I really appreciate it. I’ve gotten a few comments like that, but as long as some people are finding it useful and interesting then I’m achieving what I set out to do!
Its a blockage issue. You didn't debur the hole and any obstruction you leave affects the calculation. With those small holes a single bur has a large effect.
Interesting video, and completely refresh my mind. Sir I have one question that, if two tanks at different pressure and connected with one pipeline. And there is valve on the pipeline, as soon as we open the valve fluid will start flowing from high pressure to low pressure till it reaches the equilibrium, but how we can calculate the flow rate of the flowing fluid? As we don't know the velocity.
Hi there! Glad you found it interesting. You could only begin to start calculating that kind of thing if you had the dimensions of each tank, the initial levels, the pressure in the vapour space of the tanks, as well as the dimensions/arrangement of the line that interconnects them...
ua-cam.com/video/sUroO7PXm5M/v-deo.html This video shows a more accurate actual result compared to the computed one. I wonder if the die had something to do with the error on your experiment.
I think it's because the hole in that video is on the curved side of the bottle compared to the flat bottom of Pat's video. The hole in the side of the bottle effectively has two sides with rounded edges making the discharge coefficient closer to ~1.0 whereas Pat calculated ~0.61 for the hole on the flat bottom. So that guy's results are closer to his formula even though he left out the discharge coefficient.
Intresting
This is a must see video for every aspiring engineer.
Superbly done. Superbly explained.
Thanks Buddy.
Thanks Pat, love your work. I was busy typing " you missed coefficient of discharge" when I looked up at your video again and there its was :-)
man you r awesome still can't believe you only have 1000 subscribers you are high tier UA-cam man seep the hard work
I really appreciate it. I’ve gotten a few comments like that, but as long as some people are finding it useful and interesting then I’m achieving what I set out to do!
This is genius. Wish that such concept be taught at university. More videos please.
excellent work!
Its a blockage issue. You didn't debur the hole and any obstruction you leave affects the calculation. With those small holes a single bur has a large effect.
Nice video. We could see the cat trying to grab attention
Interesting video, and completely refresh my mind. Sir I have one question that, if two tanks at different pressure and connected with one pipeline. And there is valve on the pipeline, as soon as we open the valve fluid will start flowing from high pressure to low pressure till it reaches the equilibrium, but how we can calculate the flow rate of the flowing fluid? As we don't know the velocity.
Hi there! Glad you found it interesting. You could only begin to start calculating that kind of thing if you had the dimensions of each tank, the initial levels, the pressure in the vapour space of the tanks, as well as the dimensions/arrangement of the line that interconnects them...
@@ProcesswithPat thank you sir.
Finnegal's elasticity coefficient = the value applied to a theoretical answer to get it equal the answer you want...
ua-cam.com/video/sUroO7PXm5M/v-deo.html This video shows a more accurate actual result compared to the computed one. I wonder if the die had something to do with the error on your experiment.
I think it's because the hole in that video is on the curved side of the bottle compared to the flat bottom of Pat's video. The hole in the side of the bottle effectively has two sides with rounded edges making the discharge coefficient closer to ~1.0 whereas Pat calculated ~0.61 for the hole on the flat bottom. So that guy's results are closer to his formula even though he left out the discharge coefficient.