Poisson's Law in Thermodynamics | in HINDI

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  • Опубліковано 16 гру 2024

КОМЕНТАРІ • 80

  • @Parth.837
    @Parth.837 3 роки тому +2

    Best voice with best explanation

  • @pramitmahajan5639
    @pramitmahajan5639 4 роки тому +2

    BEST EXPLANATION EVER SIR . I LIKE THAT VERY MUCH . ALL THE EDUPOINT VIDEOS ARE THE BEST. THANK YOU SIR FOR TEACHING ME THIS FULL CHAPTER. YOU ARE THE BEST....

  • @studystudy404
    @studystudy404 4 роки тому +9

    Sirji constant Volume wali internal energy Adiabatic process mein kaise use ki ?

    • @Priyansh502
      @Priyansh502 3 роки тому

      Yahi question pooche me bhi aaya hu sirji,,,

    • @anshawasthi4185
      @anshawasthi4185 2 роки тому

      The work is done by the gas at the cost of internal energy so that there is fall in temperature also we know that the internal energy depends on the temperature

    • @studystudy404
      @studystudy404 2 роки тому +1

      @@anshawasthi4185thanks for reply🙏🏻
      But i remember a little about the topic because I asked a year back 😄 😊

  • @justwatchsss8849
    @justwatchsss8849 6 років тому +1

    Super sir you are my real Superhero

  • @daily_life317
    @daily_life317 2 роки тому +1

    wow sir amazing explanation. 👍👍🙏🙏

  • @tmfad4912
    @tmfad4912 2 роки тому

    Best teaching I have ever seen

  • @bidyasagarmohapatra8270
    @bidyasagarmohapatra8270 6 років тому +11

    sir ,du=Cv dT ye to constant volume me hota he . to ye equation adiabetic process me kaise use hoga ?? adiabetic process me to volume increase hota he...please explain me..

    • @studystudy404
      @studystudy404 4 роки тому +1

      *Exactly same problem I have* !

    • @studystudy404
      @studystudy404 4 роки тому

      @@SimSimSimSim 🤔🤔achha not seeming appropriate .. I couldn't understand 😐😐

    • @gyanendarkaur2283
      @gyanendarkaur2283 3 роки тому +1

      Adiabatic process mein heat transfer zero hoga..so volume constant rahegi.. internal energy

    • @ullasrajs3537
      @ullasrajs3537 3 роки тому +1

      Volume is not constant in Adiabatic process.
      The reason dU=nCvdT
      Cv is taken because internal energy is not path dependent.

    • @gyanendarkaur2283
      @gyanendarkaur2283 3 роки тому

      @@ullasrajs3537 Volume will be constant because no work is done...no transfer of heat so particles will not get k.E to move...so volume will be constant......

  • @navnit5122
    @navnit5122 3 роки тому +3

    This lectures is also for b.sc chemistry students

  • @spdas5942
    @spdas5942 Місяць тому

    Namaste sir, from West Bengal .

  • @sheerazkhee291
    @sheerazkhee291 4 роки тому +2

    Sir in the above case when the process adiabatic then how can take dq=dU and then put CV=dU/dt

    • @pramodkharel2082
      @pramodkharel2082 3 роки тому

      Koi thermodynamic system meh adibatic process karyane se pehele hi uska, internal energy hota hai. ham system ka volume constant rakh ke usme heat supply garte hain tab uska internal energy badta hain iska matlab uska internal energy sirf tempreture ka function at const volume hain. Ish liya hamne du=Cvdt lekha hain. Yeh adiabatic process se pehele jo internal energy hain, uska equivalence hain, in terms of cv and dt.
      second term hain, pdv, meh constant volume nahi liya gaya hain, kuin ki jab tempreture ghategi, to internal energy ghategi, uski bajhe se system meh work done hoga, uske volume badega. (internal energy du= cvdt is transferd to mechanical work, pdv). Yeh volume change, aur uper ki constant volume alag alag process ko describe karti hain. Ishiliya confusion hogaya hoga.

  • @alpeshbhaisola3529
    @alpeshbhaisola3529 Рік тому

    You are awesome 😎😎👍

  • @siddharthatal8662
    @siddharthatal8662 4 роки тому

    Best physics videos

  • @fawadmirza.
    @fawadmirza. 7 років тому +6

    Nice. Better if you explained a quick application of that formula.

    • @edupoint.physics
      @edupoint.physics  7 років тому +6

      Hello fawad mirza !
      Thank you very much for the support you have shown.
      Yes! I missed that. I shall keep your suggestion in mind.
      And as always ...... thanks for watching.

    • @apnatime4831
      @apnatime4831 Рік тому

      Application is that it can be used to find work done in adiabatic process

  • @bhaswatipaul7133
    @bhaswatipaul7133 Рік тому

    During expansion the internal pressure given by the system must be less but you considered same

  • @sukhwinderkumar4654
    @sukhwinderkumar4654 5 років тому +2

    Sir one question ... If you don't give any heat to the system .. then how piston moves upward..

    • @bharathkumar.e617
      @bharathkumar.e617 5 років тому +1

      The gas uses its internal energy to do work, and pushes the piston up

    • @cadatabdullah3511
      @cadatabdullah3511 4 роки тому

      If friction removed bt piston and wall

  • @manishranjanpersonalfinance
    @manishranjanpersonalfinance 5 років тому +1

    Sir ek doubt h ye constant volume se du ki jo value ayi use adiabatic me kaise put kiya gaya please reply sir

  • @abhishekzodge717
    @abhishekzodge717 6 років тому

    Thanks sir muze aaaispar bhaut doubt te Sab clear ho gaye

  • @restinpeace6712
    @restinpeace6712 6 років тому +8

    ham ne 1k alag thermodynamic system se kyu cv nikala or usko adiabatic system ka equation Mai kyu put kya

    • @arupbiswas8288
      @arupbiswas8288 6 років тому +2

      Rest In Peace excellent question, I am also thinking about this!

    • @sheerazkhee291
      @sheerazkhee291 4 роки тому +1

      @@SimSimSimSim
      How in adiabatic process we bring change in internal energy of system by considering piston moves upward s of its own

  • @atharv_shinde_2110
    @atharv_shinde_2110 3 роки тому

    Thank u it was very helpful

  • @dhrubanidas8064
    @dhrubanidas8064 4 роки тому

    Sir thank u soooo much... Much needed video...
    Sir bsc physics ka jitna ho sake lecture upload karna.. Plzzz 😶🙏❤
    Thanks u sir... Respct for you❤🙏

  • @mdanishrahman2485
    @mdanishrahman2485 4 роки тому

    Thank you very much 🥰💖

  • @THEGREATARC
    @THEGREATARC 13 днів тому

    Lekin adabetic system main heat kaise Diya yea badme bataunga bolke batayahi nehi, Aisa kaise

  • @swetachatterjee464
    @swetachatterjee464 3 роки тому

    Sir dU=Cvdt kyu hota h yha pe???
    Adiabatic process mei volume constant to nhi hota h!!,
    Sir please reply...... 🙏🙏🙏🙏🙏

    • @Quantum-66
      @Quantum-66 2 роки тому

      Internal energy (u) depend only temprature not depend volume / pressure,etc. This is valid for ideal gas .

  • @ayushigupta5664
    @ayushigupta5664 2 роки тому

    Sir, y did u use here natural logarithm instead of common algorithm.

  • @shyamalibhowmik8139
    @shyamalibhowmik8139 2 роки тому

    Thank you sir

  • @Quantum-66
    @Quantum-66 2 роки тому

    Why,
    Pdv + VdP = RdT
    (Pressure is constant)
    So it should be ,
    Pdv + 0 = RdT

  • @SKS-mp4oj
    @SKS-mp4oj 2 роки тому

    Thanks sir ji.

  • @kpkrkr4038
    @kpkrkr4038 2 роки тому

    If heat given to the system is zero then how internal energy change

  • @sneha_bhatt
    @sneha_bhatt Рік тому

    Ty❤

  • @gobindchandranahak5613
    @gobindchandranahak5613 5 років тому

    Sir dv must be zero at eqn 1 why is nt

  • @PremK_
    @PremK_ 3 роки тому +1

    ❤️❤️❤️❤️

  • @sunnybunny2521
    @sunnybunny2521 4 роки тому

    this is reversible adiabatic equation

  • @subhadeeproychowdhury1059
    @subhadeeproychowdhury1059 6 років тому

    Super

  • @thenewdimension9832
    @thenewdimension9832 6 років тому

    Thanks sir u are great

  • @dipankaratriya3309
    @dipankaratriya3309 6 років тому

    nice

  • @KANTSHRIVASTAVA
    @KANTSHRIVASTAVA 6 років тому

    sir please upload related to the communication

  • @rakeshkumardas6881
    @rakeshkumardas6881 5 років тому

    Ok

  • @physicshubeducation6556
    @physicshubeducation6556 7 років тому

    sir h.c verma ka solution complete dala kro

  • @suhahanaurwasi5080
    @suhahanaurwasi5080 5 років тому +1

    👌👌

  • @Rjj193
    @Rjj193 5 років тому

    Too long method

  • @kristenlover3852
    @kristenlover3852 6 років тому

    Totally fraud , in first equation , you are calculating dU = Cv dT for constant volume system and at 11:15 you are equating it to to dW for constant pressure system.
    Please reply if you have any explanation about your stupid approach.

    • @edupoint.physics
      @edupoint.physics  6 років тому +3

      “Stupid approach”
      I love and accept that.

    • @kristenlover3852
      @kristenlover3852 6 років тому

      So, how would you prove poisson's law?

    • @edupoint.physics
      @edupoint.physics  6 років тому +12

      Helllo Kristen,
      This is "stupid approach" here.
      Bhai aapko Cv aur Cp ek equation me laana hai. Thik hai ya nahi?
      Cv kahan se aayega? You need to have a system with constant volume.
      Cp kahan se aayega? You need to have a system with constant pressure.
      Agar aap Cp ko constant-volume system se laa sakte hain to congratulations dost!
      You say, Mayer's formula is there Cp - Cv = R. Par wo bhi to isi "Fraud" aur "Stupid" approach se aaya hai.
      Jo bhi ho absolute truth to kisiko pata nahi hai. Ho sakta hai ki aap hi iss "fraud" aur "stupidity" ka parda faas karein.
      "So, how would you prove poisson's law?"
      - Who the hell I am to prove that. It has been proved by Poisson in this manner.
      Aapne iss approach ko "stupid" kaha kyunki kitaabo me jo likha hai use details me ek ek karke maine samjhaya hai. Varna kitab me to sirf formula hai. Use log details me samajhte nahi hai aur doubt bhi nahi aata. Par kitabo hai to yahi.
      "Sometimes good enough is not good enough."
      Regards-
      The stupid man expecting a little amount of respect for his work.

    • @kristenlover3852
      @kristenlover3852 6 років тому

      EduPoint Bro don't get sentimental.
      I analysed the given case as well as Meyer's formula many times and came to realise what you are doing is RIGHT. the truth lies vehind the fact that ENTHALPY IS A STATE FUNCTION. Though these are two different situations but we can substitute dU just because change in internal energy is same in both the cases and it is independent of the PATH followed. Here dU acts just like a normal function of temperature
      Like dU= 3t-8
      Here Cv is a constant and acts like the 3 in above equation.
      I apologise for my harsh comments. But I want you to FEEL as well as UNDERSTAND that your explaination as well a meyer's proof is absolutely right . Your accepting that there is a flaw in the proof is wrong. YOUR PROOF IS RIGHT . YOU SHOULD FEEL THIS.Truly fifteen minutes ago when i realized this phenomenon i was jumping with excitement of enlightenment. Please reply if yyou understood what i explained above.You can also improve your video just by putting a sentence that enthalpy is a state function.
      Again , Sorry for the harsh comment.
      YOU WERE RIGHT.
      I REQUEST YOU TO UNDERSTAND MY EXPLANATION
      Regards Kristen Lover

    • @edupoint.physics
      @edupoint.physics  6 років тому +8

      Dear Kristen,
      Every comment was ironical there (what I replied to you, like “stupid”, “fraud”).
      I do not have any doubt.

  • @gajananpachbhai9008
    @gajananpachbhai9008 6 років тому

    ...

  • @fazeelmohammad8236
    @fazeelmohammad8236 Рік тому

    ❤❤❤❤

  • @nitishkaushik4299
    @nitishkaushik4299 2 роки тому

    ♥️