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JZ TEST Prep
Приєднався 11 бер 2024
JZ TEST Prep provides FREE SAT & ACT Preparation materials and guidance.
Partnerships: jztestprep@gmail.com
Partnerships: jztestprep@gmail.com
[December SAT Math] 5 Hardest SAT MATH Questions (2024)
In this video, I break down the 5 hardest SAT Math questions that you absolutely need to know before the December SAT 2024! Whether you’re aiming for a perfect score or just trying to boost your score, these questions will help you master key concepts and strategies that appear frequently on the SAT.
📚 Personalized SAT/ACT Prep: crackd.it/#/?ref=jztestprep
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Join my FREE Google Classroom: mvi6sng
If you found this video helpful, hit the 👍 button, and don’t forget to subscribe for more SAT tips and tricks! Leave a comment if you have any questions or topics you’d like me to cover next.
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00:00 Intro
00:21 Question 1
01:04 Question 2
02:38 crackd
03:06 Question 3
04:39 Question 4
06:39 Question 5
#decembersat #SATMath #sat
📚 Personalized SAT/ACT Prep: crackd.it/#/?ref=jztestprep
_______________
Join my FREE Google Classroom: mvi6sng
If you found this video helpful, hit the 👍 button, and don’t forget to subscribe for more SAT tips and tricks! Leave a comment if you have any questions or topics you’d like me to cover next.
_______________
00:00 Intro
00:21 Question 1
01:04 Question 2
02:38 crackd
03:06 Question 3
04:39 Question 4
06:39 Question 5
#decembersat #SATMath #sat
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[December SAT Math] 10 Must Know SAT MATH Questions (2024)
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In this video, I break down 10 essential SAT Math questions that you absolutely need to know before the December SAT 2024! Whether you’re aiming for a perfect score or just trying to boost your score, these questions will help you master key concepts and strategies that appear frequently on the SAT. Join the FREE Google Classroom: mvi6sng If you found this video helpful, hit the 👍 button, and d...
For Question 8, the 2 roots are shown as 1 and -3. y = a (x-1)(x+3) = 2 (x^2 + 2x - 3) = 2x^2 + 4x - 6 Thus, bc = 4(-6) = -24 We can also apply sum and product of solutions. SUM = -b/a = -b/2 = 1-3 = -2 Thus, b = 4 PRODUCT = c/a = c/2 = 1(-3) Thus, c = -6 Hence, bc = -24
For Question 4, b = 0.89c b+c = 1.89c a = 24.03(b+c) a = 24.03(1.89c) a = 45.4167c a = 45.4167(b/0.89) a = 51.03b Thus, a is 5103% of b
For Question 1 without a calculator (56)(56) - 4(16)k < 0 4(14)4(14) - 4(16)k < 0 14(14) - 4k < 0 7(7) - k < 0 k > 49
what the f, we are not allowed to use any internet source in the exam
What internet source was used? Desmos is given to you to use
p equals to 13 cuz the third equatin has 2 solutions
Please, then what's the 48 for??
Thanks, dude. i was struggling to solve most of these problems in the practice test, and the question bank doesn't do a good job in explaining the answer or their own answer is lengthy . Im not very good with desmos, so this video really helped me. Im writing my first ever SAT on march 8.
Are you kidding me? Its hardest? This is even below boards level in india
great video. love the content.
I got a 780 in maths 2nd try because i watched this video like 2 days before my exam.
Wow! Glad I could help
But can it be easy and one more questions will be there a universities who will accept without sciense exam
where did you get these questions from?
What if in question 2, the first part of the equation (3x+p) was not there, therfore leading to 20/3 = 8.
I wish our ЕНТ (UNT) math in Kazakhstan to be like SAT Aside from Calculus ЕНТ is still has harder questions at the same topics, while Desmos is abandoned
Does the online act also has a built in desmos calculator?
All seem easy, i solved first two under lik 2mins both, i am preparing for iit jee, and for us in India this is not even lowest diffcult question asked
Yeah the SAT only goes up to algebra 2 concepts so it’s definitely much easier than the JEE test
@@JZTESTPrep Thank for video btw
@Arnav2322 no problem
My both modules were of average difficulty level or English but in maths mod 1 was easy and mod 2 was difficult 😅 Now what should I expect?
Bro i just took the DEC 7 SAT u guys still didn’t take it? What time is it in america
senior taking dec sat in 6 hours chat am i cooked
Nah u cooked on the SAT fs
for number 23 at 10:53, you can graph the two equations into desmos and make x any value you want for both equations. then you can make p a slider for both and test out all the answer choices. the correct answer is the one where the two functions fit right on top of each other on the graph. this may be much easier to do.
terrible
Dec SAT is in 1 hour guys
Good luck
I dont understand the 3rd question
Thank you so much @JZ Test Prep I almost forgot the formula of Vietan. ax^2+bx+c And let p and q be the roots. the Vietan's formula states that pq = c/a p+q = -b/a I hope this helps.
in 10th question why is the formula -b/a, shouldnt it be -b/2a
No. -b/a is the sum of solutions. -b/2a is the formula for the x coordinate of the vertex.
U made an error on question 2 . -16/2 = -8 but u said it equal to 8
There are two negative signs so -(-16) is positive 16.
Bro the math section was a joke, got a perfect score on it on my first PSAT as a sophomore 😂
That’s awesome. The real SAT is usually a bit more challenging, so it’s still a good idea to keep studying but you’re definitely on right track.
bro what kinda hardest questions are those we (turkish students) can almost solve those problems in our mind
Wow, that’s impressive. I didn’t realize everyone could visualize the functions I showed so effortlessly. I guess everyone in Turkey must be scoring perfect 800s on math.
question 4 is not easy
@@Cine95 you can look to the ayt 2024 exam bro its harder than it
@@miracfrr well yeah traditional country tests are hard but some questions on sat are really hard
@@miracfrrayt is a university entrance exam.. youre maybe smart enough to solve the questions but evidently not enough to differentiate between different types of tests
Guys PLEASE drop some tips on how to factor big-degrees polynomials quickly and easily please please anything I'm begging🙏🙏🙏
Well if you still need help just plug in the polynomial over x on your graphing calculator (like 230/x) and go to the table to find y-values that aren't fractions. Those will be your factors.
@nicolej1001 wait that is actually such a great hack, thank you, but I already took my last ever SAT lmao. Still got a good score, but I'll tell my younger sis that
last question, isnt 9 a factor of 27?
That’s not what the question is asking when it’s says by a factor. It’s saying the function increases by 27 times the base value.
SAT is a joke
I was STRUGGLING so hard at Question 2 THANK YOU I hope this is my last time taking SAT
i didnt even use pencil lmao this shi is easy
@@kateyy.-.Exactly I know the benefits of being an asian
@@kateyy.-. why are you trying to flex on people, just keep it to yourself?
@@shivdesai-k6c This is just a complaint about how you take such easy exams and we have to take exams that are 20 times harder
@@kateyy.-. +sat gives you about 1min per question
please get a writing pad
so grateful for the video
Nah we alright, we got ai
wow, i fully learnt something new. thanks bro.
i am not sure when can i just plug my own value in
Can u use desmos on the sat?
Yes for every question
0:38 woahh can we actually use a digital graph in the exam?
Yess you can on the online mode of SAT
So not in the real exam?@hiteshpatil8003
would you be able to solve question 4 without desmos?
Typically the examples of that question that I've seen have it such that the two points you are given, the -7 point and the 0 point, are symmetric with the x values they ask you to calculate. In other words, plugging in -7 turns both ()'s into (2)^2 = 4. So one of the things they would ask you to find is f(-11) b/c plugging that in would make (-2)^2 = 4, so f(-7) = f(-11). You then wouldn't see (0, y) as one of the points b/c there's nothing you can make symmetric with that. So the point is, in other versions the two values to add (i.e. f(-4), f(-15)) both have x values that have the same y-values as the listed points, so you don't actually have to do any calculating. But for this specific problem, there is no easy way to solve without Desmos.
I don’t wanna be mean but these questions are actually incredibly easy compared to smth even like jee mains(as opposed to jee advanced which is hell personified)
SAT math questions aren’t overly difficult, as they only cover concepts up to Algebra 2, which most people have a solid grasp of.
No shit you literally have like a minute per question max, they’re not gonna give „hard“ questions witg that little time
Why did you redeem it? Why did you redeem it?
6:37 Bad idea to round each value to a whole number first. That could lead to a wrong answer. For example, 5.4 rounded to 5 and 5.4 rounded to 5 added = 5 + 5 = 10 However, 5.4 + 5.4 = 10.8, rounded to 11. Round after the final calculation. In this specific case rounding first didn't change the answer. But it could with other numbers. On this, you can add another function on Desmos with the a, b, and c. Then do f(-15)+f(-4)
I agree. A student should use the exact values of f(-4) and f(-15) to add them together especially since this is a student produced response question.
they need to remove the use of desmos so fast on the SAT, it's just plain stupid and abused for questions that definitely don't need it.
the test is literally 30 minutes for 27 questions, you’re not solving any of these by hand and finishing the test
Can someone explain the factoring on Q3?
yes i have the same question
First, factor out the GCF of 6. Next, factor the trinomial either using trial & error (which is what is done here) or you can also use the AC method. Do you know how to factor trinomials?
@@IdrisKagalwala Which part are you confused about? The GCF in step 1 or the factoring of 9x^4 + 36x^2 + 35?
@@jwmathtutoring never mind i figured it out i just made the x^ 2 = y at the start
@@jwmathtutoring thanks tho
how did u find the zeroe for 2x^2 - 16x + 6p using -b/a = 8? ive never seen that formula in my curriculum, is it widely used in America or sm shit?
-b/a gives u the sum of the roots, so this gives u all the roots of 2x^2 - 16x + 6p added up.
@@manhaagarwal2747 ohh i remember learning that in my junior year, thanks a lot
how to use 2nd question for desmos?
Why are we adding 8 to -3/P for Q2
If you were to solve each equation for potential x values, you would get x=-p/3 x=3 x=-3 x=8 The question told you that the sum of all 4 of these numbers is 20/3, so you can set 20/3 equal to them 20/3=8+(-p/3)+3-3 The negative and positive 3 cancel out 20/3=8-p/3 20=24-p -4=-p p=4