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Ok, i just can't be unsubscribed to the ALGEBROS ;)
At 7:75, you said that if we went from 0 to 2PI, it would be the area of two circles, but wouldn't that be from 0 to 4PI? You did 0 to PI to get just one, but PI to 2PI would just be the bottom half of the polar graph which is just empty right?
Don’t doubt the great mr bean buddy ur cut off
plug in 0 to the equation, you get 0, plug in pi/2, and thats where you get the top point. Plug in pi and youre back to 0.
How do you know what to set r equal to? That's the only thing I'm confused about
ME TOO
it says the value of r in the problem
Ok, i just can't be unsubscribed to the ALGEBROS ;)
At 7:75, you said that if we went from 0 to 2PI, it would be the area of two circles, but wouldn't that be from 0 to 4PI? You did 0 to PI to get just one, but PI to 2PI would just be the bottom half of the polar graph which is just empty right?
Don’t doubt the great mr bean buddy ur cut off
plug in 0 to the equation, you get 0, plug in pi/2, and thats where you get the top point. Plug in pi and youre back to 0.
How do you know what to set r equal to? That's the only thing I'm confused about
ME TOO
it says the value of r in the problem