At 3:06, don't you assume there that the set of all natural numbers is infinite, which in turn makes your original claim about the boundary existing already false, which therefore means your contradiction must occur? Wouldn't you have to prove that the set of all natural numbers is infinite before making that claim?
Great video
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At 3:06, don't you assume there that the set of all natural numbers is infinite, which in turn makes your original claim about the boundary existing already false, which therefore means your contradiction must occur? Wouldn't you have to prove that the set of all natural numbers is infinite before making that claim?
I actually assume that the natural numbers are bounded which leads to a Contradiction with the fact that natural numbers are closed under addition.
There are infinite bounded sets, take que rational numbers between 0 and 1, there are a infinite numbers of them but they are bounded between 0 and 1