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i love you man you saved my exams really appricate
Wow! We are glad to know that. Best wishes always.
Great eplannation. Your explannation made it easy to follow and learn.
Wow that's good you make it easy for me thank you very much God bless
Thanks you sir, may God bless you abundantly
Actually the dood is amazing. His slow style of explaining makes u grab beta
Thank you very much you teach more than my lecture
You are welcome.We are happy to hear this.We appreciate your feedback and compliment.Warm regards.
You explained it very easy to understand..just in a short time thank you..
good presentation, really i understand explanation thank you
My 12th grade would have been less stressful if I had watched your videos😢
Excellent sir u did well
Thanks so much, you made me understand stat quickly and easily
Glad it helped!
Thank so much !❤️Firstly I didnt know what is ungrounded is
You're welcome 😊
Thanks so much May God bless you 🙏
You are so welcome!Same to you. We appreciate your feedback. It means a lot to us.
I appreciate you alot 🙏🙏 for this nice teaching
Thank you for your feedback and compliment.Warm regards.
Life saviour be blessed ❤
Love from India 🇮🇳🇮🇳
Thanks for the explanation great job l thank u so much for the info 💕❤️💪👍
You are welcome. We appreciate your feedback.
I love the way you explained the math
Thanks you sir for making it easy for me to understand
You are welcome.We are glad you understood it.We really appreciate your feedback.
WOW 😲 I never knew I will understand statistics ungrounded ungroup data creating a frequency table , finding the mean , Median,mode
Thank you for your time and presenation
You are welcome.
Wow, nice video. More wisdom
A brilliant Lecturer ,meant to do dat.
Today i understand this fine, thank you very much sir
Mean is :3+4+5+5 +5+6+6+7+8+9/10:10÷58 : mean : 5.83,4,5,5 5,6,6,7,8,9.9-3=6 range is :6Media: 5,6
amazing video i like it its easy to understand
Nice clearly explained
You made it so easy to understand
I like your explanation
Thanks for liking.We really appreciate your feedback.Warm regards.
Thank you 🙏🏾🇬🇭
superbbbb.thanku
You are welcome.We appreciate your complement. We will be happy if you kindly subscribe to our UA-cam channel.
Very helpful
Glad to hear that.We appreciate your feedback.Warm regards.
Sir I'm still confused on how you get 129 as the median I thought it's should be 130
Wonderful
Thank you! Cheers!We appreciate your feedback.
Thanks so much
You're welcome!
What if the distribution of scores in ungrouped data is bimodal, how to find the value of mode? Example: 5, 3, 2, 5, 7, 2, 8, 11..what is the value of mode?
It has bimodal mode of 2 and 5 as you stated earlier
dumbass
Thank you Sir
Thank you
You're welcome. We appreciate your feedback.
on problem 3 calculating mean why did you the formula of grouped data when its ungrouped data
They have the same formula only the X's are different.
The median: 15÷2=7.5 How did you round it with a whole number to get 8?
Thank you for your feedback.How or why?Meanwhile, you are meant to always round off to obtain a counting number.
Sum number 3 I didn't understand the median part. How comes 4 is the median number? I wish you could elaborate more
Thanks
thank u sir 💜💜
That was simple
Thanks for your feedback.Warm regards.
Interesting
❤
Won
Please I have an assignment I need help
Yes sir do you any whatsapp group please add me
Thank you sir
You are welcome.We really appreciate your feedback.Warm regards.
Thanks you sir
You are welcome
i love you man you saved my exams really appricate
Wow! We are glad to know that. Best wishes always.
Great eplannation. Your explannation made it easy to follow and learn.
Wow that's good you make it easy for me thank you very much God bless
Thanks you sir, may God bless you abundantly
Actually the dood is amazing. His slow style of explaining makes u grab beta
Thank you very much you teach more than my lecture
You are welcome.
We are happy to hear this.
We appreciate your feedback and compliment.
Warm regards.
You explained it very easy to understand..just in a short time thank you..
good presentation, really i understand explanation thank you
My 12th grade would have been less stressful if I had watched your videos😢
Excellent sir u did well
Thanks so much, you made me understand stat quickly and easily
Glad it helped!
Thank so much !❤️
Firstly I didnt know what is ungrounded is
You're welcome 😊
Thanks so much
May God bless you 🙏
You are so welcome!
Same to you. We appreciate your feedback. It means a lot to us.
I appreciate you alot 🙏🙏 for this nice teaching
Thank you for your feedback and compliment.
Warm regards.
Life saviour be blessed ❤
Love from India 🇮🇳🇮🇳
Thanks for the explanation great job l thank u so much for the info 💕❤️💪👍
You are welcome. We appreciate your feedback.
I love the way you explained the math
Thanks you sir for making it easy for me to understand
You are welcome.
We are glad you understood it.
We really appreciate your feedback.
WOW 😲 I never knew I will understand statistics ungrounded ungroup data creating a frequency table , finding the mean , Median,mode
Thank you for your time and presenation
You are welcome.
Wow, nice video. More wisdom
A brilliant Lecturer ,meant to do dat.
Thank you for your feedback and compliment.
Warm regards.
Today i understand this fine, thank you very much sir
Mean is :3+4+5+5 +5+6+6+7+8+9/10:10÷58 :
mean : 5.8
3,4,5,5 5,6,6,7,8,9.
9-3=6 range is :6
Media: 5,6
amazing video i like it its easy to understand
Nice clearly explained
You made it so easy to understand
I like your explanation
Thanks for liking.
We really appreciate your feedback.
Warm regards.
Thank you 🙏🏾🇬🇭
superbbbb.thanku
You are welcome.
We appreciate your complement. We will be happy if you kindly subscribe to our UA-cam channel.
Very helpful
Glad to hear that.
We appreciate your feedback.
Warm regards.
Sir
I'm still confused on how you get 129 as the median
I thought it's should be 130
Wonderful
Thank you! Cheers!
We appreciate your feedback.
Thanks so much
You're welcome!
What if the distribution of scores in ungrouped data is bimodal, how to find the value of mode? Example: 5, 3, 2, 5, 7, 2, 8, 11..what is the value of mode?
It has bimodal mode of 2 and 5 as you stated earlier
dumbass
Thank you Sir
Thank you
You're welcome. We appreciate your feedback.
on problem 3 calculating mean why did you the formula of grouped data when its ungrouped data
They have the same formula only the X's are different.
The median:
15÷2=7.5
How did you round it with a whole number to get 8?
Thank you for your feedback.
How or why?
Meanwhile, you are meant to always round off to obtain a counting number.
Sum number 3 I didn't understand the median part. How comes 4 is the median number? I wish you could elaborate more
Thanks
You are welcome.
thank u sir 💜💜
That was simple
Thanks for your feedback.
Warm regards.
Interesting
❤
Won
Please I have an assignment I need help
Yes sir do you any whatsapp group please add me
Thank you sir
Thank you sir
You are welcome.
We really appreciate your feedback.
Warm regards.
Thanks you sir
You are welcome