Conservation of angular momentum (Hindi)

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So much happy to discover that one of my favorite study channels is in Hindi as well... Thank you very much Khan Academy 💖💖

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Khan Academy is owned by TATA group.
So basically it's Indian.

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Amazing voice... Science samajne ke liye best hai. It's like discovery show

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Mujhe to Ben 10 ka Hindi voice lagi h

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Sir,you teaching idea is very good.thanks for angular momentum,🥰🥰🥰👨‍🏫👨‍🏫

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Sir your teaching skills are fentestic

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Excellent narration...i love the way this guy explains.....

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thank you sir, aap bilkul gazab smjhaye, like length : content ratio just rocked

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woww sirr aap ke examples aur aapke pdhane ka trika awsm hai

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Very Very Fantastic way of teaching

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Nice work keep it up.
Understood every concept very well

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Best explaination ever

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It's a very good explanation

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Very good explanation 👍

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Best explanation ever

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Sir really explained very well

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Wahh..
Mja aa gya sirji

[@rahuljoshi586]

Make my doubt clear 👍🏻❤️

[@javeriaabbasi2684]

Could u please make us understand what did Bohr mean by one of his postulate:
"Electrons can revolve in orbits of fixed angular momentum".

[@sambhabgiri573]

The postulate is "Electrons revolve around in orbits whose angular momentum is the integral multiple of h/2π"
It means that electrons only revolve around an orbit where the angular momentum is equal to nh/2π.
Essentially, Iω=nh/2π.
=> mr²ω=nh/2π
=> m(an²/Z)²ω= nh/2π
=> ma²n⁴ω/Z² = nh/2π
=>ω = Z²h/2πn³a²m
where, ω is the angular speed of the electron, m is the mass of the electron, Z is the atomic number, a is the Bohr's orbit, n is the shell number.
This equation says us that the electron can only revolve in orbits where the electron can achieve Z²h/2πn³a²m angular speed.

[@champu823]

He just quantised the angular momentum of electrons "mvr = nh/2π , n belongs to Natural number

[@ssumithradevi2299]

Too gud sir... tq

[@snehlatasen577]

Nice video.

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Nice explanation

[@yogesh1535]

Thank you for helping

[@rushikeshpatil4017]

Perfect 🔥

[@ratankumarmahato8192]

hey, You have to specify the axis/point about which you are taking about

[@virajofficial2389]

Thanks so much 😊

[@priyanshusrivastav915]

Why angular momentum is conserved in non inertia frame ??

[@onlylivehrgamers4903]

Angular momentum will be conserved because only centre angular momentum is conserved butbafteb initial frame will be equal to final momentum as L1 *L2 there is no external torquein this angular momentum l- I w it is omega as ans angular momentum brother is Linear model 😎🙏❤️

[@balupujari4512]

Nice

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Thanku sir for this explanation

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Thankyou very much

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Thanks a ..lot

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Good

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Keep it up

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Great

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Thanks bhai

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Thank you

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Thank u sir u are great

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V nice

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Thanks.

[@shivnandran4955]

This video is good but

[@shivangisingh871]

♥️finally♥️

[@chhotatrader7619]

Moment inertia

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👌👌👌❤

[@junkkyardd422]

Thank you sir,
I

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Thanks sir

[@Sushilakkaumar65]

Definition chahiye

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Sarthak Ramdas Khalkar

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Ben 10 and pokemon voice

[@i.ashishhhv.x]

WR = V
MVR = L

[@aniketnagar7004]

Prove it derivationally

[@RishiKumar-ih8hp]

Torque=d(ang. Momentum) /dt.
So, if torque is 0 then ang. Momentum is constant.
________________________________
Angular momentum=moment of momentum. (Rvector×m(vvector)).
If we differentiate ang momentum with respect to time, (then it will give Rvector×fvector) which is actually torque;so it proves that torque=d(ang momentum) /dt.
________________________________
Ang momentum=Rvector×m(vvector). Vvector=Rvector×omegavector.
Looking in terms of magnitude,
Ang momentum=mR²omega.
mR² is moment of inertia(I), so ang momentum=I.omega.
________________________________
If ang momentum is constant due to torque 0,then I. Omega =constant.Now if if You increase I then angular velocity(omega) will decrease and vice versa.
________________________________Hope it clears all your minutest of doubt.

[@RishiKumar-ih8hp]

Correction_____
Vvector=omegavector×Rvector.
Magnitudinally:V=R.omega.
Ang momentum=Rvector×mRomega
Magnitudinally:mR²omega(sin 90=1).
So, ang momentum=I.omega.

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Bekar

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Thankyou very much

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Thanks sir

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Thank you so much

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Thanks sir