Organic Chemistry II - Solving a Structure Based on IR and NMR Spectra
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- Опубліковано 11 сер 2015
- In this video I determine a plausible chemical structure for an organic compound based on the given IR and H NMR spectra.
For a copy of the tables I used, click here: drive.google.com/file/d/0BwOc...
Nmr is the bane of my existence, I'm never going to become a chemist
I agree. NMR for me is like riding a bike without the seat, if you know what I mean.
I hate ittt so much, IR spec is so much easier and when I got to NMR I was like pls… god no…
Honestly it’s so easy once you do the “I am ___H next to ___H’s it gets to easy
Wooow these explanations are so good, like I am so happy I found this video! Thank you so much!!
thank you for this video, I have an exam on how to find the structure of molecule using both nmr and IR, mass spectre, this video was what I searched
This was very helpful! I'm looking forward to more videos :)
You have saved my life.. This is so much easier to understand than my professor.
Thanks for the comment Kaytlyn! I'm glad to hear you found this video helpful. If there are any other topics you'd like me to make videos about feel free to email me at tony.chemistryexplained@gmail.com
I'm agree with you hahaha my professor so....................... Jshahakbsenhaksshwkjs
Keep it up, Dr John. Well explained.
I love how you broke everything down! Made it so much easier to understand, thank you so much!!
You are very welcome!
Thank you for the great video. I learned many things from you.
Wow you walk through this with great explanation. Do you have more videos with these types of problems
?
You saved my life. Thank you very much.
Man be saving lives even after 7 years
Tysm for explaining in a very easy and basic manner. It ready helped me a lot.❤
I love you this is the best EVER!!!!!!! very helpful I wish you the best in life Tony I can't thank you enough.
I watch your videos at 2021 and found this very useful. keep doing good !
exactly!! better than how my lecturer explained to me!
Oh wow this video has lots of views! You were a great professor at WWU. Keep it up!
view digger be gone
This is just what I need.. thank you so much..
You are very welcome! I'm glad it was useful.
Very much helpful to learners like me thank you for such a great video
You are very welcome! Thank you for the nice comment!
SIR, we need more videos with other examples... practicing more these problem with you makes it more easier.
reallllllll
you made me pass my exam
god bless
You are great!! thanks :D
This is just what I needed to review for my final tomorrow. Thank you for the helpful video
You are very welcome! Good luck on your final!
No because there are no H's on the adjacent carbon. The H's on the ring are on non-adjacent carbons and therefore are too far away to cause splitting.
Great content! was very helpful.
Just take my money. This is worth the time in gold.
Do you have a pdf of the sheet you were using with those values?
U ARE AMAZING :) thanks a lot
You are very welcome! Good luck with your studying!
You're a superman... Thanks alot
Ha! I don't know about superman, but you are very welcome!!
So helpful thanks a lot!!
Thank you so much😭❤️❤️ i have a final exam tomorrow and i was really worried, i get it know. Anddd i like your pen
I have several IR spectrum gotten from my research which I have grafted polyacrylamide onto Hydroxyethyl cellulose how to completely assign the spectrum
Love u Tony, thanks so much
may God bless your soul you helped me so much
You are welcome!
Really clear and quick, but I think you could manage finding out the products that comes out with the tautomerization process, to be sure that is effectively a carbonyl group, and also to avoid any possible viewer doubt about the other signals.
that's my opinion
its sooo Easy thanks
I have some 14-day old urine in the refrigerator, I want to drug screen it via GC/MS. Will the results still be valid? What is Forensic protocol, in regards to length of time a sample is valid?
My professor gives us the NMR data, but asks us to figure out IR ourselves first, it isn’t given. Also we have to memorize all of the NMR and IR numbers, we don’t have a chart given to us to use on the exam. I have yet to find a video that explains how to come up with an plausible organic structure using only given NMR data to come up with IR data.
Morgan Gill that will definitely make it more challenging! But, depending on the compound there is a lot of good info you can get from just the NMR. If you want to send me an example problem I can take a look today and make a new video for you! You can email me at Tony.chemistryexplained@gmail.com
Same here ,I have to memorize all the HNMR, CNMR ,IR , Mass Fragmentation values , do they see us as machines ?
Thank you for replying! I never saw it! I finally got it after I looked at it a bit more, and now it’s easy! I ended up with an A in the class, PTL. Thanks for uploading this video!
@@LoveAustralian Would you be able to give a few pointers on how to solve these problems? If not, could you direct me to a UA-cam that can? I am currently in the same boat as you were. Thank you
Afiya Fox I’d have to see an example problem, it’s been 8 months since I last did NMR and IR! However, I’m sure this professor would be willing to help if you emailed him! He said his email is Tony.chemistryexplained@gmail.com Best of luck! (As for recommended UA-cam videos, I actually pulled up charts on google of NMR to IR, if I remember correctly, and practice problems on Chegg of IR to NMR and that helped too!)
What if you do not have labelling for your NMR-spectra?
thanks u soo much ... u save my life
Haha, you are welcome Ahab! Glad you found it helpful.
Hi Tony,
I have to admit, a very nice explanation. However, I wonder how you know that the propyl group and methyl group at 2.3 ppm are not swapped? The shift difference between CH3-C=O and CH3-Ph is very small (2.1 and 2.3 ppm respectively, according to your shift table) and, in my experience, the shift alone cannot be decisive in such cases. Is your structure based on some additional spectra, e.g. HMBC?
Hi Nebojsa Simic! I think the easiest way to answer your question is to look at the integration and splitting patterns of those peaks you are questioning. The peak that I have assigned as the aromatic methyl group integrates to 3H and is a singlet, while the peak that I have assigned to the CH2 group next to the carbonyl carbon integrates to 2H and is a triplet (splitting from the adjacent CH2). Does that answer your question? Hopefully it helps!
Me too i feel the same .. since ch3 can give s at 1 if only propyl was para to ester
Would degrees of unsaturation be necessary in validating the structure? If so, why am I getting a large number when calculating the d.o.u. ?
Akwi Njoh I believe you’d get 5 - this accounts for 1 ring, 3 pi bonds in the ring, and 1 double bond in the carbonyl group
In this video I determine a plausible chemical structure for an organic compound based on the given IR and H NMR spectra.
In examination, they don't give us the chart.I'm so terribly confused😨
can you pls put the copy of the problem again, the link doesnt work. thank you
I have no idea about nmr (H1, C13), no base, this subject is new to me. But I have a spectra of my compounds, how can I solve it?
Hi Maria, if you are able to email me your spectra I would be happy to make some easy explanations of the theory of NMR! Just email me at tony.chemistryexplained@gmail.com
okay
Thank you ❤️
Hello Tony. Usually at our exams what we get, is the molecule and we have to give the chemical shift, Multiplicity (s,d,t,q) and the integration (1H, 2H, 3H etc). I have been looking through youtube without finding an example that shows how to solve such problem. Also we get the nmr spectra by itself without an IR. Can you please help?
Hi Farah, of course! Do you have a specific molecule example that you'd like me to make a video of? I will try to find something to post tomorrow in any case! Here is another video that I recently made that just deals with an NMR spectrum that might help as well: ua-cam.com/video/ZcNIariMkSc/v-deo.html
Oh You answered. Thank you so much. Well, I have 2-3 examples actually from previous exams with the answers as well - that doesn't help me that much, as I want to understand it and solve it myself. Do you have an e-mail I can send you these examples? Thank you again for replying ...
Hi Farah, you can email me at tony.chemistryexplained@gmail.com
If 2 imine group is present and both attached with benzene ring. What would be expected peak. In IR
Helpful
cool!!
Can't we switch the R groupe? Ch3 with co and o . And ch2ch2ch3 in the para side?
Assalamualaikum Tony.
I want to get solution of alkyl halide Spectra's by NMR.. I have to present it by next week. Can you please help me..
tnx a lot for your useful video..how can I access to your handout?
hi, love the video. i'm confused by one small item though, why is the methyl group attached to the benzene a singlet? is it not affected by the neighbouring protons on benzene?
It’s not affected because the other hydrogens are not 3 bond neighbors to the ones in the methyl
Gracias! Mis profes no tienen idea como explicar
informative
can I contact you Tony St. John, I have some problem in explanation of my FTIR chart
Hi Anees! Feel free to email me at Tony.ChemistryExplained@gmail.com
acc. to final structure there must be a quartet (ch3-ch2-)
The chain in question is actually H3C-CH2-CH2- so the middle carbon's hydrogens are split by both the 3 hydrogens to their left and the two to their right. Thus it would be a multiplet, not a quartet.
The -CH3 attached to benzene ring should have (2H,d) and not singlet is'nt it?
Nope! The label (2H, d) would mean the integration is 2, and the splitting pattern is a doublet. Since the -CH3 attached to the benzene ring has 3 H's, it should integrate to 3 (3H), and since there are no H's on the carbon in the ring that the -CH3 group is attached to there will be no splitting and will therefore be a singlet (3H, s). Hope that makes sense!
thank you sir, I understood my mistake. There are 3H's typing mistake and doublet i took the adjacent carbon splitting. Thank you sir for your reply and explanation.
♥
How do you know there is a ring and not a double bond?
Hi Allison, the peak at 1600 in the IR spectrum tells us there is a ring!
Thank you!
Also, if you do the HDI you can kind of guess if it is a ring if it is greater than 4.
They don't give us table any way to memorize it
Plz explain uv spectroscopy
Structures of dien & enone plz
hi, where could i get a copy of that table?
+Nav Seira Here is a link to the tables!
drive.google.com/open?id=0BwOceMKQTVFxRTh1Szl4aTh0eE0
***** thanks!
good please sent me the problem of this?
محمد الكيمياوي عربي مفتهم الماده خويه
We are doing this type of stuff in Ochem 1 and we don't get a table!!
I'm so fcked for tomorrow lol, I hate how we have to memorize all the fragments, CNMR, HNMR spectra values like can't we have a chart or something? :'(
I dont know sir.......how explain ???????
Why is it sp3? Sp2? I'm not understanding this part. You just kinda stated it.
Sir, is it possible for you to email me the reference table that you use in the video? Please. I really need it
If you click on "Show More" in the video description I have posted copies of the reference tables!
Could you do one just from analytical data, no graphs ?
Yes
I liked that pen
1759 is HC=N
Sir I am a research scholar, I have lot of confusion in nmr interpretation and IR interpretation ,can you help me
Praise Be Tony St. John, Savior of the Orgo Students!
Soru göndersem cevaplar mısınız
If only we could use a cheat sheet
why/
It is very very hard
Sir C9H11BR
im so high
Me and all my homies hate NMR
this did not help at all