No. By using xy/z we get the same ans. Plz check it once again.. But I'm taking interior of the cell 0,1,2,... 7.. Not using 2-001, 3-, 4- , 5-, this like.. When I'm using my first step that is 0,1,2,.. 7..... I can't get the ans at x/yz..
ma'am when i solve this using boolean expression m2,m3,m4,m5 then answer is [x(bar) y z(bar)], [x(bar) y z], [x y(bar) z(bar)],[ x y(bar) z] so is it wrong??? please reply ma'am
No you are not wrong If u take x(bar)y common from first two terms and xy(bar) common from next two terms you will get the answer U have to reduce it using Boolean laws
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Nice teaching
Your teaching way is very good 👍👌
exellent explaination mam...thanks to u and ur channel..helped much ..sugesting my friends
Very clear teaching, Thank you
so sweet voice...i think i may top in this subject coz of u
Well understood ma'am ❤👍 thank you so much 🙏
Thank you for the explanation Ma'am. Can u pls solve the same qn without k-Map .
thank you for your times Mam!!
Ma'am interchange the X y. Z answer is different maam
No
Akka super teaching
If we take xy/z then we dont get the ans plz explain why
No. By using xy/z we get the same ans. Plz check it once again.. But I'm taking interior of the cell 0,1,2,... 7.. Not using 2-001, 3-, 4- , 5-, this like.. When I'm using my first step that is 0,1,2,.. 7..... I can't get the ans at x/yz..
Thank you once again mam👍👍👍
Corner grouping was also possible?
thank you mam from bangladesh🇧🇩
Nice class...
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Nice mam
Nice 👍👍👍
ma'am when i solve this using boolean expression m2,m3,m4,m5 then answer is
[x(bar) y z(bar)], [x(bar) y z], [x y(bar) z(bar)],[ x y(bar) z] so is it wrong??? please reply ma'am
Yes wrong
No you are not wrong
If u take x(bar)y common from first two terms and xy(bar) common from next two terms you will get the answer
U have to reduce it using Boolean laws
Like you mam so much
Can you pls explain maam