Physics 38 Electrical Potential (15 of 22) Potential Outside 2 Concentric Cylindrical Conductors

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  • Опубліковано 22 січ 2025

КОМЕНТАРІ • 52

  • @valeriereid2337
    @valeriereid2337 Рік тому +1

    It is wonderful that I can return to these lectures and listen again for more clarity. Thanks Professor for making these available.

  • @odgarig8601
    @odgarig8601 Місяць тому +2

    So we changed the d from E=Vd into r when we did the integration when finding the voltage? It was a bit confusing...

    • @MichelvanBiezen
      @MichelvanBiezen  Місяць тому +1

      Both d and r are variables representing linear distance.

  • @odgarig8601
    @odgarig8601 Місяць тому +2

    Why do we go from the outer surface to the inner when integrating? Can we go the opposite direction

  • @hamhim7912
    @hamhim7912 4 роки тому +1

    what's the different about the result if the inner plate is given a negative charge and the outer plate is given a positive charge?

    • @MichelvanBiezen
      @MichelvanBiezen  4 роки тому

      The direction of the electric field would be opposite, and the sign of the change in voltage would be opposite as well.

  • @lefterisspanoudakis3152
    @lefterisspanoudakis3152 2 роки тому +1

    The negative charges on the outer cylinder will accumulate on the inner surface of that cylinder.

    • @MichelvanBiezen
      @MichelvanBiezen  2 роки тому

      You are correct. They will migrate to the inner surface of the outer cylinder.

  • @jatinrathore3997
    @jatinrathore3997 7 років тому +3

    @Michel van Biezen
    if we draw a gaussian cylinder enclosing both the cylinders then net charge enclosed will be zero as there are equal and opposite charge densities.Then the electric field outside the cylinders should be zero according to gauss's law right?

  • @Cottarino
    @Cottarino 2 роки тому

    I"m having trouble with a problem, infinite coaxial cylinders the inner cylinder has a charge density rho(non-conducting) and radius a. the outer cylinder has radius b and is a grounded conductor. I'm being asked to solve for the electric potential everywhere in space. I have a hard time figuring out how the grounding effects the system.

  • @rramshankar5173
    @rramshankar5173 3 роки тому +2

    Thank you sir! Wonderful and clear explanation!

  • @valeriereid2337
    @valeriereid2337 Рік тому +1

    Wonderful. Thanks for an excellent lecture.

  • @aadithephysicsguru8933
    @aadithephysicsguru8933 7 років тому +3

    How did you get the electric field formula that is on the top? Isn't the denominator 4*pi*epsilon naught (because k sub e is 1/4*pi*epsilon naught)? I have never seen that formula before... Anyway, thx for all these videos...My AP Physics C grade is a 99 because of your videos!!!

    • @aadithephysicsguru8933
      @aadithephysicsguru8933 7 років тому +2

      Wait a minute... I figured it out... You applied Gauss' Law beforehand to derive that formula for the electric field using a cylindrical Gaussian surface. Is that right?

    • @MichelvanBiezen
      @MichelvanBiezen  7 років тому +1

      That is correct.

  • @davisjohn-d6h
    @davisjohn-d6h 5 років тому +1

    If the outside cylinder had a thickness to it, would a negative charge be induced on the inner wall of it and a positive charge be induced on the outside surface?

    • @MichelvanBiezen
      @MichelvanBiezen  5 років тому +1

      That is correct.

    • @davisjohn-d6h
      @davisjohn-d6h 5 років тому +1

      @@MichelvanBiezen thank you sir.

    • @odgarig8601
      @odgarig8601 Місяць тому

      @@MichelvanBiezen It's awesome how you take the time to answer these questions. All the respect I can give for you dear sir!

  • @Ben-786
    @Ben-786 Рік тому +1

    Now if we calculate yhe electrostatic energy per unit length,we get a factor of 1/2...why is that sir?

    • @MichelvanBiezen
      @MichelvanBiezen  Рік тому +1

      Think of charging a capacitor. It takes almost no work to add the first charge. But to add the last charge it takes a lot of work. To place the average charge on a capacitor, it takes 1/2 the work of the last one.

  • @myrrhagoyokpin8057
    @myrrhagoyokpin8057 2 роки тому +1

    hello! why are we using lamda and not sigma? isnt the charge spread out on the lateral surface area of the cylinder?

    • @MichelvanBiezen
      @MichelvanBiezen  2 роки тому +1

      It depends on the application. Here the difference in potential depends on the strength of the electric field between the two cylinders. The electric field can be found using Gauss's law which shows that the electric field depends on the total charge inside the surface and it doesn't matter if it is along a line of charge or the surface of a small cylinder (as long as the charge in uniformly distributed), thus we can use line charge density just as well as surface charge density,

    • @myrrhagoyokpin8057
      @myrrhagoyokpin8057 2 роки тому +1

      @@MichelvanBiezen So here we could also have used surface area charge density and would still get the same answer?

  • @mckboulos
    @mckboulos 6 років тому +2

    Hi Pr. Could you please explain to me why you always put the negative sign when you integrate. Thank you.

    • @MichelvanBiezen
      @MichelvanBiezen  6 років тому +1

      It is by convention. Since the potential is greater near the positive charge, the equation requires a negative sign to ensure that the potential increases as you get closer to the positive charge.

    • @bugrahanatar2205
      @bugrahanatar2205 5 років тому

      @@MichelvanBiezen sir understanding of sign it is so emberassing for me. If the potential is greater when it is toward to the positive why we put negative sign is it going to lower to bigger?

  • @rickgrimes47
    @rickgrimes47 4 місяці тому

    Thanks professor Michel.

  • @shajeelaselvadhas1616
    @shajeelaselvadhas1616 7 років тому +2

    sir do you have a video about finding v for concentric sphere/shell and one is earthed

    • @MichelvanBiezen
      @MichelvanBiezen  7 років тому

      This video may help: Physics - E&M: Electric Potential (20 of 22) Equipotential Surfaces in a Varied E-Field

  • @kleamburimi6089
    @kleamburimi6089 7 років тому +5

    man u the best

  • @faris4363
    @faris4363 4 роки тому +1

    Ur a legend

  • @mishaldurrani125
    @mishaldurrani125 4 роки тому

    so in this case we are assuming that the outside cylinder has no thickness - almost zero thickness-?

    • @MichelvanBiezen
      @MichelvanBiezen  4 роки тому

      If you are referring to the Gaussian surface, you are correct.

  • @enjoy5327
    @enjoy5327 4 роки тому

    Thank you so much sir from India,awesome teaching sir, with line by line explanation

  • @abdohajar908
    @abdohajar908 8 років тому +1

    Michel van Biezen
    Hello sir, thank you for the help
    I would like to ask whether an electric field exists inside the larger cylinder. Since the larger cylinder is a conductor shouldn't the electric field inside it be 0. Moreover does the electric potential change as we move between r2 and r1 because if there's no electric field there should be no change in potential.
    Once again. thank you for untying the knot in my head
    All the best

    • @MichelvanBiezen
      @MichelvanBiezen  8 років тому +2

      Since there is charge on both the inner and outer cylinder, there will be an electric field between them. (No electric field inside the inner cylinder).

    • @abdohajar908
      @abdohajar908 8 років тому

      Thank you

    • @KimuraSetsuna
      @KimuraSetsuna 6 років тому

      +Michel van Biezen
      Mr.Michel, is it empty between the two cylinder?

  • @KimuraSetsuna
    @KimuraSetsuna 6 років тому +1

    +Michel van Biezen
    Mr.Michel, is it empty between the two cylinder?

    • @MichelvanBiezen
      @MichelvanBiezen  6 років тому

      Yes, there is no charge between the two cylinders.

    • @KimuraSetsuna
      @KimuraSetsuna 6 років тому

      Excuse me, but what I mean to ask is, is it hollow?as of no presence of metal around the area
      I got mistaken thinking that it is two solid cylinder, that kept me wondering why there is electric field in between....
      but at last i figure that maybe it is hollow.....if it is hollow i can understand why there is electric field in between....

  • @halilbayzan2602
    @halilbayzan2602 5 років тому

    Could we do it by the gaussian surface

  • @ElifArslan-l9g
    @ElifArslan-l9g 3 роки тому

    thank you

  • @kirasdfg
    @kirasdfg 9 років тому +1

    Helpful. Thank you!