+ Tfr] ?? why the entire [t - Tfr to t] time slot shoul be free in order to avoid collision??
The most underrated channel. Thank u for each and every tutorial ❤️
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Neso academy is doing their best grateful job keep it up 👍
You explained this so much better than my professor.
Excellent teaching sir.. We want more videos from u
super explanation, clear voice. Thank you very much. better than tutorials point lecturs..
I never have understood a single lecture by Tutorials Point. He should either speak in Hindi or if he chooses to speak in English then that should be clear. *पता नहीं क्या हि बोलता है* |
MR. Neso THANK YOU for giving such information for us.... keep going..😇😇
you are ultimate man!!!lots of love to you
This explanation is so clear .thanks♥️🔥👍
Thanks, that really helped to visualize it.
Who need paid courses when you have a Neso Academy courses for free 🔥🔥
Thank you Sr 😃
really excellent sir
You understand well so you are able to explain in simple manner❤️❤️whereas our lecturers never understand 😏so thy can't teach properly🤦
clear explanation thank you very much
Great video, keep up the amazing work
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@@nesoacademy it is still asking for fuel
thank you sir
Excellent Teaching
Thank you!
Simple and best
thank u so much sir
Thank you so much
thank you
Thank you very much👍
Thankuu sirrr it means a lot💗
You're really good!! Thank you
Very helpful!
Thanks sir
can we simulate ALOHA using Packet Tracer? If yes then please upload its video? If no then please let us know , in which platform we can do this?
Explanation 👍🔥
BOOM!
Awesome sir👌👌👌👌
thanku
For throughput formula, if G = number of stations...how can we take G = 0.5 ?
same what a nonsense line, and trying to explain it as if it makes some sense.
at 10:49 you told that to avoid a collision the previous frame should also be free but the forward time should also be free for it to avoid the collision in future then the Vulnerable time should be V=3*Tfr right???
The next Tfr will be taken into account by the next station who has to transmit data next. Next Tfr will be counted in vulnerable time for next station.
No, if the current frame is free and we know that all frames are uniform. It is obvious that the next frame will not be collided with the current one.
@@mahamamir9176 elaborate
Tq sir nice
Boom!
2:30 😂😂😂😂😂👌👌👌👌
Hiii
How are you❤
@@sumadhursah6019 ha bhai mil gaya reply
Nice Video!👍
Doubt :How the throughput of pure ALOHA is maximized when frames are in uniform length?🤔🤔🤔🤔🤔
Compare the last slide with the first slide
Non uniform has more collision
@@whois2517 Thank you
Now i remember ALHOHA with the boom
why we cant transmit the B frame in [t - Tfr, t] time slot and A frame in [t, t+ Tfr] ?? why the entire [t - Tfr to t] time slot shoul be free in order to avoid collision??
🤩
11:40 how the number of stations can be in a non-integer value G=0.5?
Same question
it means when one station transmit in 2Tframe then u will get maximum efficiency
saviour
Nice video🤟
So pure aloha does not actually solves the problem of collision?
It solves,by retransmitting if ack is not received by the sender
@Neso Academy what is frame transmission time??
Great , Brilliant bro but please use Hindi language
13/7/21
11:51 am
impossible that i saw this comment at the same time three years down the line. Gosh!!
How can we have 1/2 station????
Why throughput is maximum at G = 0.5 ?????
@@_s_h_l_o_k_ differentiate it, and equate to 0, you'll know.
i am dead after listening to your pure accent :-
A :- ye
shared :- shard
damn god protect us
boom
,it leads to collision.
How 1/2 system as transition state
7:30? Someone please elaborate why it happens
Please what is half station
does this videos has notes?
yay and b
A❌ Yeaa✅
sir total kitne video hai iss series mei
205
@@kaushalagrawal1620 Yaha to bas 97 hi dikh rhe h
You dance around collisions without actually explaining the ALOHA protocol properly.
What is the limit of G in pure-aloha? :(
I know a website where you can check it. its name is google.
@@catast9075 gotem
9:46
Half Station ?
Does it mean half of the total number of stations (G) involved in transmitting the frames ??
7:30? Someone please elaborate why it happens
00:01 Pure Aloha is a random access protocol for wireless LAN and shared medium.
01:34 Collision occurs when multiple stations transmit data at the same time.
03:05 Pure Aloha allows stations to transmit frames on a shared medium.
04:39 Pure Aloha enables any station to transmit data at any point of time, leading to collision possibilities.
06:05 Pure Aloha uses a strategy called waiting for a random amount of time to prevent collision.
07:31 The throughput of Pure Aloha is maximized when frames are of uniform size.
09:04 In Pure Aloha, collisions occur when multiple frames are transmitted simultaneously.
10:37 Pure Aloha is a multiple access protocol
why we cant transmit the B frame in [t - Tfr, t] time slot and A frame in [t, t+ Tfr] ?? why the entire [t - Tfr to t] time slot shoul be free in order to avoid collision??
How Can I get your ppt?
You can't.
Ycce gang wya
This technique is very tedium
Cant get it 😅
it seems that the world suffer from bad teachers, this is very obvious from the comments.
p
2:24 BooM!!
Wv
3rd class
just chnge the backgrond green background………………………..
Hindi nhi aati kya Bhai use Hindi also
Very poor pronunciation... 😢
The Indian accent in this video is hard to understand. Perhaps a AI generated voice is more welcomed
Please change your voice tone
Boom!
Thank You