Muchas gracias por compartir este video sinceramente la primera parte muchos videos lo mencionan pero en tu ultimo metodo con la region amarilla es la que no podia encontrar, siempre en origin 6.5 si lo podia hacer pero en las ultimas versiones no encontraba esa opcion hasta que vi tu video, muchas gracias amigo y ojala puedas seguir subiendo mas videos interesantes :).
FWHM should be multiply with cos theta, right? Isn't it should be: (Col("K")*Col("λ"))/radians(Col("FWHM"))*cos(radians(Col("Peak Position 2theta"))/2)/10 instead of: (Col("K")*Col("λ"))/radians(Col("FWHM"))/cos(radians(Col("Peak Position 2theta"))/2)/10 Please correct me if I'm wrong. TQ
Hi. I tried analyze my XRD data. After picking up the peak, and try to "Fit till Converge", The last message says "Fit did not converge".. So, what should I do?
That's one of the reasons, why should you do the suggested method. So, please follow the next method shown in the video. The method with quick fit option.
@@InSciLab Is it true that for some samples some fittings are preferred to the others? I have found for some of my samples that Lorentz is the best but for some samples Gauss is the best. What is ur opinion in this regard?
Is this method need baseline before ? I am very happy when you reply me because i have some trouble with them. Because my data is not nice and graph is not straight!
It can be found on our website, InScilab inscilab >XRD tutorials> article "FWHM & Crystallite Size (Scherrer equation) from XRD using Origin |2 methods".
(Col("K")*Col( "l"))/(radians(Col("FWHM") )*cos(radians(Col("Peak position 2theta")/2))*10) (Col("K")*Col( "l"))/radians(Col("FWHM") )/cos(radians(Col("Peak position 2theta")/2))/10 both are valid ... (mark the brackets)
Thank you sir. I have been using rather complicated approach, this simplifies and speeds up my calculations.
You are most welcome
Thanks for this helful video!
Muchas gracias por compartir este video sinceramente la primera parte muchos videos lo mencionan pero en tu ultimo metodo con la region amarilla es la que no podia encontrar, siempre en origin 6.5 si lo podia hacer pero en las ultimas versiones no encontraba esa opcion hasta que vi tu video, muchas gracias amigo y ojala puedas seguir subiendo mas videos interesantes :).
Gracias por sus valiosos comentarios.
Thank you so much for your video. It helped me a lot! 😊
THANK U FOR UPLOADING IT HELPED ME A LOT
looks easy and understandable.Thanks sir
Nice video, thanks for the templates as well.
Glad you like them!
thanks for your uploads... Really it's very informative... Kindly upload a video on the use of "Digital micrograph 3.7".........
Thanks a lot it is working sir.....
W = FWHM/sqrt(ln(4)) in Origin (6:05)
Nice video, thanks sir.
Thank you for this helpful video
According to formula FWHM*cos but have used in set column value / instead of *
FWHM should be multiply with cos theta, right?
Isn't it should be:
(Col("K")*Col("λ"))/radians(Col("FWHM"))*cos(radians(Col("Peak Position 2theta"))/2)/10
instead of:
(Col("K")*Col("λ"))/radians(Col("FWHM"))/cos(radians(Col("Peak Position 2theta"))/2)/10
Please correct me if I'm wrong. TQ
Thanks Sir.
Thank you so much sir
Man, you are the best !!
What a great encouragement! Thanks
Foi de grande ajuda este tutorial! Muito obrigado por compartilhar seu conhecimento. Thanks to share your knowledge!
Hi. I tried analyze my XRD data. After picking up the peak, and try to "Fit till Converge", The last message says "Fit did not converge".. So, what should I do?
That's one of the reasons, why should you do the suggested method. So, please follow the next method shown in the video. The method with quick fit option.
Hii...its really a nice video. Have you compared the results with Voigt fitting?
Yes. This was better.
@@InSciLab Is it true that for some samples some fittings are preferred to the others? I have found for some of my samples that Lorentz is the best but for some samples Gauss is the best. What is ur opinion in this regard?
@@ashaneog6470 Yes. exactly right
@@InSciLab thank you
Fit did not converge. Maximum iteration setting of 400 was reached. how to solve?
and after i got all those crystalite sizes, do i average it out to get a single value?
Super sir
Thank you very much. Excellent job, more grease to your elbow
thank you. if only the K value can be turned into an equation that represents several particle shapes, then no need to choose either spherical or etc.
MUCHAS GRACIAS !!!
Hi, is this based on Segal's method to calculate the Crystallinity Index? Thank u
Scherrer equation for size and Segal's equation for Crystallinity
If there is about 4 samples, can it be determined by stacking all together in a graph or must do one sample at a time?
I would do one at a time.
Can we calculate cristalite size in the multiphase data ?
I think so... If you sort out the peaks corresponding to each phase....
very useful
Wonderfull 😍
So where is the link of the template
Check the description
Is this method need baseline before ? I am very happy when you reply me because i have some trouble with them. Because my data is not nice and graph is not straight!
Yes that would be better!
If you have very noisy data, you can smooth it and do baseline correction.
Sir can u share me xpert highscore plus software....
Where is the excel files for the calculations?
It can be found on our website, InScilab
inscilab >XRD tutorials> article "FWHM & Crystallite Size (Scherrer equation) from XRD using Origin |2 methods".
Sir what is the name of the background music????
Saving the World by Aaron Kenny
during vedio i feel i am seeing Hollywood movie
You are the champ.
🙂 🤗 🤩
cheers m8
Instrumental brodening needs to be subtracted.
cool music
😃
Hi, I think you calculated the Scherrer equation wrong in your code. you are dividing FWHM by Cos theta rather than multiplying.
(Col("K")*Col( "l"))/(radians(Col("FWHM") )*cos(radians(Col("Peak position 2theta")/2))*10)
(Col("K")*Col( "l"))/radians(Col("FWHM") )/cos(radians(Col("Peak position 2theta")/2))/10
both are valid ... (mark the brackets)
In fact, FWHM is not accurate. Check integral breadth instead!
ماكو داعي إلى هذه الموسيقى المزعجه
where is the link to download the template