Thanks, Fatima! We're so glad you enjoyed the lecture. Don't forget to subscribe for future sessions and feel free to send us a DM with any questions or for info on our Prep options. :)
Really enjoyed the way the lessons were taught. It's impeccable !! . I have one slightest doubt: in the last qs (56:00), how come the probability P(of getting 1 greater than 4) = 2/6? I didn't entirely get this explanation. Could you kindly elaborate a bit more? Thanks in advance!
Hey! Thanks for your feedback and question! For one roll, the probability of getting a number greater than 4 is the probability of rolling a 5 or a 6. As such, there are 2 possible success cases, out of the 6 total possible numbers, meaning P = 2/6. Does that make sense?
@bravo I think you mean 2 distinct factors. I get that. I was just musing a bit because one of my professors 30+ yrs ago was so indignant about 1 not being considered a prime anymore. He was in his 80s. Lol. It just depends on how it's defined today as opposed to in previous decades. My comment was more of a joke than anything.
Hello Sir, I don't understand solving of Question 6. If remove 2 chips in bag, remains 10 chips in bag. Why second probability is 1/11? Maybe I can't understand due to English isn't my native language.
Hi! Good question! The important thing to keep in mind is that he pulls out the chips one at a time. So for the first chip, the probability is 1/12. Now there's only one fewer chip in the bag, so the probability for the second chip is 1/11. Does that make sense?
Hi, Mansi! You can take a look at a bit more info on the GRE itself in our Blog Article here: www.manhattanprep.com/gre/blog/what-is-the-gre/ You can also take a look at the Prep we offer via the link below and if you'd like further details or personalized assistance in choosing the best option for you, shoot us an email at nxtsocial@kaplan.com and we'll connect you with an Enrollment Specialist for details. GRE Prep: www.manhattanprep.com/gre/
Hi! Thanks for your question. Our GRE Free Prep Hour series is not intended to be a complete program. Each teacher decides what they would like to teach, so some topics might be covered more than once and some might not be covered at all. It's possible that some students might find Free Prep hour to be enough to get to their goal score, but if you are aiming for an especially high score, then use this series as a supplement to your main course, books, or studies.
Hi, Pushpak! Thanks for your question. Sorry, I kind of rushed through that calculation in the lecture. The probability of a single roll greater than 4 is 2/6 (two possible numbers (5 and 6) out of 6 total possibilities). To get two rolls greater than 4, we multiply 2/6 x 2/6, which is 4/36, or 1/9. Does that make sense?
Hi, Murtaza! Thanks for your question! Our GRE Free Prep Hour series is not intended to be a complete program. Each teacher decides what they would like to teach, so some topics might be covered more than once and some might not be covered at all. It's possible that some students might find Free Prep hour to be enough to get to their goal score, but if you are aiming for an especially high score, then use this series as a supplement to your main course, books, or studies.
Hi, Arif! You can absolutely join in any of our Prep Hour sessions. Even if you aren't studying for the GRE right now, the strategies and techniques shared by the instructors in the videos are always beneficial to have in your exam prep toolkit.
What I've learned from this lecture is that I need to go play more craps to study for the GRE. Probability involving 6's all day. great lecture.
at 50:30, the possible outcomes of two dice rolls whose sum is 8 are {(2,6), (3,5), (4,4), (4,4), (5,3), (6,2)}. so the probability is 6/36 = 1/2.
you need to count 4,4 only once because it is the same in either ways
One of the best lectures!!
Thanks, Fatima! We're so glad you enjoyed the lecture.
Don't forget to subscribe for future sessions and feel free to send us a DM with any questions or for info on our Prep options. :)
@@manhattanprepgre7390 That's great :)
Really enjoyed the way the lessons were taught. It's impeccable !!
.
I have one slightest doubt: in the last qs (56:00), how come the probability P(of getting 1 greater than 4) = 2/6? I didn't entirely get this explanation. Could you kindly elaborate a bit more?
Thanks in advance!
Hey!
Thanks for your feedback and question!
For one roll, the probability of getting a number greater than 4 is the probability of rolling a 5 or a 6. As such, there are 2 possible success cases, out of the 6 total possible numbers, meaning P = 2/6. Does that make sense?
easy explanation, thanks for the video
I'm still debating on whether 1 is a prime or not. Lol (Edit: FYI, my math courses were pretty old school, 1990s).
One is not a prime number as a number to be prime it needs 2 factors
@bravo I think you mean 2 distinct factors. I get that. I was just musing a bit because one of my professors 30+ yrs ago was so indignant about 1 not being considered a prime anymore. He was in his 80s. Lol. It just depends on how it's defined today as opposed to in previous decades. My comment was more of a joke than anything.
God bless you
Hello Sir, I don't understand solving of Question 6. If remove 2 chips in bag, remains 10 chips in bag. Why second probability is 1/11? Maybe I can't understand due to English isn't my native language.
Hi! Good question! The important thing to keep in mind is that he pulls out the chips one at a time. So for the first chip, the probability is 1/12. Now there's only one fewer chip in the bag, so the probability for the second chip is 1/11. Does that make sense?
Thank you so much.
You're very welcome! :)
It is Very useful Thanks
We're so happy that the Prep Hour is useful to you! :)
yo hey well i want to know more about gre so can you tell me about it please?
Hi, Mansi! You can take a look at a bit more info on the GRE itself in our Blog Article here: www.manhattanprep.com/gre/blog/what-is-the-gre/
You can also take a look at the Prep we offer via the link below and if you'd like further details or personalized assistance in choosing the best option for you, shoot us an email at nxtsocial@kaplan.com and we'll connect you with an Enrollment Specialist for details.
GRE Prep: www.manhattanprep.com/gre/
is this enough for probability prep??
Hi! Thanks for your question. Our GRE Free Prep Hour series is not intended to be a complete program. Each teacher decides what they would like to teach, so some topics might be covered more than once and some might not be covered at all. It's possible that some students might find Free Prep hour to be enough to get to their goal score, but if you are aiming for an especially high score, then use this series as a supplement to your main course, books, or studies.
I had doubt in question 10
How is probability for 4+,4+ 2/6 and not 2/36
Please explain this I'm stuck here
Hi, Pushpak! Thanks for your question. Sorry, I kind of rushed through that calculation in the lecture. The probability of a single roll greater than 4 is 2/6 (two possible numbers (5 and 6) out of 6 total possibilities). To get two rolls greater than 4, we multiply 2/6 x 2/6, which is 4/36, or 1/9. Does that make sense?
@@manhattanprepgre7390 thanks for your guidance 👍🏻
You're very welcome! 😊
is this course enough for preparing for gre totally?
Hi, Murtaza! Thanks for your question! Our GRE Free Prep Hour series is not intended to be a complete program. Each teacher decides what they would like to teach, so some topics might be covered more than once and some might not be covered at all. It's possible that some students might find Free Prep hour to be enough to get to their goal score, but if you are aiming for an especially high score, then use this series as a supplement to your main course, books, or studies.
I'm a frehsman in college, so should I still watch these videos?
Hi, Arif! You can absolutely join in any of our Prep Hour sessions. Even if you aren't studying for the GRE right now, the strategies and techniques shared by the instructors in the videos are always beneficial to have in your exam prep toolkit.