Thank you for the very instructive series of videos on this topic. They are all very clear, except in this one, where I can’t see a trick at time 1:50. The entropy is said to be S=f(T,V); and T,V are defined as independent variables. But i can’t have a non-zero result when I apply de/de p|T (I mean de for partial derivative). The only way is to think T and p as functions of (p). So, with the chain rule, i can have the equation: (de S/de p)|T = (de S/de T)(de T/de p)|T + (de S/de V)(de V/de p)|T and then apply the switch of variables, as indicated… Am i wrong? Please, tell me if it turns to be correct. Thank you! Greetings from Italy
Sir what we have to do in this question..........Derive a relation for the change of internal energy when the independent variables T and V of the substance undergo a simultaneous change. Express the result in terms of measurable quantities P, V, T, B, K, Cp and Cv only. Simplify the relation for an ideal gas. ..........plz tell 🙏🙏🙏❤️
ua-cam.com/video/hGMYI9HWY6A/v-deo.html Watch this video on energy equations, and you will get your answer. Derivation is there as well as calculation for ideal is also there.
Thank u sirrrr........ again a great one😊
Welcome..☺️
How does the second equation form dS = (delta S/ delta T ) dT + ( delta S / delta V) dV
Do you have any video related ode & pde conversion?
Thank you for the very instructive series of videos on this topic. They are all very clear, except in this one, where I can’t see a trick at time 1:50.
The entropy is said to be S=f(T,V); and T,V are defined as independent variables. But i can’t have a non-zero result when I apply de/de p|T (I mean de for partial derivative). The only way is to think T and p as functions of (p).
So, with the chain rule, i can have the equation:
(de S/de p)|T = (de S/de T)(de T/de p)|T + (de S/de V)(de V/de p)|T
and then apply the switch of variables, as indicated…
Am i wrong?
Please, tell me if it turns to be correct. Thank you! Greetings from Italy
Sir what we have to do in this question..........Derive a relation for the change of internal energy when the independent variables
T and V of the substance undergo a simultaneous change. Express the result in terms of measurable quantities P, V, T, B, K, Cp and Cv only. Simplify the relation for an ideal gas. ..........plz tell 🙏🙏🙏❤️
ua-cam.com/video/hGMYI9HWY6A/v-deo.html
Watch this video on energy equations, and you will get your answer. Derivation is there as well as calculation for ideal is also there.
A big thx ❤
3:02 , at that point there 2nd Maxwell equation is used instead of 1st☺
Please sir, give me the proved of CP-CV=alpha ²VT/beta
send me a mail on physicslearning2020@gmail.com
I will reply back the proof.
Thanks
Welcome...🙂
💗💗
How to get Cp and Cv formula
But i have Cp =dQ/m dt= t ds /m dt .
Where did m go!!!
The value of m was considered 1.
The value of m was considered 1.