Complex numbers as matrices | Representation theory episode 1

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  • Опубліковано 7 січ 2025

КОМЕНТАРІ • 69

  • @jarahfluxman20
    @jarahfluxman20 3 місяці тому +41

    The reason complex conjugation corresponds to transposition in the matrix rep is because the inner product :=z* w on the complex plane is mapped to the standard dot product on R^2, and complex conjugation on C and transposition on R^2 both represent the hermitian adjoint.

    • @AllAnglesMath
      @AllAnglesMath  3 місяці тому +11

      That's such a cool connection! I have been thinking about making a video about adjoints for a while, but I haven't gotten around to it yet.

    • @superuser8636
      @superuser8636 2 місяці тому +2

      Shout out to all my hermitians

  • @pedroth3
    @pedroth3 3 місяці тому +43

    I have always known that complex numbers could be represented as matrices, but never stopped to think about their application to matrix theory, Perfect video

  • @DandapaniTripaathi
    @DandapaniTripaathi 28 днів тому +2

    Just helped me in my group theory course, thank you

  • @pecugihan
    @pecugihan 12 днів тому +1

    I know there's something connection in complex number and vector, it really similar, like the notation (a+bi and ai+bj), how it work etc, that connection is ✨matrices✨
    tysm for making this video

  • @johnstuder847
    @johnstuder847 3 місяці тому +9

    Wow - thank you!
    So glad there are people like you that understand this stuff well enough to combine seemingly disparate concepts and provide a high level summary without the details and rigor that obscure many of the important concepts. Well done! I kept hoping you would work my favorite subject in there - how the Fourier transform, SVD, (singular value decomposition), tensors, and Roots of Unity are related. Keep up the great work! Love your channel.

    • @BlueDog15391
      @BlueDog15391 3 місяці тому +2

      Sounds cool, where would you recommend reading about the connection between Fourier transform and SVD for those who are impatient?

    • @AllAnglesMath
      @AllAnglesMath  3 місяці тому +2

      I can see the connection between Fourier and roots of unity, but where do tensors and the SVD come in? If you have a good reference where I can learn more, I will definitely consider making a video about that.
      Right now, you might be interested in a video we have on Patreon that looks at Fourier analysis as the study of the characters of a circle.

  • @maxwellmogadam399
    @maxwellmogadam399 3 місяці тому +7

    this is my personal favorite subject, a fun exercise is to think about complex valued matrices, for example try looking at a pauli matrices as a set of nested matrices

  • @AlanCanon2222
    @AlanCanon2222 3 місяці тому +4

    I learned about complex numbers while programming a Mandelbrot set generator in Pascal on my parents' PC, based on an algorithm published in Scientific American. I remember getting pretty deep into complex numbers, and proving what I later knew to be famous basic theorems. Namely, if an equation is true among complex numbers, then it is also true among their complex conjugates; and that if you multiply two complex numbers represented as vectors, the rotation of the product is the sum of the rotations of the factors, and the length of the product is the product of the lengths. Of course now I know my way around the complex plane in terms of r* e ^ (i * theta), which makes these facts self evident, but I remember proving them just using algebra.

    • @AllAnglesMath
      @AllAnglesMath  3 місяці тому +3

      That's pretty cool! When you proved that second theorem, especially the part where the angle of the product is the sum of the angles, did you realize that you had discovered an exponential relation?

  • @finite1731
    @finite1731 3 місяці тому +14

    This is bascially the reason why z* doesnt have a derivative since the jacobean of the transformation is a reflection and not a rotation and scalling (the only transformations possible when multiplying by a complex number) which is effectively the reasoning behind the Cauchy-Riemann equations, it took me ages to understand the link between the linear transformation due to complex multiplication and the restricted set of matricies which describe complex multiplication which the jacobean must be in, since it too must reprosent complex multiplication thus must be of this form thus the CR equ.'s. (whenever I found the jacobean, I assumed that that must mean a derivavtive must exist, but no)

    • @finite1731
      @finite1731 3 місяці тому +3

      You video made this idea very clear, well done

  • @mjkhoi6961
    @mjkhoi6961 3 місяці тому +2

    I always wondered why the "i" matrix had the negative sign in the top left instead of the bottom right, this explains it perfectly

  • @mrervinnemeth
    @mrervinnemeth 3 місяці тому +19

    Fun fact: i is an anti-symmetric matrix here. You can decompose every square matrix to the sum of a symmetric and an anti-symmetric component every time: ½(A + Aᵀ) is the symmetric and ½(A - Aᵀ) is the anti-symmetric component, where Aᵀ is the transposed matrix. This doesn't add up entirely because a symmetric matrix is not necessarily a multiple of the identity matrix, but it still looks like decomposing a complex number to a real and an imaginary component. Stupid me, I had to correct the formulas.

  • @dan0_0nad76
    @dan0_0nad76 3 місяці тому +9

    Bro i swear i love you

    • @dan0_0nad76
      @dan0_0nad76 3 місяці тому +6

      Just failed an exam and got so frustrated that i almost felt like i should not be doing math ever again.
      Your intuitive explanations really keeps me motivated

    • @AllAnglesMath
      @AllAnglesMath  3 місяці тому +5

      @@dan0_0nad76 Sorry to hear that you had a bad time with an exam. It happens to the best of us. I hope you'll be able to keep doing what you love.

  • @SkielCast
    @SkielCast 3 місяці тому +4

    This series looks really promising! It's great!
    I would suggest to speed up a little bit the narrative, I had to listen it at 1.5 to keep me engaged

  • @mrervinnemeth
    @mrervinnemeth 3 місяці тому +13

    Geometric algebra gives you a hint how to do this properly. Let's go to G(2,0), the two-dimensional space. Your i matrix is simply a transformation, and it's a bivector in GA, and a pseudoscalar in this space. We have the x axis and the y axis, but y can be written simply as y = i x. From now on we can describe every point on the plane with a x + b i x. This gives an algebra entirely isomorphic to the complex numbers. Or we can choose G(0,1), which is much simpler, and still isomorphic to complex numbers.

    • @AllAnglesMath
      @AllAnglesMath  3 місяці тому +7

      As it happens, I'm preparing the series on GA right now. And you've hit the nail on the head. We will publish 2 videos about this later. Also, G(0,1) is trivially isomorphic to C, but I prefer the way they emerge from G(2,0) because it's much more surprising. You define 2 elements that square to 1, and magically you get a new element that squares to -1. Math is full of such surprises.

    • @mrervinnemeth
      @mrervinnemeth 3 місяці тому +4

      @@AllAnglesMath Sorry for the spoiler :)

  • @eqwerewrqwerqre
    @eqwerewrqwerqre 3 місяці тому +7

    Wow, this is amazing. I've got go watch all your videos real quick.

    • @AllAnglesMath
      @AllAnglesMath  3 місяці тому +3

      Feel free to ask questions in the comments if needed.

  • @FaTeAnimationVault
    @FaTeAnimationVault 3 місяці тому +4

    In computational physics this is a very, very useful tool.

  • @mariotabali2603
    @mariotabali2603 3 місяці тому +3

    This is rather good so far

  • @rylieweaver1516
    @rylieweaver1516 3 місяці тому +3

    All angles never disappoints 🙌🏻

    • @AllAnglesMath
      @AllAnglesMath  3 місяці тому

      Thanks for having so much faith in our channel.

  • @peskarr
    @peskarr 3 місяці тому +10

    heavily underrated content, instant subscription

    • @TurboLoveTrain
      @TurboLoveTrain 3 місяці тому

      This should be taught day one of any linear equations curriculum.

  • @markhamann8030
    @markhamann8030 3 місяці тому +3

    This is great. I've been trying to understand capacitance and inductance without resorting to to the square root of -1, which makes the math work but is far from intuitive. This is taking me into a good direction.

    • @AllAnglesMath
      @AllAnglesMath  3 місяці тому

      You can often replace complex numbers by something else (such as matrices or 2D vectors). The math still works, but it's often more verbose. You no longer package the 2 parts into a single number, which leads to twice as many equations. By packaging those back into vectors/matrices, you may be able to recover the original elegance.

    • @markhamann8030
      @markhamann8030 3 місяці тому

      @@AllAnglesMath Yes. The thing I like about representing impedance as [[R, Z][-Z R] is that it's 2 vectors: the top one being the impedance, and the bottom one being a vector with the same magnitude but rotated exactly 90 deg counter-clockwise. So you do V*[[cos t, sin t] [-sin t, cos t]] = [[R, Z][-Z, R] * I*[[cos t, sin t] [-sin t, cos t]] .
      This shows exactly how the real and reactive elements turn real and 90 deg out of phase currents into real and out of phase voltages while reactive elements turn real and out of phase currents into out of phase and real voltages. It's all quite intuitive when you do it this way.
      It doesn't depend on an understanding that multiplying by i means rotation.

  • @apuji7555
    @apuji7555 3 місяці тому +5

    This is super interesting!

  • @MathsSciencePhilosophy
    @MathsSciencePhilosophy 3 місяці тому +6

    Nice idea to write i as a matrix ⭐❣️

  • @sleepysnekk
    @sleepysnekk 3 місяці тому +12

    honey wake up new allangles series 🗣️🗣️🔥🔥

  • @OmarAhmed-ic4fw
    @OmarAhmed-ic4fw 3 місяці тому +1

    What an Amazing video I hoped not to end!!

    • @AllAnglesMath
      @AllAnglesMath  3 місяці тому

      Thank you! Sorry that it had to end 🤷

    • @OmarAhmed-ic4fw
      @OmarAhmed-ic4fw 3 місяці тому

      @@AllAnglesMath It would be great to see another video in this series soon!

  • @MrRyanroberson1
    @MrRyanroberson1 2 дні тому +1

    somewhere between complex numbers and GL(2) is the subset of GL(2) with positive determinants, since that one must be closed under multiplication as well.

    • @AllAnglesMath
      @AllAnglesMath  2 дні тому

      True, but be careful: the determinant has to be strictly positive. Zero is not allowed (because matrices with zero determinant have no inverse).

  • @nishchayy
    @nishchayy 3 місяці тому +3

    Great work great video. Thank you

  • @blue5659
    @blue5659 3 місяці тому +3

    Is it possible to represent signed numbers in terms of just unsigned numbers in vector form?

    • @AllAnglesMath
      @AllAnglesMath  3 місяці тому

      I'm not sure. I like this question though, it makes me think.

  • @brofessorsbooks3352
    @brofessorsbooks3352 3 місяці тому +3

    Amazing keep it up!!

  • @woomygfx
    @woomygfx 2 місяці тому +1

    these matrix representations reminds me a lot about functors, could there maybe be a correlation or could be that I'm just confusing things...?

    • @AllAnglesMath
      @AllAnglesMath  2 місяці тому +1

      Every matrix representation is a homomorphism; and those in turn are studied as the "arrows" in category theory. Functors are an arrow between such arrows. The condition for functors is indeed very similar to the conditions you see for many other kinds of arrows such as isomorphisms, linear transformations, or diffeomorphisms.

  • @friedrichfreigeist3292
    @friedrichfreigeist3292 3 місяці тому +1

    Please note that i, sin and cos are not variables. This is why one should not write them cursive.
    This topic is so based. I had a lot of representation matrices stuff in a group theory course.

  • @MaxPicAxe
    @MaxPicAxe 3 місяці тому +3

    Wow that's awesome

  • @05degrees
    @05degrees 3 місяці тому +6

    Ah, among other stuff this introduction reminds me how I derived quaternion matrices by myself, not without errors at first.

    • @AllAnglesMath
      @AllAnglesMath  3 місяці тому +3

      Nothing ever happens without errors at first 😉

  • @harryh5666
    @harryh5666 20 днів тому

    6:46 really.. how?
    Lets say we want to make an angle of (1/7)*2π out of the available angles:
    (1/3)*2π , (1/4)*2π , (1/5)*2π
    So we want to find integers x,y,z such that [0]:
    (1/7)*2π = (1/3)*2πx + (1/4)*2πy + (1/5)*2πz
    Cancelling 2π gives [1]:
    (1/7) = (1/3)x + (1/4)y + (1/5)z
    Cancelling the common denominator of 3*4*5*7=420 gives [2]:
    (3*4*5) = (4*5*7)x + (3*5*7)y + (3*4*7)z
    Reducing modulo 7 gives [3]:
    60 ≡ 0 (mod 7)
    ⇒ 4 ≡ 0 (mod 7)
    [3] is clearly not true.
    The equation [1] also fails because (via congruence relations) it implies [4]:
    x=3a , y=4b , z=5c for integers a,b,c
    ⇒ 1 = 7a + 7b + 7c
    ⇒ 1/7 = a + b + c
    [4] is clearly not true.
    The group of integers under addition is closed (otherwise it wouldnt be a group).
    If x,y,z are allowed to be rational numbers then [1] has an infinte number of rational solutins.
    But how is this fundamentally different from taking all rational roots of unity on the unit circle to begin with.

  • @pecugihan
    @pecugihan 12 днів тому +1

    16:06 I laughed in this one, ofc it's not wrong cuz it still 1x1 matrices but idk it just funny 😭😭

  • @manfredbogner9799
    @manfredbogner9799 3 місяці тому +3

    Sehr gut

  • @peterfireflylund
    @peterfireflylund 3 місяці тому +1

    What is “number samba”?

    • @AllAnglesMath
      @AllAnglesMath  3 місяці тому

      That's just the phrase I use for the product between two matrices, or between a matrix and a vector. I adopted this phrase half jokingly in the series on linear algebra.

    • @peterfireflylund
      @peterfireflylund 3 місяці тому +1

      @@AllAnglesMath oh. I hoped I heard misheard something less like a secret club handshake/wink.

  • @vishnuvudhisen1874
    @vishnuvudhisen1874 3 місяці тому +1

    Eigen value =i?

  • @TurboLoveTrain
    @TurboLoveTrain 3 місяці тому

    The little hole you punched in the middle is why phi doesn't start at zero.

  • @anamariatiradogonzalez
    @anamariatiradogonzalez 3 місяці тому

    Que ne lo paguen que estiy jasta el cñ moño de abajo😊

  • @hyperduality2838
    @hyperduality2838 3 місяці тому

    Real is dual to imaginary -- complex numbers are dual.
    "Always two there are" -- Yoda.

  • @omipial2084
    @omipial2084 Місяць тому

    1:11-;6:46-6:56;8:10-8:22;9:03-9:15;