In the peanut butter analogy, wouldn't it be better to use smooth pb to resemble the positive region? In chunky pb, the bits of peanuts would be electrons embedded in its smooth surrounding.
At 10:27 it's stated that, "If the nucleus was the size of a Ping-Pong ball, the electron would then be the size of a tennis ball." Everywhere I looked, it's stated that a single "proton" is 1835 times the size of a single electron. *So, if the nucleus itself (say Hydrogen, one proton) was the size of a Ping-Pong ball, the* *electron would be WAY LARGER than a teeny-tiny tennis ball. Did I misunderstand the comparisons?*
Hi Mark- Yes, the MASS of the proton is 1835 times the size of a single electron. The size or VOLUME of the proton compared to the electron is something else entirely. I got the ping-pong ball/tennis ball quote from the 1998 Glencoe Chemistry book written by Robert C. Smoot. On page 88, he writes, "...imagine the hydrogen nucleus as the size of a Ping-Pong ball. The electron is roughly the size of a tennis ball, and about 1.35 km away." Subsequent editions don't mention the volume of the proton & electron, probably because it would confuse sharp-eyed students who'd want to know why a bigger object has a smaller mass. On the same page he also writes, "...the radii of the nuclei of atoms vary between 1.2 x 10 -3 pm (or 0.0012 pm) and 7.5 x 10 -3 pm (or 0.0075 pm) The radius of the electron is about 2.82 x 10 -3 pm (or 0.00282 pm) So, the smallest nucleus would be a proton with a size of 0.0012 pm which is 2.35 times smaller than the electron (0.00282/0.0012 = 2.35). And I guess a tennis ball would be about 2.35 times bigger than a Ping-Pong ball. The quantum world is strange, isn't it?
Haha. I think he (Richard) wanted to say that: "If the nucleus was the size of a ping-pong ball, the ATOM would then be the size of a tennis ball." Hence, the distance between the nucleus and the electron, would be the size of 14 football stadiums.
How come the alpha particles don’t seem to be affected by the electrons? Wouldn’t an alpha particle cling to an electron if it came close to it? Or at least wouldn’t it be thrown off course? Is it because the electrons are so small compared to the nucleus that it’s practically impossible to hit one? What would happen if it did hit one?
I don't know, but my guess is that the electrons are far from the nucleus which creates a lot of space in the atom. Thus, the alpha particle is extremely unlikely to encounter an electron. And if an alpha particle did encounter an electron, the alpha particle would be moving so fast that the force of attraction between the two would not be enough to throw it off course. These are just guesses - I really don't know the answer to your questions (and they are pretty good questions!).
I always notice unkempt, dirty nails but you sir are not only smart but clean and well groomed. 👏🏼👏🏼👏🏼
In the peanut butter analogy, wouldn't it be better to use smooth pb to resemble the positive region? In chunky pb, the bits of peanuts would be electrons embedded in its smooth surrounding.
Hmm, that might be a better way to describe the plumb pudding model. Thanks for the suggestion!
At 10:27 it's stated that, "If the nucleus was the size of a Ping-Pong ball, the electron would then be the
size of a tennis ball." Everywhere I looked, it's stated that a single "proton" is 1835 times the size of a
single electron. *So, if the nucleus itself (say Hydrogen, one proton) was the size of a Ping-Pong ball, the*
*electron would be WAY LARGER than a teeny-tiny tennis ball. Did I misunderstand the comparisons?*
Hi Mark- Yes, the MASS of the proton is 1835 times the size of a single electron. The size or VOLUME of the proton compared to the electron is something else entirely. I got the ping-pong ball/tennis ball quote from the 1998 Glencoe Chemistry book written by Robert C. Smoot. On page 88, he writes, "...imagine the hydrogen nucleus as the size of a Ping-Pong ball. The electron is roughly the size of a tennis ball, and about 1.35 km away." Subsequent editions don't mention the volume of the proton & electron, probably because it would confuse sharp-eyed students who'd want to know why a bigger object has a smaller mass.
On the same page he also writes, "...the radii of the nuclei of atoms vary between 1.2 x 10 -3 pm (or 0.0012 pm) and 7.5 x 10 -3 pm (or 0.0075 pm) The radius of the electron is about 2.82 x 10 -3 pm (or 0.00282 pm) So, the smallest nucleus would be a proton with a size of 0.0012 pm which is 2.35 times smaller than the electron (0.00282/0.0012 = 2.35). And I guess a tennis ball would be about 2.35 times bigger than a Ping-Pong ball. The quantum world is strange, isn't it?
Haha. I think he (Richard) wanted to say that: "If the nucleus was the size of a ping-pong ball, the ATOM would then be the size of a tennis ball." Hence, the distance between the nucleus and the electron, would be the size of 14 football stadiums.
How come the alpha particles don’t seem to be affected by the electrons? Wouldn’t an alpha particle cling to an electron if it came close to it? Or at least wouldn’t it be thrown off course? Is it because the electrons are so small compared to the nucleus that it’s practically impossible to hit one? What would happen if it did hit one?
I don't know, but my guess is that the electrons are far from the nucleus which creates a lot of space in the atom. Thus, the alpha particle is extremely unlikely to encounter an electron. And if an alpha particle did encounter an electron, the alpha particle would be moving so fast that the force of attraction between the two would not be enough to throw it off course. These are just guesses - I really don't know the answer to your questions (and they are pretty good questions!).
Legend.... Thank u
thanks so so much :D
excellent
Its already been left in a comment but Ill say again anyways.. Excellent.