For the first question or like always use this trick Make r = 0 or 1 and then substitute that point to each equation and make sure it satisfies both cuz they are same line.
6:37 Bad idea to round each value to a whole number first. That could lead to a wrong answer. For example, 5.4 rounded to 5 and 5.4 rounded to 5 added = 5 + 5 = 10 However, 5.4 + 5.4 = 10.8, rounded to 11. Round after the final calculation. In this specific case rounding first didn't change the answer. But it could with other numbers. On this, you can add another function on Desmos with the a, b, and c. Then do f(-15)+f(-4)
the formulas for the sum of roots when you've got a 2nd degree eq is -b/a, and product of roots is c/a, as we're given the sum of roots (20/3) we know that it's the sum of roots of the eq, we can find the factors by equating each of the bracket = 0 (everytime we get this type of eq), for the eq 2x^2-16x+6p, we can again use the sum of roots formula as it'll givve the sum of values of x without messing with the p, by adding all the values of p we got and the sum of roots of the third eq, we'll add them and equate them equal to the total sum of roots and find the value of p, hopr this helps, I'm not at explaining maths
Good video. I took the SAT and got 760 math, only recommendation is explaining more common less difficult questions because these questions are super obscure and have a next to nothing chance of showing up on the real test.
Thanks, I have a different video going over 10 more common questions. But I wouldn’t say these have no chance at showing up since these questions came from real practice tests and from students who saw these on actual tests.
Yeah I recognize half of them that you pulled straight out of the college board blue book practice tests. I have taken the SAT three times(and over a dozen practice tests) and I feel like these questions are so obscure that you wouldn’t encounter them on the real test. They’re are so many crazy random questions that they can throw at you, so instead of studying each individual crazy obscure one I think that studying a bunch of Desmos tips would help a lot of people more. Just telling you what I think, you did a great job explaining them so keep it up.
There are actually two ways to solve the first problem. You need to plug in x and y, and if I plug in r as y and isolate x - I get x to see if it is the answer meaning if they match they lie on the infite number of solutions. The second doesn't really matther much, but when you write you should include all numbers like 20/3= -p/3 + 8 + 0. The third is to show how to find greatest common factor, don't just say 6. As a student, when I'll be solving these questions I'll get stuck by dividing all the numbers to get 6. Just show desmos gcf(54,216,210) = 6.
First, factor out the GCF of 6. Next, factor the trinomial either using trial & error (which is what is done here) or you can also use the AC method. Do you know how to factor trinomials?
Essentially, what the question means it that 48 (the base value) has to increase by a factor of 27. The way he did it is for complicated situations. The easy way is by simplifying what in the bracket and checking if it is a factor of 27, which in that case 3^3 is 27.
I wish our ЕНТ (UNT) math in Kazakhstan to be like SAT Aside from Calculus ЕНТ is still has harder questions at the same topics, while Desmos is abandoned
If you were to solve each equation for potential x values, you would get x=-p/3 x=3 x=-3 x=8 The question told you that the sum of all 4 of these numbers is 20/3, so you can set 20/3 equal to them 20/3=8+(-p/3)+3-3 The negative and positive 3 cancel out 20/3=8-p/3 20=24-p -4=-p p=4
Well if you still need help just plug in the polynomial over x on your graphing calculator (like 230/x) and go to the table to find y-values that aren't fractions. Those will be your factors.
@nicolej1001 wait that is actually such a great hack, thank you, but I already took my last ever SAT lmao. Still got a good score, but I'll tell my younger sis that
Typically the examples of that question that I've seen have it such that the two points you are given, the -7 point and the 0 point, are symmetric with the x values they ask you to calculate. In other words, plugging in -7 turns both ()'s into (2)^2 = 4. So one of the things they would ask you to find is f(-11) b/c plugging that in would make (-2)^2 = 4, so f(-7) = f(-11). You then wouldn't see (0, y) as one of the points b/c there's nothing you can make symmetric with that. So the point is, in other versions the two values to add (i.e. f(-4), f(-15)) both have x values that have the same y-values as the listed points, so you don't actually have to do any calculating. But for this specific problem, there is no easy way to solve without Desmos.
Typically the examples of that question that I've seen have it such that the two points you are given, the -7 point and the 0 point, are symmetric with the x values they ask you to calculate. In other words, plugging in -7 turns both ()'s into (2)^2 = 4. So one of the things they would ask you to find is f(-11) b/c plugging that in would make (-2)^2 = 4, so f(-7) = f(-11). You then wouldn't see (0, y) as one of the points b/c there's nothing you can make symmetric with that. So the point is, in other versions the two values to add (i.e. f(-4), f(-15)) both have x values that have the same y-values as the listed points, so you don't actually have to do any calculating. But for this specific problem, there is no easy way to solve without Desmos.
Well I basically explained that we are finding which of the equivalent forms displayed 1/c as a coefficient of x that makes the first statement true where when x increases by the value of c the function increases by a factor of 27.
All seem easy, i solved first two under lik 2mins both, i am preparing for iit jee, and for us in India this is not even lowest diffcult question asked
Wow, that’s impressive. I didn’t realize everyone could visualize the functions I showed so effortlessly. I guess everyone in Turkey must be scoring perfect 800s on math.
@@miracfrrayt is a university entrance exam.. youre maybe smart enough to solve the questions but evidently not enough to differentiate between different types of tests
@@JZTESTPrep I'm having trouble with getting the same regression parameters you have. Triple checked my inputs with yours to make sure I entered them in right. Any way to do it without desmos?
The only factors of 35 are 7 and 5 so just think of what the other factors need to be. 9 has factors 1,3 & 9 but only 3 works since we need the middle value to add up to 36.
I don’t wanna be mean but these questions are actually incredibly easy compared to smth even like jee mains(as opposed to jee advanced which is hell personified)
![[March SAT Math] These 3 Questions were JUST added](http://i.ytimg.com/vi/37YoPXLGAk4/mqdefault.jpg)
![[March SAT Math] These 3 Questions were JUST added](/img/tr.png)
For the first question or like always use this trick
Make r = 0 or 1 and then substitute that point to each equation and make sure it satisfies both cuz they are same line.
exactly 👍
my DSAT exam is on 7th December. Thank you so much for such a helpful video.
booklist please
hey can I add you on instagram for some questions?
I'm taking it on December 7 too!
Same here 😢😢😢
@@MuhammadHussain-q1i3g 1. the official digital SAT study guide
2.princeton review
3.the college panda
4.the ultimate guide to SAT by Erica L. Meltzer
6:37 Bad idea to round each value to a whole number first. That could lead to a wrong answer.
For example, 5.4 rounded to 5 and 5.4 rounded to 5 added = 5 + 5 = 10
However, 5.4 + 5.4 = 10.8, rounded to 11.
Round after the final calculation.
In this specific case rounding first didn't change the answer. But it could with other numbers.
On this, you can add another function on Desmos with the a, b, and c.
Then do f(-15)+f(-4)
I agree. A student should use the exact values of f(-4) and f(-15) to add them together especially since this is a student produced response question.
i didn't understand the explanation of the process for the second question but the rest i did understand. i rate this video 4/5 stars thank you
the formulas for the sum of roots when you've got a 2nd degree eq is -b/a, and product of roots is c/a, as we're given the sum of roots (20/3) we know that it's the sum of roots of the eq, we can find the factors by equating each of the bracket = 0 (everytime we get this type of eq), for the eq 2x^2-16x+6p, we can again use the sum of roots formula as it'll givve the sum of values of x without messing with the p, by adding all the values of p we got and the sum of roots of the third eq, we'll add them and equate them equal to the total sum of roots and find the value of p, hopr this helps, I'm not at explaining maths
I like the youtubers who use a little humor while teaching..............it's you.
I was STRUGGLING so hard at Question 2 THANK YOU I hope this is my last time taking SAT
i didnt even use pencil lmao this shi is easy
@@kateyy.-.Exactly I know the benefits of being an asian
@@kateyy.-. why are you trying to flex on people, just keep it to yourself?
@@shivdesai-k6c This is just a complaint about how you take such easy exams and we have to take exams that are 20 times harder
@@kateyy.-. +sat gives you about 1min per question
Good video. I took the SAT and got 760 math, only recommendation is explaining more common less difficult questions because these questions are super obscure and have a next to nothing chance of showing up on the real test.
Thanks, I have a different video going over 10 more common questions. But I wouldn’t say these have no chance at showing up since these questions came from real practice tests and from students who saw these on actual tests.
Yeah I recognize half of them that you pulled straight out of the college board blue book practice tests. I have taken the SAT three times(and over a dozen practice tests) and I feel like these questions are so obscure that you wouldn’t encounter them on the real test. They’re are so many crazy random questions that they can throw at you, so instead of studying each individual crazy obscure one I think that studying a bunch of Desmos tips would help a lot of people more. Just telling you what I think, you did a great job explaining them so keep it up.
thank god
Just took December sat and all these questions were on it 😢
@@Minion_daily lol did you get them right?
underrated video
great video. love the content.
Very helpful video ❤. I need more of these
pls do the 2nd part! this one was extremely helpful
so grateful for the video
Thank you man!
0:38 woahh can we actually use a digital graph in the exam?
Yess you can on the online mode of SAT
So not in the real exam?@hiteshpatil8003
pleaseee solve the question 3 manually- without using desmos
Question 3 (the factoring one) did not use Desmos at all?
how did u find the zeroe for 2x^2 - 16x + 6p
using -b/a = 8? ive never seen that formula in my curriculum, is it widely used in America or sm shit?
-b/a gives u the sum of the roots, so this gives u all the roots of 2x^2 - 16x + 6p added up.
@@manhaagarwal2747 ohh i remember learning that in my junior year, thanks a lot
Can you make video about using desmos i couldn't get no 4
Please make another one of these I NEED a 1500+
1440 rn btw
Make sure to check out my other video going over 10 “hard” commonly tested questions
bro i need a 1100 lol
must be painful to be so damn close and have to retake it lol
There are actually two ways to solve the first problem. You need to plug in x and y, and if I plug in r as y and isolate x - I get x to see if it is the answer meaning if they match they lie on the infite number of solutions. The second doesn't really matther much, but when you write you should include all numbers like 20/3= -p/3 + 8 + 0. The third is to show how to find greatest common factor, don't just say 6. As a student, when I'll be solving these questions I'll get stuck by dividing all the numbers to get 6. Just show desmos gcf(54,216,210) = 6.
Thanks for the feedback.
What if in question 2, the first part of the equation (3x+p) was not there, therfore leading to 20/3 = 8.
Can someone explain the factoring on Q3?
yes i have the same question
First, factor out the GCF of 6. Next, factor the trinomial either using trial & error (which is what is done here) or you can also use the AC method. Do you know how to factor trinomials?
@@IdrisKagalwala Which part are you confused about? The GCF in step 1 or the factoring of 9x^4 + 36x^2 + 35?
@@jwmathtutoring never mind i figured it out i just made the x^ 2 = y at the start
@@jwmathtutoring thanks tho
very helpful. tysm!!
could someone explain the last question? i didnt understand it fully
Essentially, what the question means it that 48 (the base value) has to increase by a factor of 27. The way he did it is for complicated situations. The easy way is by simplifying what in the bracket and checking if it is a factor of 27, which in that case 3^3 is 27.
@iam_kemialiu oh i kind of get it now, thanks!
I wish our ЕНТ (UNT) math in Kazakhstan to be like SAT
Aside from Calculus ЕНТ is still has harder questions at the same topics, while Desmos is abandoned
Why are we adding 8 to -3/P for Q2
If you were to solve each equation for potential x values, you would get
x=-p/3
x=3
x=-3
x=8
The question told you that the sum of all 4 of these numbers is 20/3, so you can set 20/3 equal to them
20/3=8+(-p/3)+3-3
The negative and positive 3 cancel out
20/3=8-p/3
20=24-p
-4=-p
p=4
Can we solve question 4 without using desmos?
Does the online act also has a built in desmos calculator?
I dont understand the 3rd question
Guys PLEASE drop some tips on how to factor big-degrees polynomials quickly and easily please please anything I'm begging🙏🙏🙏
Well if you still need help just plug in the polynomial over x on your graphing calculator (like 230/x) and go to the table to find y-values that aren't fractions. Those will be your factors.
@nicolej1001 wait that is actually such a great hack, thank you, but I already took my last ever SAT lmao. Still got a good score, but I'll tell my younger sis that
where did you get these questions from?
would you be able to solve question 4 without desmos?
Typically the examples of that question that I've seen have it such that the two points you are given, the -7 point and the 0 point, are symmetric with the x values they ask you to calculate. In other words, plugging in -7 turns both ()'s into (2)^2 = 4. So one of the things they would ask you to find is f(-11) b/c plugging that in would make (-2)^2 = 4, so f(-7) = f(-11). You then wouldn't see (0, y) as one of the points b/c there's nothing you can make symmetric with that. So the point is, in other versions the two values to add (i.e. f(-4), f(-15)) both have x values that have the same y-values as the listed points, so you don't actually have to do any calculating. But for this specific problem, there is no easy way to solve without Desmos.
how to use 2nd question for desmos?
I got a 780 in maths 2nd try because i watched this video like 2 days before my exam.
Wow! Glad I could help
how would you do 4 without desmos?
For question 4 what gave it away that you couild use a regression?
We were given the function and two points on it
is there a way to solve QN. 1 without desmos. easy yes, but tedious. is there an easier way?
just plug in each values from the answer choice and check if lhs equals rhs
I dont get question 3
Just factor the expression
last question, isnt 9 a factor of 27?
That’s not what the question is asking when it’s says by a factor. It’s saying the function increases by 27 times the base value.
hello can we do 2 th question with desmos
You can but in my opinion it is much more tedious and is easier with the method I showed.
@@JZTESTPrep can u show how can i do this question with desmos
Can u use desmos on the sat?
Yes for every question
how can we calculate 4 without desmos?
Typically the examples of that question that I've seen have it such that the two points you are given, the -7 point and the 0 point, are symmetric with the x values they ask you to calculate. In other words, plugging in -7 turns both ()'s into (2)^2 = 4. So one of the things they would ask you to find is f(-11) b/c plugging that in would make (-2)^2 = 4, so f(-7) = f(-11). You then wouldn't see (0, y) as one of the points b/c there's nothing you can make symmetric with that. So the point is, in other versions the two values to add (i.e. f(-4), f(-15)) both have x values that have the same y-values as the listed points, so you don't actually have to do any calculating. But for this specific problem, there is no easy way to solve without Desmos.
bro in question 5 u said the wording is pretty tricky and tried explaining it and u literally re read the question without explaining nothing
Well I basically explained that we are finding which of the equivalent forms displayed 1/c as a coefficient of x that makes the first statement true where when x increases by the value of c the function increases by a factor of 27.
U made an error on question 2 . -16/2 = -8 but u said it equal to 8
There are two negative signs so -(-16) is positive 16.
All seem easy, i solved first two under lik 2mins both, i am preparing for iit jee, and for us in India this is not even lowest diffcult question asked
Yeah the SAT only goes up to algebra 2 concepts so it’s definitely much easier than the JEE test
@@JZTESTPrep Thank for video btw
@Arnav2322 no problem
bro what kinda hardest questions are those we (turkish students) can almost solve those problems in our mind
Wow, that’s impressive. I didn’t realize everyone could visualize the functions I showed so effortlessly. I guess everyone in Turkey must be scoring perfect 800s on math.
question 4 is not easy
@@Cine95 you can look to the ayt 2024 exam bro its harder than it
@@miracfrr well yeah traditional country tests are hard but some questions on sat are really hard
@@miracfrrayt is a university entrance exam.. youre maybe smart enough to solve the questions but evidently not enough to differentiate between different types of tests
Can anyone help me for no 4
Yeah what part of it are you struggling with?
@@JZTESTPrep I'm having trouble with getting the same regression parameters you have. Triple checked my inputs with yours to make sure I entered them in right.
Any way to do it without desmos?
@@JZTESTPrep wait never mind I renetered it and it worked. Could we get a tut on doing it by hand- no desmos though?
These videos are amazing, but for question 5, collegeboard's explanation more understanding than yours. Thanks a lot for this videos buddy.
Bro the math section was a joke, got a perfect score on it on my first PSAT as a sophomore 😂
That’s awesome. The real SAT is usually a bit more challenging, so it’s still a good idea to keep studying but you’re definitely on right track.
How did you FOIL that @4:06?
The only factors of 35 are 7 and 5 so just think of what the other factors need to be. 9 has factors 1,3 & 9 but only 3 works since we need the middle value to add up to 36.
@@JZTESTPrep I'm lowkey lost, is there any video explaining this strat?
@@beyondhumanity7025 me too tell me if u found a video @jztestprep
please get a writing pad
they need to remove the use of desmos so fast on the SAT, it's just plain stupid and abused for questions that definitely don't need it.
the test is literally 30 minutes for 27 questions, you’re not solving any of these by hand and finishing the test
yes dude the vid was terrible! just playin, whered u get those problems from? finally som1 with realistic stuff
Thanks. #1,2 and 5 came from blue book prac tests. #3 and 4 came from people who took the actual test in Novemeber and October and saw those questions
senior taking dec sat in 6 hours chat am i cooked
Nah u cooked on the SAT fs
Are you kidding me? Its hardest? This is even below boards level in india
I don’t wanna be mean but these questions are actually incredibly easy compared to smth even like jee mains(as opposed to jee advanced which is hell personified)
SAT math questions aren’t overly difficult, as they only cover concepts up to Algebra 2, which most people have a solid grasp of.
No shit you literally have like a minute per question max, they’re not gonna give „hard“ questions witg that little time
Why did you redeem it? Why did you redeem it?
SAT is a joke
terrible