Asfaque Khan The formula may look like y(i+1)=y(i)+(k1+.........)*h Some people write it is y(i+1)=y(i)+(k1p+.........) Both are right as the h is bundled with k1 as k1p=k1*h.
This guy teaches way better than my worthless numerical methods professor at UTPA. I don't understand how my professor even got hired or how he gets such good scores on his course evaluations.
@yousafkazmi The formula may look like y(i+1)=y(i)+(k1+.........)*h Some people write it is y(i+1)=y(i)+(k1p+.........) Both are right as the h is bundled with k1 as k1p=k1*h.
In deriving Runge-Kutta method of 4th order, how many unknown coefficients are involved originally and how many equations you get to find the values of these unknown coefficients? Hence how many coefficients can be chosen arbitrarily?
at the k2 part...why there is (y+k1*h/2)....most of the books don't have that h part
Asfaque Khan The formula may look like y(i+1)=y(i)+(k1+.........)*h
Some people write it is y(i+1)=y(i)+(k1p+.........)
Both are right as the h is bundled with k1 as k1p=k1*h.
oh..right!! got it...thanks sir for such early reply☺
pro trick: you can watch series at Flixzone. Been using them for watching loads of movies these days.
@Louie Barrett Definitely, have been using flixzone} for since november myself :)
Even after 11year this content is one of the best I found on UA-cam.
Probably The Best.
This guy teaches way better than my worthless numerical methods professor at UTPA. I don't understand how my professor even got hired or how he gets such good scores on his course evaluations.
just a heads up, for the third derivative in the Taylor series expansion, you have dx^2 in the denominator
@yousafkazmi The formula may look like y(i+1)=y(i)+(k1+.........)*h
Some people write it is y(i+1)=y(i)+(k1p+.........)
Both are right as the h is bundled with k1 as k1p=k1*h.
Thank you for the explanations.
elegant explanation
Yes, you can.
In deriving Runge-Kutta method of 4th order, how many unknown coefficients are involved originally and how many equations you get to find the values of these unknown coefficients? Hence how many coefficients can be chosen arbitrarily?
for solving higher oder derivatives can we apply heuns method
that i learnt from this video link
nmmathforcollege
i love you sir!
Hello, how do you alter this formula to calculate a second order differential equation?
Can you please explain why is it called the 4th order as the order of the derivative in the equation is one?
4th order as it uses up to 4th derivative terms in Taylor series.
can you show the proof ?
I think the subscript of derivatives should be x(i) when y(i+1) is expanded with Taylor series.
fucking fucking fuxking fuxking fucjing helpful!!
regression interpolation derivative just everything
how we find values of coffiecnts a1,a2,,...?
Need solution of 2nd order differentia equation by 4th order RK and e examples too
Go to nm(dot)mathforcollege(dot)com and click on Keyword. Click on Higher Order Differential Equations. See the last three video lectures in sequence.
derivate where you are and where you want to go
Vielen Dank
im having the same problem. if you figure it out then let me know :P
i learned this in 1st grade
Good for you. Time to learn 2nd grade stuff.