Angular momentum will be conserved because only centre angular momentum is conserved butbafteb initial frame will be equal to final momentum as L1 *L2 there is no external torquein this angular momentum l- I w it is omega as ans angular momentum brother is Linear model 😎🙏❤️
The postulate is "Electrons revolve around in orbits whose angular momentum is the integral multiple of h/2π" It means that electrons only revolve around an orbit where the angular momentum is equal to nh/2π. Essentially, Iω=nh/2π. => mr²ω=nh/2π => m(an²/Z)²ω= nh/2π => ma²n⁴ω/Z² = nh/2π =>ω = Z²h/2πn³a²m where, ω is the angular speed of the electron, m is the mass of the electron, Z is the atomic number, a is the Bohr's orbit, n is the shell number. This equation says us that the electron can only revolve in orbits where the electron can achieve Z²h/2πn³a²m angular speed.
Torque=d(ang. Momentum) /dt. So, if torque is 0 then ang. Momentum is constant. ________________________________ Angular momentum=moment of momentum. (Rvector×m(vvector)). If we differentiate ang momentum with respect to time, (then it will give Rvector×fvector) which is actually torque;so it proves that torque=d(ang momentum) /dt. ________________________________ Ang momentum=Rvector×m(vvector). Vvector=Rvector×omegavector. Looking in terms of magnitude, Ang momentum=mR²omega. mR² is moment of inertia(I), so ang momentum=I.omega. ________________________________ If ang momentum is constant due to torque 0,then I. Omega =constant.Now if if You increase I then angular velocity(omega) will decrease and vice versa. ________________________________Hope it clears all your minutest of doubt.
Correction_____ Vvector=omegavector×Rvector. Magnitudinally:V=R.omega. Ang momentum=Rvector×mRomega Magnitudinally:mR²omega(sin 90=1). So, ang momentum=I.omega.
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Khan Academy is owned by TATA group.
So basically it's Indian.
Amazing voice... Science samajne ke liye best hai. It's like discovery show
Mujhe to Ben 10 ka Hindi voice lagi h
Sir,you teaching idea is very good.thanks for angular momentum,🥰🥰🥰👨🏫👨🏫
Sir your teaching skills are fentestic
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Understood every concept very well
It's a very good explanation
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woww sirr aap ke examples aur aapke pdhane ka trika awsm hai
Very Very Fantastic way of teaching
Why angular momentum is conserved in non inertia frame ??
Angular momentum will be conserved because only centre angular momentum is conserved butbafteb initial frame will be equal to final momentum as L1 *L2 there is no external torquein this angular momentum l- I w it is omega as ans angular momentum brother is Linear model 😎🙏❤️
👌👌👌❤
Could u please make us understand what did Bohr mean by one of his postulate:
"Electrons can revolve in orbits of fixed angular momentum".
The postulate is "Electrons revolve around in orbits whose angular momentum is the integral multiple of h/2π"
It means that electrons only revolve around an orbit where the angular momentum is equal to nh/2π.
Essentially, Iω=nh/2π.
=> mr²ω=nh/2π
=> m(an²/Z)²ω= nh/2π
=> ma²n⁴ω/Z² = nh/2π
=>ω = Z²h/2πn³a²m
where, ω is the angular speed of the electron, m is the mass of the electron, Z is the atomic number, a is the Bohr's orbit, n is the shell number.
This equation says us that the electron can only revolve in orbits where the electron can achieve Z²h/2πn³a²m angular speed.
He just quantised the angular momentum of electrons "mvr = nh/2π , n belongs to Natural number
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@@ankitasur4560 kabhi to shant se rah lo bhai
Thanks sir
Perfect 🔥
Ben 10 and pokemon voice
Best explaination ever
Good
Thankyou sir for such a nice explanation
Very good explanation 👍
Thank you so much
This video is good but
Too gud sir... tq
Great
WR = V
MVR = L
Sir really explained very well
Thankyou very much
Moment inertia
Thanks bhai
thank you sir, aap bilkul gazab smjhaye, like length : content ratio just rocked
♥️finally♥️
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Nice explanation sir 🎉🎉🎉🎉👍👍👍👍
Nice explanation
Keep it up
sir samajh nhai aaya
Thank you
Thank you for helping
Make my doubt clear 👍🏻❤️
Best explanation ever
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Thanks.
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Thanks a ..lot
Sarthak Ramdas Khalkar
Definition chahiye
👍
Woooo
Thank you sir,
I
Wahh..
Mja aa gya sirji
hey, You have to specify the axis/point about which you are taking about
Thanku sir for this explanation
Prove it derivationally
Torque=d(ang. Momentum) /dt.
So, if torque is 0 then ang. Momentum is constant.
________________________________
Angular momentum=moment of momentum. (Rvector×m(vvector)).
If we differentiate ang momentum with respect to time, (then it will give Rvector×fvector) which is actually torque;so it proves that torque=d(ang momentum) /dt.
________________________________
Ang momentum=Rvector×m(vvector). Vvector=Rvector×omegavector.
Looking in terms of magnitude,
Ang momentum=mR²omega.
mR² is moment of inertia(I), so ang momentum=I.omega.
________________________________
If ang momentum is constant due to torque 0,then I. Omega =constant.Now if if You increase I then angular velocity(omega) will decrease and vice versa.
________________________________Hope it clears all your minutest of doubt.
Correction_____
Vvector=omegavector×Rvector.
Magnitudinally:V=R.omega.
Ang momentum=Rvector×mRomega
Magnitudinally:mR²omega(sin 90=1).
So, ang momentum=I.omega.
V nice
Bekar
Thank u sir u are great
Thanks sir
Thanks sir