How does he take something so complex and make it so simple to understand? Absolutely amazing that Dr. Bazett is able to convey so easily in a few minutes what many professors can't in hours of lecture
Great "straight-forwardness" for picturing multivariable limits and great ending questions! I'm teaching multivariable calculus in the Winter and am using these as a refresher for myself. I've already seen some ways of presenting things that I'm going to use to improve my course. 👍
perhaps it would be best if some teachers could swallow their pride and instead just send a link to your videos :) well done, i'm starting to get this now at least from a conceptual viewpoint. thank you so much!
I showed my professor (who is a great professor) his videos and told him that I use his videos to understand everything more conceptually, and he shared his channel with our entire class and linked them in our resources for the program we use.
Your videos are great. If you could put some translations, it would help many many more students. If you think about that, remember Portuguese, please. I want to recommend your videos to my friends, but they don't understand English. Just a suggestion.
How does one choose which path to choose to test for continuity, anyways, maybe I choose a bunch of different paths and get the same function value for all of them (get result that limit exists for that function), but still there maybe paths where it may be different, here I do not know what I don't know. It's a bit ambiguous
How many of the same limit results do you need in order to conclude that the limit exists. For example taking the 2 paths allong the x axis and the y axis is not enough right?
Even a million paths wouldn't be enough. That's why we have to either use some proven algebraic rules or prove it from the limit definitions directly. It's not easy!
Sir, why we can't prove it by y=mx, if limit is free from m. Please sir make video on this topic. I am going to die for this question.sir please, please,
Great content! Just a quick question, how do you prove that the limit does in fact exist? Because failing to prove that the limit does not exist does not mean that the limit exists, how would you go about proving it if plugging in values of x and y results in 0/0 or something along those lines?
i don't know answer to this question in multivariable calculus world. but in calculus 1 in university we thought to prove limits and it was only acceptable answer and just calculating wasn't acceptable. the way it work was as following: by considering any value for instance _a_ we should show that there is a value such as _b_ where: f(x⁰+b) < a ultimately the job was to find a function to find _b_ based on _a_ and showing for every _a_ there is can be a _b_ founded. it was really hard to understand and solve problems in this way.
i know that using direct substitution resulting in 0/0 means you need a different approach, e.g. manipulating the function by e.g. factoring things out, L'hopital or you could try to look at the limit of the function along the line y = ax where a is just any constant in R and y = ax^2. Usually these two are enough to show that the limit does or does not exist. There is a more accurate proof for this (i think it is called the epsilon delta proof) but I'm quite unfamiliar with it. Another way is to use the intermediate value theorem and setting one variable to be greater or equal to another (this is is most commonly used when the limit of the variable goes to 0 so we can compare the two limits).
This type of limit IS weird! It makes sense, though, since this particular limit is of the form 0/0. It can have multiple values and is thus indeterminate.
Dr. Bazett, there are tricky equations with tricky points that don't have a normal vector, even if they seem smooth and well behaved. For instance, consider z=(x^3-3xy^2)/(x^2+y^2). It is easy to see that z=0 at (0, 0) , since every limit converges to that value. It is also differentiable at that point. But it has three-fold symmetry around that point, so no plane fits as tangent. How should that point be treated? In particular, normal vectors define in optics how light reflects off a mirror. If a mirror was made with that shape, how would light be reflected at that point?
let's consider this function f(x,y)=x*y/((x-1)^2+y^2) and (x,y) approach to (1,0) then what path can we take? Can we still take y = x or should we take for example y= x -1?
The best way maybe average contrast of each dimension will intersect at centroid then use that as objective reduce the computation in computer time because it expensive
Trefor, I think path can't be curvature that is not continuous (because that would cause problems for h --> 0), but I am not sure. Also, if curvature is differentiable, then (for h --> 0) we can aproximate it by some streight line and that we can easly solve. So, does curvature (path) must be continuous and/or differentiable? Thanks
Sir, is there a condition that the curve along which we approach should be smooth? Because otherwise there can be many path along which any limit would not exist
Sir, please make a video on last two questions. Sir please😭😭😢😥😭😭😭. Sir, if limit is same with all paths along the line, would it be same along any curvy path.
What is the difference between the limit and the continuity definition? One could say in the continuity definition we add the last term L(left)=L(right)="F(xo)"and in the limit definition we dont use the last term thats the only thing and thats wrong thats why if we are asked about this exact example about continuity at the origin the question has no sense at all. And what about if we are asked about the continuity in general of f=xy/(x^2+y^2) of course it is!!!
My thought was that if you approach the limit with all combinations of straight line paths and they all converge to the same value then approaching along a curved path would also yield the same value and the limit would exist. May be there is more to it though.
How does he take something so complex and make it so simple to understand? Absolutely amazing that Dr. Bazett is able to convey so easily in a few minutes what many professors can't in hours of lecture
On god
Accidentally coming across this video just a night before my Calc3 midterm was the best thing that could happen. Cheers!
same in calc2 haha. How did your's went 2 years ago?😂
Great "straight-forwardness" for picturing multivariable limits and great ending questions! I'm teaching multivariable calculus in the Winter and am using these as a refresher for myself. I've already seen some ways of presenting things that I'm going to use to improve my course. 👍
the animation really helped me understand, thank you!!!
Thanks a lot Dr. Bazett! The graph really helped me understand intuitively.
Glad it was helpful!
@@DrTrefor U deserve alot in heaven Dr .
I used this for my midterms and I am back to it for my finals, and it is just as helpful each time (-:
Good luck!
@@DrTrefor Thank you!
I literally have your line integrals video on right now!!
in which video we're gonna answer to the those questions?
thank you so much
perhaps it would be best if some teachers could swallow their pride and instead just send a link to your videos :)
well done, i'm starting to get this now at least from a conceptual viewpoint. thank you so much!
I showed my professor (who is a great professor) his videos and told him that I use his videos to understand everything more conceptually, and he shared his channel with our entire class and linked them in our resources for the program we use.
Failed out of Calculus 3 yesterday. I'll be here for the next 4 months preparing it to retake it next fall.
damn, that sucks! Welp, good luck in the fall, I'm sure you can do really well next time:)
Thank you so much, I understand why multivariable limit is theta independent now.
Thank you!! Explaining it with a actual 3-D graph helps a lot!
You're very welcome!
Could you add the subtitles, please? You're a great teacher
Your videos are great. If you could put some translations, it would help many many more students. If you think about that, remember Portuguese, please. I want to recommend your videos to my friends, but they don't understand English. Just a suggestion.
Rotational effect on the graph will be more helpful for better understanding
Vamos de aprender calculo and english together, salve teacher leandro.... tudo our meu king
How does one choose which path to choose to test for continuity, anyways, maybe I choose a bunch of different paths and get the same function value for all of them (get result that limit exists for that function), but still there maybe paths where it may be different, here I do not know what I don't know.
It's a bit ambiguous
This video opened my eyes :OOOOOOO
How many of the same limit results do you need in order to conclude that the limit exists. For example taking the 2 paths allong the x axis and the y axis is not enough right?
Even a million paths wouldn't be enough. That's why we have to either use some proven algebraic rules or prove it from the limit definitions directly. It's not easy!
we learned this topic today , the way we chose was to use squezee theorem
Sir, why we can't prove it by y=mx, if limit is free from m. Please sir make video on this topic. I am going to die for this question.sir please, please,
Sir, absyln delta definition of limit??
Great content! Just a quick question, how do you prove that the limit does in fact exist? Because failing to prove that the limit does not exist does not mean that the limit exists, how would you go about proving it if plugging in values of x and y results in 0/0 or something along those lines?
i don't know answer to this question in multivariable calculus world. but in calculus 1 in university we thought to prove limits and it was only acceptable answer and just calculating wasn't acceptable. the way it work was as following:
by considering any value for instance _a_ we should show that there is a value such as _b_ where:
f(x⁰+b) < a
ultimately the job was to find a function to find _b_ based on _a_ and showing for every _a_ there is can be a _b_ founded. it was really hard to understand and solve problems in this way.
i know that using direct substitution resulting in 0/0 means you need a different approach, e.g. manipulating the function by e.g. factoring things out, L'hopital or you could try to look at the limit of the function along the line y = ax where a is just any constant in R and y = ax^2. Usually these two are enough to show that the limit does or does not exist. There is a more accurate proof for this (i think it is called the epsilon delta proof) but I'm quite unfamiliar with it. Another way is to use the intermediate value theorem and setting one variable to be greater or equal to another (this is is most commonly used when the limit of the variable goes to 0 so we can compare the two limits).
This type of limit IS weird! It makes sense, though, since this particular limit is of the form 0/0. It can have multiple values and is thus indeterminate.
Great lecture with incredible effort, thanks
Dr. Bazett, there are tricky equations with tricky points that don't have a normal vector, even if they seem smooth and well behaved. For instance, consider z=(x^3-3xy^2)/(x^2+y^2). It is easy to see that z=0 at (0, 0) , since every limit converges to that value. It is also differentiable at that point. But it has three-fold symmetry around that point, so no plane fits as tangent. How should that point be treated? In particular, normal vectors define in optics how light reflects off a mirror. If a mirror was made with that shape, how would light be reflected at that point?
You are excellent at explaining!
let's consider this function f(x,y)=x*y/((x-1)^2+y^2) and (x,y) approach to (1,0) then what path can we take? Can we still take y = x or should we take for example y= x -1?
Just found your channel.
Very nice videos and explanations!
Thank you
no permutation or combination of 26 alphabets can define how good you teach , I'm not jokin it was actually too good
this idea of restriction is just cool
Please postprocess audio to remove this empty room echo effect. Beside this your content is great :)
The best way maybe average contrast of each dimension will intersect at centroid then use that as objective reduce the computation in computer time because it expensive
wow !! very good graphics and explanation
how can someone dislike that 😂
Guardian angel professor ❤
Trefor, I think path can't be curvature that is not continuous (because that would cause problems for h --> 0), but I am not sure. Also, if curvature is differentiable, then (for h --> 0) we can aproximate it by some streight line and that we can easly solve. So, does curvature (path) must be continuous and/or differentiable? Thanks
Thank you sir 🔥
Thank you teacher. 🎉
what are the answers to those questions at the end?
Sir, is there a condition that the curve along which we approach should be smooth? Because otherwise there can be many path along which any limit would not exist
That's true about other instruments, to an extent.
Can someone plz explain why the 0,0 of y and x arent a same point ?
Very nice video ❤
loved the video 👍👍👍👍👍
Sir, please make a video on last two questions. Sir please😭😭😢😥😭😭😭.
Sir, if limit is same with all paths along the line, would it be same along any curvy path.
great stuff.
Great explanation
Glad you think so!
Sir, how can we contact with you.
What is the difference between the limit and the continuity definition? One could say in the continuity definition we add the last term L(left)=L(right)="F(xo)"and in the limit definition we dont use the last term thats the only thing and thats wrong thats why if we are asked about this exact example about continuity at the origin the question has no sense at all. And what about if we are asked about the continuity in general of
f=xy/(x^2+y^2) of course it is!!!
What software are you using for the 3D graphs?
Matlab
tbh, i came to find answers to the questions myself.
Anyways, thanks.
I wondered about Question 2; my intuition says that, yes, a limit would exist if the approach on every straight line yields the same result.
My thought was that if you approach the limit with all combinations of straight line paths and they all converge to the same value then approaching along a curved path would also yield the same value and the limit would exist. May be there is more to it though.
That is green theory was introduced but I called it là grange theory
wow it's math pewdiepie. damn he explains stuff so well...
so you can make y = any type of 'x' ??
Another time unbelievable content
However at 2min54 if you plug y=-x the denominator will not be wero ?
so the limits kinda like a volume/ area
New sub here!
1:15
who are these 5 people? :)
I just love your videos. Is there a way to take you out on a date ? 💓
4:15
multivariable function... such a hypocrite!!!
He’s hot I can’t focus
XnotYas i cant stop staring at his beard
SCAM VIDEO!!!
Go on…