Jamb 2023 Tutorial in Chemistry Electrolysis Class

[@fide_emeka]

Best UA-cam channel to recharge knowledge of chemistry 😂.

[@faithotaru6515]

Nice work 😊😊😊😊😊😊😊

[@victoryabanah8236]

Thank you so much nurse bright, you are indeed a wonderful tutor and i am yet to see any tutor that can be compared to you, i am not just saying it... that's the fact. You are indeed a guru. Thank you for helping me achieve what i couldn't achieve in 3 months under an hour. I pray that boundless opportunities come your way. I am indeed grateful 🙏

[@NurseBright]

Amen✨

[@faithotaru6515]

​@@NurseBrightamen and amen amen and amen amen and

[@virginiainyima8330]

Hmm thank u from the last assignment on the first Faraday electrolysis I gotA(1304.35C)

[@preciousariana7239]

The first practice question answer is option A that is Q= 1304.35C

[@temitopedeborah573]

I wish I had known this man few months ago😮
You're the best teacher 🎉

[@flourishxo5523]

Thanks for the video.... chemistry simplified

[@NurseBright]

Very Correct ❤️💥❤️

[@imaobongjimmy]

You're amazing 🤩

[@Rex_Emperor]

As from questions 3 these are what I got
m=570315/289500=1.97g
m=627120/193000=3.25g
I=28950/7200=4.02A
and lastly, mass of Mercury=25215450/12545000=2.01g
Am about forgetting all this thanks for reminding me.

[@NurseBright]

Very Correct 💥❤️💥
You are welcome ❤️
Keep sharing with Friends

[@DESMMMYYYYYY]

Thank you sir for an imparting class🎉🎉🎉🎉❤❤

[@sanusinazifi7953]

May God reward u abundantly

[@emmanuellaakpa531]

I love this
I learnt a lot
Thank you very much sir

[@NurseBright]

You are welcome ❤️
Keep sharing with others

[@chidiebubemaduabuchi2493]

Love your teaching pattern. I understood everything. I wish you could teach me physics

[@NurseBright]

So Glad you have been impacted by my Video lessons ♥️
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[@diyaazaghloul756]

Amazing video thank you for sharing this information

[@NurseBright]

Glad it was helpful!

[@TreasureIsaac-og3od]

Sir pls how can we arrange this in bracket in our jamb calculator

[@christianifeanyi8578]

Great job sir I understood everything

[@NurseBright]

You are welcome

[@excellentosagie-gw4cz]

Wonderful😁
I'm so glad I can solve questions under the second law of electrolysis 🙌🥳🥳🥳🥳

[@NurseBright]

I am Glad you where impacted greatly with this Video lesson
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[@MelodyChiji-fi5sg]

​@@NurseBright please I can't find the second law of electrolysis in your video 🙏

[@OBINNAENEKWENCHI]

​@@NurseBrightomoooo, this question na number 38 last year jamb

[@baddylawrence]

I watched the first electrolysis video and it explained everything, now after watching this i have become a pro thanks man, I wish you could do some physisc

[@NurseBright]

❤️❤️❤️
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[@OBINNAENEKWENCHI]

My God oo, this question came out exactly last year jamb,

[@AdebayoElizabeth-ek1ke]

IF THIS MAN SHOULD START TEACHING PHYSICS...MY LIFE DON BETTER BTHAT

[@Genas_pet]

I can't find the first video about electrolysis

[@ondomaadoga873]

Answer is 3.25g
Thank you very much for making me a brilliant student just with your understandable teaching

[@Augustinetech]

Its nice.

[@stegenjnr]

Am watching this from the university
Thanks it was helpful

[@OnyekaAzuka-cn7ig]

Well understood
Thanks Nurse bright

[@NurseBright]

♥️♥️

[@VictorMbama-nu4yx]

Thanks u r de best chemistry teacher I ever had😊😊😊😊😊😊

[@NurseBright]

Thanks ❤️
Keep sharing with others

[@Niabari-m5g]

Like,
My teacher doesn't even xplain these formulas
Thanks so much

[@NurseBright]

Happy to help!

[@kingentropy9906]

Gid bless you, please sir I needed tutor on vapor density

[@chiechefulamnmeriwe4132]

Thanks so much. I thought that electrolysis was very hard to solve but now I can solve it. Thank you so much nurse bright, am really happy

[@NurseBright]

I am glad
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[@godswillgarbabusy4508]

Good one sir

[@NurseBright]

Keep watching

[@oghenetegaofuoma9920]

This was so helpful sir😊❤. I love the fact that you speak audibly and your handwriting is legible.

[@NurseBright]

Thanks a lot 😊
Keep sharing with friends

[@AdamAyobami-nb6sv]

1: 1304.35c
2: 3.25g

[@PreciousChukwuemeka-cp9yx]

Please how did u get this number one cause my calculator is giving me another different answer

[@Chidinmarhoda1]

God bless you abundantly

[@shakiruolayinka5612]

Thanks you very much sir I now understand

[@ogiemercy]

Thanks sir
The mass is 32.5g

[@okhideaigbe8976]

One of the best in the world

[@Benzene-y1l]

Thanks OBO of chemistry 🙌

[@NurseBright]

You are welcome

[@ogbaogheneochukomiracle2645]

Q1: 1304.35C (a)✅
Q2: 3.25g✅
Q3: 9.6g✅✊
Thanks for the lectures ✨❤️🙏

[@NurseBright]

You are welcome ❤️

[@NurseBright]

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[@AjayiOmodele-fx6km]

May God bless your knowledge,bros

[@olusegunidowujohnson6758]

Good job

[@NurseBright]

Thanks
Keep sharing with your friends

[@OkaforFavour-dm7xi]

Thank you sir I really appreciate

[@michealpeter9981]

Last question I got 9.6g
Thank you sir ❤

[@NurseBright]

Very correct ❤️💥❤️
You are welcome

[@BunmiUzorka-sd7ej]

Thank you for making me understand

[@NurseBright]

You are welcome ❤️
Keep sharing with friends

[@FunmilayoAgoi]

😅 sir how can I get molar mass of cu2+

[@temitopemarindoti8619]

Atomic mass of copper is 64 generally that is also the mm

[@chinyerenkwuo]

This man too good abeg ❤❤

[@innocentfavour8020]

I love the way you broke down the whole thing but I feel it will be better if you can add questions related to the topics you've taught so we can use them to practice at home probably at the end of every lesson
Thanks and God bless

[@NurseBright]

Noted!

[@ebenezeroluwafemi]

I follow this person to

[@SalimCypher]

Mass of cupper = 4.27g (approx)

[@SusanaMoses-dw1gq]

I got( a) for your first question
And I got 3.25g for the second question
And 9.6g for the 3rd ques

[@Niabari-m5g]

Me too

[@BunmiUzorka-sd7ej]

You are good

[@NurseBright]

❤️❤️

[@GospelUmoh-gt9wt]

Question 1 Answer is (A) Thanks' very much sir

[@chommyloveezeh]

Question 1 _ 1304.34c
Question 2 _3.25g
Question 3 _9.6g
Thanks for the lectures
God bless you ❤

[@NurseBright]

♥️♥️
Amen
You are welcome
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[@GodLike_001]

Thanks it simplified it ❤️✨

[@adukwame-zl4ri]

I love it

[@NurseBright]

Thanks

[@uduakedet693]

Thank you so much sir

[@NurseBright]

You are welcome ❤️

[@OdiliGodstime]

Thank you very much Sir ❤❤

[@ComfortUka]

Thank you very much Sir!

[@EdwardDestiny-zm8oy]

3.249 is the answer to the second question and question 1 is A

[@EmmanuelNwagbara-gt4og]

Thanks for the video.
Pls solve this question on 2020 jamb chemistry
Calculate the quantity of electricity in coulomb's required to liberate 10g of copper from a copper compounds cu is 64,F is 96500Cmol.
Thanks

[@AdewaleAdemola-zx2oj]

Solve it by using : Q= n*q*f

[@OkekeChiamaka-zy6rb]

@@AdewaleAdemola-zx2ojwhat’s f

[@OkekeChiamaka-zy6rb]

@@AdewaleAdemola-zx2ojn is number of moles right?

[@Grace-o3l9p]

The last question i got 2.29 though i approximate it. Your teaching has really been helpful thanks 😊

[@NurseBright]

Great job!

[@DikeIshioma-yk4of]

God bless you very much sir,i really appreciate ❤

[@VictoryAjayi-o9u]

Am so happy for this tutorial 😂😂❤

[@Holybible010]

Thanks Nurse bright
Truly you are brighten up our future ❤
I appreciate❤

[@NurseBright]

You are so welcome

[@chikamazi1618]

3.Mass2=9.45g

[@SAMOKilebi]

Thank you sir

[@uzochiuzochiann]

The answer is A
Love your lectures

[@NurseBright]

Very Correct
You are welcome ♥️💥♥️
Keep sharing with Your Friends

[@dr.aralaxsciencelaboratory5707]

Wow! tutor Bright weldone and thanks for this opportunity.
My answers goes thus
Practice Q 1 : Q=1304.347c
Practice Q 2: M= 324.932
Practice Q 3: Mass of Cu = 9.45g
Please are answers correct ?

[@NurseBright]

❤️❤️

[@AbdullahiAbuayyubNurudeen]

First question
1304.35

[@AbiodunSolaide]

I liked the video i even subscribed to your channel without wasting time
Thanks so much sir🥰

[@RadiyatosheizaAhmed]

Thank you so much sir,is today that I understood this particular topic .am so happy. The answer to the practice question is 9.6g. Please can you teach circle theorem in maths

[@RadiyatosheizaAhmed]

Please sir am very low at physic can you help.

[@M.O.D-zv6ky]

thank you sir and the answer to question 1 you gave us fist is 3.25g

[@cliffordelvis5028]

Please the last one...can you show me how to multiply all
I did
2.7×63.55÷26.9=6.379
Is it correct or am I missing something 🙏🙏

[@anyichiechidalu4284]

Number 2 on the general
324.93g

[@SommarachukwuOrakwelu-r5w]

Sir it's A i.e 1340.35C
Thanks for your teaching sir

[@Ebuskitchens]

Good morning sir, please can you like explain the General electrolysis on how you got 1.97g BCS I have been trying but no way. Thank you 🙏🙏🙏

[@NurseBright]

Input the values into the calculator you will get the value(1.97g) gotten in the video lesson
What you simply have to do is to input the Values in the calculator carefully
Not just Writing it like that in the calculator
When the Write the Numerator(up part) make sure you put it in a parenthesis or bracket ( ) do same for the Denominator (down part)

[@Ebuskitchens]

@@NurseBright thank you

[@UzairuIbrahim-iz4uv]

Sir, I got my answer as 4N 🔥🔥☑️☑️

[@ijeomasmart2143]

God bless you sir🥰

[@miraclesorevaekpe]

In the last question, I got 9.81g .......sir please am I correct?

[@NanjiNnekaAngela]

Second practical:3.24932g

[@MatthewEledu-p1s]

Number 1 question,1304.35

[@idowuolamide6943]

Option A is correct sir(first law of electrolysis

[@andreweaustin]

I couldn't hold my interest anymore since bumping across your classes but to hit the subscribe button.
Thank you very much for the simple explanations ❤❤❤❤

[@NurseBright]

You are welcome ♥️
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[@andreweaustin]

@@NurseBright that's for sure.
I am holding on to your classes for more informative and interesting classes

[@shontan4588]

if the substance deposited is a non metal or an anion with negative charge, what is the q in this instance?

[@prettytopia]

Non metals can't be deposited. Idk about the anion part tho

[@Al-ameenMuhammad-ut1gm]

Please sir, can I directly use formulae in waec theory chemistry.

[@NurseBright]

Yes you can

[@ChiomaIfeanacho]

Thank you

[@mosesolabanji3811]

2nd practice question 3.249g

[@rabzy_gamer1948]

Tnks❤

[@kizzyprince-kw2nm]

Number 2 question -1.62g

[@immaculatejames]

1. A
2. 3.2541g
3. 378g

[@funmipatrick6531]

Q1.
1304.35C

[@NurseBright]

Very Correct

[@jessibliss11]

This is what i also got

[@VictorEmeasoba-wm9sk]

God bless you,so if I use these formula in WAEC they will not fail me

[@prettytopia]

This is for jamb o it might be different.... The point of jamb is to answer 2 questions per minute hence the short solvings

[@JaiyesimiOmowunmi]

For the first question i got 1304.35c

[@Chimamaka-oq1jl]

Pls how do I get the answer of 10 raise to -4

[@SuzannaMoses]

3.25 first exercise

[@favourloveday7507]

The answer to the general question 2 is 324.93g. Sir, am I correct?

[@unknown-zp8pv]

That's what I got but others are getting 1304 how ?

[@thecatholicnextdoor3058]

Sorry, please is the answer ro the very last practice question=9.6g?
Is x=9.6g?

[@Ibironke-l6w]

Questions 2: 325g

[@HMKDCENTRE_ABC123]

Second practice question I got 32.49

[@BlossomOnwordi]

God has helped me through this class ooo

[@favourloveday7507]

Sir, Question 1 the answer is A
1304.35C, am I correct?

[@ComfortUka]

Please Sir, Q3, this is what I got, 627120/193000 = 3.24g or 3.25g approxi., pls is it correct?

[@olatoyejoshuapelumi2059]

How do we get this molar mass cuz some questions don't provide it

[@prettytopia]

Jamb always gives molar mass na

[@DaisyOkpetoritse]

Sir pls do some physics

[@BlissfulBoySRD-dz3kv]

3.24 for the first exercise