@@AmanSingh-qw7wvthere shouldn't be a concept of gravity here, may be its how the pressure and volume change, the path the processes choose isn't same...
In 3:45 u give some heat, u r a part of surrounding, system split it in two parts,one part is internal energy and other part will do work so w.d by system less than w.d on system(surrounding)
Sir aap work done ke area under curve le rhe hain tu area under P1V1 to P2V2 lena chahiye na aap to seedha area under P1V1 se leke area under pressure= 0 and V2 le rhe hain...? Why?
Sir, if the system is doing some work , then it will be negative. I'm correct or not sir, please tell me. In this video, you have taken work as positive. 🤔🤔🤔
Sir , according to Boyle's law volume is inversely proportional to pressure but when the temperature is constant but here we are giving heat to the system so , the temperature of the system changes ....so what is the law u r applying
1st law Inverse relationship always exist between volume Nd temperature but yes it depends on situation that u mentioned.if temperature is constant inverse relationship explicitly exist between p and v Nd if T is not constant implicit inverse relationship exists between p and v.
Sir internal energy and change of internal energy pe video banaye.... exam ah rahe hein sir, thodi si apse madat mil jati toh achhe marks atee🙏🙏🙏🙏♥️♥️♥️🙏🙏
dono work yani system se or system pe work ak sath hohi nhi sakata kon work kar raha he ye volume bada he ya gta he isase pata chalega or jo volume bde or gate bhi to zab volume bad raha he tab system or zab gat raha he tab syatem pe work kiya za raha hoga.
Sir app ne quasistatic process ka jikkr starting me kiya but jab figure ban gya to quasistatic ko samjhaya nhi, aap ne figure se bataya ki workdone hota hai matlb quasistatic me workdone milta hai
dekhiye ye ak dharna he jese ak exampal me x ki value 2 ase to dusre me aur kuch aa saakati he is tarah yaha hamesa bfa line acb se niche ho ye zaruri hi nhi.
Sir jo piston pe weight h wo v system hi h na,to wo system pr kaise kam KR skta h.us tym v piston khud k upr ho weight h usi k Karn niche aaega na to,external workdone kaun kiya.plz clr sir.
dekhiye system kisko pasand karana uko dekhane wala hi decide karata he jese aapne system ko weight ke sath leliya or video me weight ko system me nhi liya or agar hum weight ko system ke sath le to system ki energy me uki potencial energy bhi aap jaye gi to zab piston niche aye ga tab weightvka potencial energy ka siraf gas ki energy me zayegi.
net workdone zero nahi hoga kyuki hum sirf pressure ko constant mankar volume ka small change consider kar rahe hai...aur phir volume ke respect me integration karke workdone nikal rahe hai.
You have given a very good explanation Sir
Aapk teaching technique sub se alleg Hain aur kammmmaaaaallllll ki Hain !!!.....
Thanks a lot sir !!!
Kya mst pdhate ho sir mja aa gya pdh ke this is called combination of technology and talent. 👍👍👌👌👌😃❤❤❤
Sir bphot badiya Lecture hai
Best explanation ever thank u
One of the great explanation....
Nice and excellent service sir.
Good effort in right direction sir. Please continue in this way to provide free study with better understanding
Thank you Mahendra.
Right
In graph pressure first increase and last in decrease
thank you sir maja agaya.........
Really very interesting lecture!!
#distinctphysics #distinctphysicsbsc
Best explanation 👌
great job sirji....
Sir please explain when we are going from p2v2 to p1v1 then why did you assume the work done to be less than going from p1v1 to p2v2 ?????
20:53
what is your problem please explain
Yes I had also confused for this.... Please give explaination sir
Because pdv work negative when surrounding do work on the system
One query: Why the work done by thermodynamic system and w.d. by surrounding are not same? Any specific reason behind this?
May be bcoz of thermodynamics was working aginst gravity,
@@AmanSingh-qw7wv sorry bro... But according to me... It is incorrect explaination... I am hoping for the next explanation from you... 😊😇
@@AmanSingh-qw7wvthere shouldn't be a concept of gravity here, may be its how the pressure and volume change, the path the processes choose isn't same...
Work same hota h bas najarye ki baat h
In 3:45 u give some heat, u r a part of surrounding, system split it in two parts,one part is internal energy and other part will do work so w.d by system less than w.d on system(surrounding)
Best explanation ❤️❤️
Sir you are great explainer
Good job sir
Thnku so much sir for this amazing video 😊
Sir aap work done ke area under curve le rhe hain tu area under P1V1 to P2V2 lena chahiye na aap to seedha area under P1V1 se leke area under pressure= 0 and V2 le rhe hain...? Why?
Sir, if the system is doing some work , then it will be negative.
I'm correct or not sir, please tell me.
In this video, you have taken work as positive. 🤔🤔🤔
It's is clockwise cyclic processand another reason is work done by the process
U explain too good
Sir , according to Boyle's law volume is inversely proportional to pressure but when the temperature is constant but here we are giving heat to the system so , the temperature of the system changes ....so what is the law u r applying
1st law
Inverse relationship always exist between volume Nd temperature but yes it depends on situation that u mentioned.if temperature is constant inverse relationship explicitly exist between p and v Nd if T is not constant implicit inverse relationship exists between p and v.
18:30Sir jab hum p ko dv Se multiply karenge to Hume small area ka work na milega
Fir se puchhen
Sir please also cover maths topics and make videos on partial differentiation and multivariable calculus.
sir at 7:23 i think you have interchanged the ordinate and absicca.
+Ayush Goel
There is a strong possibility.
I commit that kind of mistakes very often.
thanks very much sir
Thanks sir u are great
Sir internal energy and change of internal energy pe video banaye.... exam ah rahe hein sir, thodi si apse madat mil jati toh achhe marks atee🙏🙏🙏🙏♥️♥️♥️🙏🙏
Thank u sir ❤️❤️❤️❤️
Very helpful thankyou sir
You are super
Sir ye kaise pta ki jo hm work kr rhe hai system pr wo system k dwara kiye gye work se km hai ya jyada ...ya barabar
dono work yani system se or system pe work ak sath hohi nhi sakata kon work kar raha he ye volume bada he ya gta he isase pata chalega or jo volume bde or gate bhi to zab volume bad raha he tab system or zab gat raha he tab syatem pe work kiya za raha hoga.
sir plese put analogous system of degre syllabi
sir , jab quasi static process hoga , to us case me net work done to zero ho jayega , isko please clear kar dijiye.
Is it helpful for bsc physics owners students?????? Plzz reply me sir
Thank🙏💕🙇🙇🙇 sir
Are you teaching anymore bsc 1 year physics topic as mechanics oscillations
Sir aap kainsi book se padate hai
One question: how do you know that when surrounding is working on the piston then work done is less than that of when piston works on surrounding??
actually sir is not saying this case,, he is saying that the same states can be achieved reversely by doing less work on the system..
Biroo, Extra work is conserved in enternal energy form.
wonserfull.
+friends frendly
Thank you.
Sr quasi static process real process hai ya ideal bs ye confirm kr dijiye
wowwwwww! tnx sir jee
+Saif Bacchu
You are welcome.
Your support is very much valuable to us.
@@edupoint.physics we are always with you sir.. We support to you to make more videos on this channel 🥰
Sir please reply
Humne Jo work kia uska curve alag kyu h
Aesa work hum krenge kese
hit de ke hum v or v man chahe state me lega skate he.
Bahut Barhyia
Sir solve problem of thermodynamics
Sir, which books is good for thermodynamics
Sneha Ghosh tm use krti ho to kro n sabko kyu dra rhi ho .. pagal ladki
Sir app ne quasistatic process ka jikkr starting me kiya but jab figure ban gya to quasistatic ko samjhaya nhi, aap ne figure se bataya ki workdone hota hai matlb quasistatic me workdone milta hai
Thanks
BFA line ACB se niche hi keu hoga sir..plz clear..
dekhiye ye ak dharna he jese ak
exampal me x ki value 2 ase to dusre me aur kuch aa saakati he is tarah yaha hamesa bfa line acb se niche ho ye zaruri hi nhi.
Thank u sir
Sir jo piston pe weight h wo v system hi h na,to wo system pr kaise kam KR skta h.us tym v piston khud k upr ho weight h usi k Karn niche aaega na to,external workdone kaun kiya.plz clr sir.
dekhiye system kisko pasand karana uko dekhane wala hi decide karata he jese aapne system ko weight ke sath leliya or video me weight ko system me nhi liya or agar hum weight ko system ke sath le to system ki energy me uki potencial energy bhi aap jaye gi to zab piston niche aye ga tab weightvka potencial energy ka siraf gas ki energy me zayegi.
Direct point pe aao explain only quasi static only
sir iske numerical ki video ki link send kriye pless
Your videos are being watched all over the despite not understand your language. Can you speak in English, please?
But sir 1 st figure me pressure kam hai and last figure me pressure jyada hai
sir ek vedio partical eccelerater per.
+friends frendly
Channel me available hai.
Please search typing "cyclotron edupoint".
coordinate galat likha hai sir
👍
♥️
sir , jab quasi static process hoga , to us case me net work done to zero ho jayega , isko please clear kar dijiye.
Thank you sir
Thanks sir
thank you so much sir
sir , jab quasi static process hoga , to us case me net work done to zero ho jayega , isko please clear kar dijiye.
net workdone zero nahi hoga kyuki hum sirf pressure ko constant mankar volume ka small change consider kar rahe hai...aur phir volume ke respect me integration karke workdone nikal rahe hai.
Static process me work done zero hoga lekin quasi static me work done toh hoga hi kyuki isme negligibly hi sahi parameters change honge
thanks sir 🙏🙏
Thank you sir