Linear Programming 3: Graphical Solution - with negative coefficients

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  • Опубліковано 23 жов 2024

КОМЕНТАРІ • 51

  • @katherinebalka200
    @katherinebalka200 8 років тому +14

    You have a wonderful voice and your videos are so well made and good at explaining the solution! Thanks for the help!!!

  • @kathleenferguson407
    @kathleenferguson407 7 років тому +3

    Very clearly and thoroughly explained. You make it seem quite easy. Thank you.

  • @EldoNorte
    @EldoNorte 3 роки тому +1

    For finding the straight line axis values A and B, one can also transform their equation in the form (X/A) + (Y/B) = 1

  • @bisikoobee
    @bisikoobee 6 років тому +1

    Thanks so much for very good explanation. You've helped me to prepare for a midterm. My God will continue to strengthen you and help you in all your endeavours.

  • @thajisajir
    @thajisajir 5 місяців тому +1

    Thank you Sir. You helped to solve my homework.

    • @joshemman
      @joshemman  5 місяців тому

      You're welcome, Vivid.

  • @chinsvlogs
    @chinsvlogs 7 років тому +5

    best explanation ever!! thank yoU!

  • @mohammadhassan8654
    @mohammadhassan8654 8 років тому

    thanx too much ..I hope that you can also be described the simplex method...in the same charming and understanding way

  • @SanjayGupta-zf4vc
    @SanjayGupta-zf4vc 7 років тому +1

    Thnk u so much for explanation in detail....

  • @gtubekr
    @gtubekr 5 років тому

    Thank you so much !!!!!! (From South Korea)

  • @programmingintellects3856
    @programmingintellects3856 7 років тому

    you helped me in my exams ... soo thankful to u

  • @arifnoman2492
    @arifnoman2492 7 років тому +1

    well explained..thank you so much
    sir explain simplex method. plz

  • @ronunkwor
    @ronunkwor Рік тому

    Thank you so much

  • @ejirogift6523
    @ejirogift6523 5 років тому

    thanks a lot for this video..... it has been really helpful... i just have a little challenge. i came across a question to formulate a linear programming problem with a maximization objective. let the model have 5 constraints with the first and third constraints having 7 unknowns. at least one of the constraints should be left with 3 unidentified resources combination, but the second and fifth constraints should have 5 resource mix each. please how do i go about this?

  • @itsdannyftw
    @itsdannyftw 8 років тому +1

    3:02: "are less than constraints and are satisfied in the direction of the origin".
    Is it just a coincidence that this worked for the *negative* coefficient constraint -3X +6Y

    • @joshemman
      @joshemman  8 років тому

      +itsdannyftw
      You are right. I should have shown how. I was trying to cut down the video length as much as possible. It is always better to test. But I guessed I simply applied one of the rules I suggested against; "if the negative sign is only on the x coefficient, then treat the situation as normal. If it is only on the y coefficient, go the other direction." The example you gave "-3x + 2y ≤ -4" is the same as "3x - 2y ≥ 4".
      I guess I shouldn't be saying "toward the origin". I actually didn't mean it as a rule; I was only trying to describe the direction.
      Thanks for bringing this up. It'll help clean up my act a little bit.

    • @itsdannyftw
      @itsdannyftw 8 років тому

      +Joshua Emmanuel
      Thanks for clarifying. Also, could you refer me to the video where you stated those rules? I don't recall you mentioning them in any of the LP series videos. In addition, I suppose those rules can get a little messy, i.e. do they only apply when the equations are in standard form, and not when in slope-intercept form? And like in the example I gave, when or how would we know which is the appropriate equation we should be using? i.e. even though "-3x + 2y ≤ -4" is the same as "3x - 2y ≥ 4", why is it that we need to make this distinction (or put another way, 'convert' it to another equivalent equation/form)? I don't understand; is it simply to be able to apply the "rules" and thus to determine which direction to shade?
      Actually I think I misunderstood the rule, I thought we were looking at the negative signs on only either of the two coefficients, but rather I think the rule suggests to have only one negative sign on the entire equation? i.e. in this case, although there is only one negative sign on the x coefficient, thus, we should 'treat the situation as normal', we need to notice that there is also a negative sign on the '4', hence why you multiplied the equation by -1, in order to be able to 'conform' to the rule requirements which enables you to apply the rule?
      Evidently, if so, having these 'rules' does make the process more complicated than it actually is. And rather, it seems to be always best to test points, like you have mentioned previously. Or have I misunderstood and to be efficient at solving these problems, you really ought to just persevere in applying those rules?
      Thanks again.

    • @joshemman
      @joshemman  8 років тому +1

      I actually never mentioned those rules in any of my videos. And yes, rewriting the the constraint is simply an attempt to fit it to one of the modes the rules apply to.
      My Verdict: Testing points is the best way to go.

    • @itsdannyftw
      @itsdannyftw 8 років тому

      +Joshua Emmanuel Excellent, thank you. May I ask how did you arrive at that rule you quoted then? Is it just from experience?
      Out of experimentation, I attempted to try it out on this constraint equation:
      3x - 2y ≤ 4
      which ultimately gets shaded to the left (or 'above') the line.
      However applying what you stated earlier that, "if [the negative sign] is only on the y coefficient, go the other direction." If that rule were to be applied here, wouldn't we be shading to the right or 'below' the line (since that is the 'other direction' for a less than or equal to constraint)? Is this a scenario where I have incorrectly applied the rule or it's a scenario where I have encountered an exception to the rule (and thus again, clearly elucidates why you don't advocate the use of these 'rules')? I assume the former, and hope you could clarify.

    • @joshemman
      @joshemman  8 років тому +1

      Yeah, the rules come by observation.
      "Above the line" is the "other direction" for a ≤ constraint by the way. And, did I say forget the rules?
      What you call "above" sometimes may actually be "below", depending on the objective.
      Test the points, and you can never go wrong.

  • @sejvihasani9426
    @sejvihasani9426 7 років тому +2

    I couldn't not thank you. so, thank you very very much

  • @ibrahimsabthasildar7507
    @ibrahimsabthasildar7507 4 роки тому

    Sir how we consider the constraints of 0 1 2 mutipication

  • @Nightsaberban
    @Nightsaberban 5 років тому

    Thanks I think I can do what I was stuck on now!

  • @mariadisano7088
    @mariadisano7088 3 роки тому

    Thank you!

  • @SrgntLoveGaming
    @SrgntLoveGaming 5 років тому

    You're brilliant!

  • @ahmedelsabagh6990
    @ahmedelsabagh6990 6 років тому

    Great video

  • @daliaal-saeed5978
    @daliaal-saeed5978 7 років тому +1

    thank youuu!!

  • @mrytyunjaykr
    @mrytyunjaykr 4 роки тому

    Thankyou

  • @MrOcean505
    @MrOcean505 9 років тому

    thanx a lot you're the best
    Regards

  • @burgerkini8757
    @burgerkini8757 2 роки тому

    i'm just confused where does the 0.5 came from

    • @joshemman
      @joshemman  2 роки тому

      Can you include the time stamp

  • @rickdelano5531
    @rickdelano5531 7 років тому

    Al hail Joshua !!!

    • @joshemman
      @joshemman  7 років тому

      You forget to add "King"...haha.

    • @rickdelano5531
      @rickdelano5531 7 років тому

      Joshua Emmanuel haha I just watched this before writing the exam and I forgot that King part I might have typed it in a rush so yah ... Hail King Joshua !!!

    • @joshemman
      @joshemman  7 років тому

      Lovely! You're amazing. Thanks for the comments.

  • @cherdoudayoub5755
    @cherdoudayoub5755 2 роки тому

    Thanks sir
    But I don’t understand
    Min Z= -x - y
    Sc -x + y =< 2
    x+y = 4
    x >= 0 ; y >= 0
    Help me plz
    Thanks

    • @joshemman
      @joshemman  2 роки тому +1

      Go to the link below.
      Click Solve Model at the bottom left corner.
      Click Model Overview to see the graph and objective function value.
      online-optimizer.appspot.com/?model=ms:jg10guIKiyf2t2YJEgJawGH3RBanu8s1

    • @cherdoudayoub5755
      @cherdoudayoub5755 2 роки тому +1

      @@joshemman thank you so much (from Morocco 🇲🇦)

    • @joshemman
      @joshemman  2 роки тому +1

      @@cherdoudayoub5755 My pleasure

  • @matinajazmine
    @matinajazmine 3 роки тому

    Am getting opposite answers when I do it with u .I dunno why

  • @aslinurakbulut6771
    @aslinurakbulut6771 7 років тому +1

    i cant thank you enough !!!

  • @Up2gethigh
    @Up2gethigh 4 роки тому

    thank you man