IIT JEE Advanced aspirants Only | Introduction to Deep thinking.
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- Опубліковано 9 вер 2024
- This is one of the Snippet of the math Simplified program that we used to offer. I hope you'll learn something new from it.
Link of Set of 60 Program - www.jeesimplif...
I know this video won't get many views.
but, for my love of math, I uploaded it
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Pta nai , sayad mene ye video phele dekhi hai
How to score almost full in jee advanced maths ?
Correction 9:50 in 1st case y is from 1 to infinity. Not from -ve infinity to 1. 😊
One more thing what I noticed is min. Value of |x|+...|x-n| will at f(n/2).
I found this one year ago in 11th in function chapter. So you may add that.
The Fibonacci numbers were first described in Indian mathematics as early as 200 BC in work by Pingala on enumerating possible patterns of Sanskrit poetry formed from syllables of two lengths.
Google op 💀👍
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Bro this is fake in 19 century many books were published in India claiming to discover something in past like vimana shastra etc every thing were fake
😂😂😂😂😂😂
I learnt this in java in grade 8 and fiorgot thanks
one thing i noticed is
0+1 = 1
1+1=2
2+2= 4
4+2=6
6+3=9
9+3=12
12+4=16
pehle do me 1 , 1 add hua , phir 2, 2 phir 3,3 phir 4,4!!
if anybody can simpify it more that would be great
There are patterns everywhere....the reflection of light , particles of sand , etc
In maths these patterns reveal themselves in the most beautiful form ...thats interesting
Sir sri niwasa ramanujan
9:21 y can never be negative... Also x is negative hence -2x is always positive
Yes you are right brother
Yes
I was also confused at that point
Aur yeh kehta h ki meri maths bhut strong h😂
Literally got goosebumps thankyou verry muchh please create this kind of videos frequently it will help us to build deep thinking ❤🔥❤🔥
When saw the values 13:16 , i saw a pattern emerging -
0 x 1 = 0
1 x 1 = 1
1 x 2 = 2
2 x 2 = 4
2 x 3 = 6
3 x 3 = 9
3 x 4 = 12
4 x 4 = 16 Each number first gets multiplied to its successor, then the successor multiplies to itself and so on
DAMN BROTHER this one is a pretty nice observation in my opinion
I noticed a pattern in the modulus series
|x| + |x-1| + ...+ |x-n|
If n = 2k i.e. even
Then the minimum value will be k(k+1)
And if n=2k+1 i.e. odd
Then the minimum value will be (k+1)^2
For n=21
21=2k+1: k= 10
Thus (10+1)^2 = 121
Also the wierd thing i found was the minimum value always occur at x=k..that is the graph
is always symmetric about about the mid point term in case of odd "n" and symmetric at the mid point of k-1 and k in case of even "n"
Which makes sense if we think about it..
Bhai IIT tuhi clear karega.
I also noticed same when it was taught in coaching plus I am in 10th
10th se hi coaching..wahh
@@arpittttt
@@prathamshah216 9th se -
@@prathamshah216 one of my friend in my class sits in 11th class batch of a local coaching too 🤠
Another pattern emerges from here. If you look closely you'll find, the terms which are not a perfect square are actually the product of the roots of the neighbouring terms. For example let's take the 5th expression from here 14:44, It is the product of 2 and 3 whose squares are written just above and below 6.
This is just an observation and i might be wrong but i check for some values in desmos and it does seem to follow this pattern.
Legends know this lecture is already in math simplified course
I'm in class 10 and i got a project on fibonacci art - bihar 👀😂 bihar integrated project cbse
its quite simple though why perfect squares are appearing they are coming up with those with even terms bcz ofc the minimum value i hope anybody could see it'd appear in the mid value like for |x|+|x-1|+|x-2|+|x-3| it'd be 1.5 so distance from midpoint to a no. would have 0.5 decimal now we need to go right and left so doubling that would always result in an odd no. And what wxactly is an odd no. series its a square :)
Mode lxl to lx-21l= 121
7 crore ⛈️⛈️
Jaat bhai 🔥🔥🔥💥💥💥💯💯💯
Great video as always, but I think this is the 2nd time of making a video like this, and the older video also had some content, I thought a new illustration was mentioned in this video. Cheers!
A great way of questions thinking and thought process towards math concept you are math lover as well as a genius
And Very much thanku Bhaiya for these kind of videos as I think many educational institiutions lack giving these contents which will help many JEE Aspirants who lack deep thinking during question solving.....👍
(2n - 1)^2 where (2n+1)gives the highest numerical value of the modelus.
i thought many people would know the method to calc the min. value of modulus functions but as it doesn't seem to be the case, lemme help:
Simply plot the turning points(0s) of the individual mods on the no. line for 2 mods. eg:
|x-2| + |x-3|
now what you get on the no. line is the 2 zeroes: 2, 3.
1] Consider a no. b/w 2 and 3,eg , 2.5, 2.6, 2.3, etc putting these no. as x, we find it will always result in y = 1 i.e |2-3|
2] consider a no. 3, and put it as x, this will always result in y = 1.
Hence we can conclude the same for
y = |x-a| + |x-b|
y min is |a-b|
I was taught this in my coaching centre, pretty simple method to understand and play with it a bit more and understand what's happening to get to the method of finding min val of |x-3| + |x-55| + |x-74|
Thanks for reading xd. I hope I was able to help you!
I also remember this
Bhaiya ye video phele hi dekh liya tha ye re-uploaded h ❤
Isme even walo ke liye pattern Aisa hai 1*2 2*3 3*4 ..... x-8 ka 20 hoga x-10 ka 30 hoga x-12 ka 42 hoga and so on.... To generally (n/2)*((n/2)+1) hoga even ke liye
Min value of molulus series till |x-21| = 121
The pattern that I observed was that:
The term which are not perfect squares are actually the difference of their next term with its square root.
9:20
There is a contradiction for first case you wrote y = (-infinity, 1) I think this is not ok. For X
When n is even, then Tn = (n/2) ka whole square.
And when n is odd, then Tn = (a)n-2 + (n - 1) where n is the no. Of terms and a1 = 0 fixed. Thanku bhaiya for making this video. 🙏 Mera laga nhi tha mere se bann jayga but Maine bnaya . Ab Mera confidence bhut bhut badh Chuka h. Again thanku
Thus, |x| + | x-1| +.......+ |x-21| = 121
No. Of total terms |x| to |x-21| = 22.
Then according to general term, n is even then (n/2) ka square = (22/2) ka square = 121.
I've got another pattern:
2 baar +1
Phir 2 baar +2
Phir +3
And according to this:
12+4=16 next will be 16+4=20 and Yes Then, 20+5=25..!
Edit:
Generalized result as-
If term is even then it's direct (n/2)²
If odd suppose 5001th then nearest even (to be precise predecessor has to be taken) here 5000, then
(n/2)² + (n/2) this gives (5000/2)² + (2500) i.e, 6252500
same
I've also identified this one
When we plot these graphs and numbers is greater and greater it looks like parabola!!!!
i noticed a pattern that for |x-n| where n is an odd no. if you round up (n/2) and square it you get the minimum value
Are nhi !
Ye hoga 👇
[ (n+1)/2 ] ka square na where n is odd number
@@PrinceGuptaFilms multiple ways ho sakta hai same problem ke liye shayad
HOMEWORK ANSWER:- 121
If number of terms is even then answer will be (n/2)^2
bilkul dhaga khol diya.....it wa really amazing🤯...please bring more such videos
bhaiya iss series m ek aur pattern dekhiye de rha h
for example |x| + ........ |x-9| so 9 is the 5 odd number i.e the ans will be [5]² { ye apne video m bataya tha}
for |x|+......|x-8| so 8 is a even number ,even numbers pe pattern uske aagli wali series se ban rha h
[5]² - 5
i.e pattern for |x|+.......|x-n| = [m]²- m
n+1 is the m th odd number
there is one more pattern jo non perfect square number hai wo apne aage wale perfect square number se utna hi piche hai aur apne piche wale se utna hi aage ( 2 jo hai 1^2 se 1 aage hai or 2^2 se 2 piche hai same for 6 2^2 se 2 aage hai hai aur 3^2 se 3 piche hai.
Ans is 11×11
10:19 sir |x|+|x-1| toh always +ve hai toh range when x
I was searching for these types of vodeos of jee topics explained in shorts
Wow😮 want more of these type of videos ❤️
bhaiya please recomend everyone jee quest maths fundae because sir is doing more hard work for student. sir 22 years of teaching experience and also he is memeber of american mathematical society .sir is laso new on youtube.
There's also something like deep work
Read this stuff in JAVA as a part of my 10th Computer Syllabus..
Pata nhin tha ki yeh advanced Maths mein iss Tarah Kaam karega..
Sir in this series 2 consecutive numbers ki difference same aa rahaa hai like
1-0=1
2-1=1
4-2=2
6-4=2
9-6=3
12-9=3 ..............
See the difference pattern in answers..
Now my favourite channel
Bhaiya this video unlock the new thinking level
This fibonacci series is used as pattern in stock markets
I also noticed the squaring pattern in just 1 minute😄
Idk why this vedio was different from others , and effective too , I'm surely gonna do the homework u gave 😂❤️ , good job bhaii
Ashish sir taught this in class
i would like to say is that |X| is non-negative rather than positive
modulus 21 tak ka ans hoga 121....cause n=21, then ans -- [(n+1)/2]^(2) ....and for the even ones pichle wale terms ke sath n/2 add kardo
Bhaiya I noticed another pattern .
The min value of fuction when it ends with the even no. is = T + (n÷2)
Where 'n' is the even no. by which it is ending and
T is the previous term which is a function ending with odd no. and that we can find out by your method
Answer is 11 sqaure or 121
Thank you Bhaiya
Its a good video, keep it up buddy 👏👏👏.
Ok 🙂
Bhaiya, I am an 11th grader preparing for JEE.. 1 offline institute se kar rahi hu preperation.. Main koi sum solve karti hu mujhe kuch din baad uska logic yaad nahi rehta.. Iss wajah se mere mock tests mein mere marks bohot kam ho rhe hain.. I hope you read this comment..😃
I think there is a mistake in 2nd question answer it should be [0,1] not (0,1)
Bhai mene abhi just yeh word ap meh dekha tha book meh . 2 hr pehele
Cengage ki book mein na bhai??
15:54 Ans - 121
Fibonacci numbers founds in sunflower 🌻 😊😊
21 term ke liye 11ka square answer aayega
121????
which is best Watching video lectures in 1.5x or 1.0x
bro isnt it like in order as +1 2 times +2 to time +3 2 times and so on vo bhi ki achi series hai
First bhaiya🎉🎉❤
Hello sir, I am an also educator.
I think you should directly roast jee itself.
Subjects are deeper than any exam in the world.
How can y take (-infinite to 1) it will be (1, infinity) because u can't keep x positive in first case
Bhaiya mere test mein ese questions nahi bante but jab mein baad mein karta hun toh ho jata hai
Kya karun?
I think we are getting the deep Thinking Series furtherly maybe
Hello I know you from jee simplified from discord back then in 2022 how is prepration goin?
Legends know that this video is reuploaded
Wrong Kiya h bhai Y kabhi negative nhi ho skta aur waha tumne (-infinity to 1) kiya h.
Wo negative nhi ayega becoz x ki value negative hogi tbhi wo case hoga and fir wo overall positive ho jaayega.
Iske baare me Maine super 30 me suna tha
bahiyaa app "set of 60" class 11th ka lia kab la oo ga
Mai to ye video dekhne ke bad bhi nature ke is pattern ko nhi dekh pa rhi😅😅😅
0:20 JOJO REFRENCE
I think bhaiya, you forgot to write |x-3| in last two rows.
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man you are teaching pythagorean philosophy in INDIA
mujhe lga koi science ka trick nikalne wae ho jisse through calculations of some mysteries
Hey i had a question can u make such video for the factorial of 0 being 1
I really like to see such videos of subjects so it would really fun and intresting to see
Bro I also noticed a thing in that series that in first , second and third series have a difference of 1 , and then third fourth and fifth series has a difference of 2 ,and again after that fifth sixth and seventh series has a difference of 3 and hoping this goes on and on...hope u understand
Ey I noticed the same thing!
121 bhaiya apne odd bol Diya lakin even no.of terms .ain perfect square aa raha hai and you done mistake writting order
General solution will be [(n+1)/2]²
Where n should be odd natural number
n = (no. of terms) - 1
Or
n will be constant no. of nth term
bhai isme ek or pattern bhi ban rha h
ki phale 2 me 1 ka gap
phir next 2 me 2 ka gap
phir next 2 me 3 ka gap ......
jaise 0 to 1 ,1 ka gap
1 to 2 ,1 ka gap
2 to 4 , 2 ka gap
4 to 6 , 2 ka gap
6 to 9 , 3 ka gap
9 to 12 , 3 ka gap
12 to 16 , 4 ka gap ......
creative 👌
Bhaiya why didn't you still reveal that you have cleared jee advanced or not?
I badly failed in my first attempt.
about the second attempt, I’ll someday talk about it achhe sai. Kafi happening story hai people can get misguided that’s why I don’t wanna casually talk about it.
also, I want people to listen to me cuz I make sense. for the same reason we never boast ranks students who joined our programs got.
Goal is to create the healthiest culture. driven by passion.
@@jeesimplifiedBhaiya aap apna face revel kab karoga
Kyoki mujhe lagta hai ki mana apki aawaz phela suni hai aur ma aapko janta hu .
Maybe never. I just don’t like popularity. Not as of now.
@@jeesimplifiedunderstood bhaiya
Bhaiya reupload kiya hai na apne?
Yup, The other channel isn’t much popular so I thought of uploading here as well 😸
This is business (joking 😂)
Hw ans 121
Answers will be 121
Bhaiya aapki site open hi nhi ho rhi
it says to make some account and fir kuch open bhi nhi hot h
So please make a video for that
By the way love your teaching ❤❤
It’ll open by 3pm
14:16 bro you forgot to add graphs
14:16 nahi dikha...
Recurrence relation
Re-upload.
Video Is Re-uploaded❤
121
|x| + |x-1| + |x-2| ............... | x-r |
if r is odd then
min value =(( r-1)/2)*2
[exept x-1]
if r is even then
min value = (r(r+2))/4
From which IIT you are
I am planning to buy his website's subscription, can anyone tell me if he himself covers the topics and whether all of the maths topics are covered.
Hello bhaiya
Posted again
Bhaiya kya aap bata sakte ho jee mains ke liye board ka certificate 75 wala chaiye ya sirf woh admission ke time dena hota hai ? Bcoz I am jee dropper aur mujhe boards mein 75 che kam hai toh mein kya jee mains nahi de sakta kya?
Steel ball run