Olympiad Mathmatics | A Beautiful Radical Expression | Find the Value of x = ?

[@RealQinnMalloryu4]

(x)^2 ➖(6)^2={x^2 ➖ 36}={x^0+x^0 ➖ x^0+x^0 ➖ }={x^1+x^1}=x^2 (x ➖ 2x+2) .(x)^2 ➖ (6)^2={x^2 ➖ 36}={x^0+x^0 ➖ x^0+x^0 ➖ }={x^1+x^1}=x^2 (x ➖ 2x+2).