Continuous Functions

[@loveforkitten2721]

Thank You So Much

[@sounderyavenugopal5287]

Thank you so much sir

[@anujsharma223]

Very helpful

[@akashab1111]

Is, x sin(1/x) bounded?

[@pratapdey1108]

No

[@akashab1111]

@@pratapdey1108 so how does limit as x tends to 0 f(x)= x sin(1/x) exist?

[@holden6059]

Akash Kumar it is bounded, as x tends to infinity, the value of xsin(1/x) tends to 1

[@jeeconceptvideosandsolutio2548]

​@@akashab1111 0* oscillatory fnc = 0

[@GursimarSinghMiglani]

noo