you have to divide Q by the moles of a reactant. It doesn't matter if you use Mg or AgNo3, however, if you divide by the moles of AgNO3 you must then multiply your answer by 2 to fit the 1:2 molar ratio. Hope that makes sense! It confused me too
AgNO3 is in excess as it says that all of it is reacted so u use magnesium instead. Towards the bottom it gives u the units for the answer which is kj/mol so you know u have to divide the energy by something. In this case moles of Mg
Soooooo helpful- thank you Sir!
btw this was the last video, your rounding in 22 ii is wrong as 2.2599 is rounded to 2.26, not 2.60.
why do we work out the moles of magnesium ? what suggest that thats what we have to do
you have to divide Q by the moles of a reactant. It doesn't matter if you use Mg or AgNo3, however, if you divide by the moles of AgNO3 you must then multiply your answer by 2 to fit the 1:2 molar ratio. Hope that makes sense! It confused me too
AgNO3 is in excess as it says that all of it is reacted so u use magnesium instead. Towards the bottom it gives u the units for the answer which is kj/mol so you know u have to divide the energy by something. In this case moles of Mg
thanks
D A N K E !
Bitte schon! Good luck with your exams :-)
:D DOUBLE DANKE!
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@@torpedocubing5775 It means thank you in German