Solve Radical (Square Root) Equations with Two Radicals

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  • Опубліковано 8 вер 2024
  • This video shows how to solve square root (radical) equations with two radical expressions. The equations are rearranged so that one radical is on each side of the equals and then both sides are squared. This process is then repeated until there are no radicals remaining.

КОМЕНТАРІ • 47

  • @vl.revenge4461
    @vl.revenge4461 11 місяців тому +5

    TYSMMM. I’m in Algebra 3 Honors and trying my best to maintain my 96% in the class. Our teacher never went over a problem like this where one side of the equation has a constant after the square root (3) on problem a. This makes so much senseeee

    • @johnssolutionset
      @johnssolutionset  11 місяців тому +2

      I'm glad it helped! This double radical problems are some of the most challenging in all of algebra, so you're in good shape if you can get these.

  • @Kaylaamori
    @Kaylaamori 6 місяців тому

    Thank you for this video. Straightforward and easy to understand. Following along helped me get a problem I had been stuck on for nearly 20 minutes, massive gratitude.

  • @mendozajovy
    @mendozajovy 2 роки тому +8

    Square both sides. Then simplify. The simplification is very long and should be accurate. It must also follow the laws of exponents.

    • @johnssolutionset
      @johnssolutionset  2 роки тому +2

      On (b), it's best to add one of the square roots to the other side before squaring.

    • @mendozajovy
      @mendozajovy 2 роки тому

      @@johnssolutionset yes the radical should be transpose to the other side. It would be more complicated if you dont transpose it.

  • @o8jkk
    @o8jkk Рік тому +11

    Dude the fact that i still dont get it makes me want to jump

    • @o8jkk
      @o8jkk Рік тому +4

      I'm so done why is math hard

    • @johnssolutionset
      @johnssolutionset  Рік тому +1

      These radical equations are one of the hardest topics, so if you can get through this bit, it eases up a bit. Try this video: ua-cam.com/video/nDLPtIMz6gE/v-deo.html

  • @user-ry4on7jx5y
    @user-ry4on7jx5y 8 місяців тому +2

    I tried doing this with the equation : sqrt(9-x) = -2 + sqrt(4x -4) and it didnt work... my test is tomorrow 😬

    • @johnssolutionset
      @johnssolutionset  8 місяців тому

      Try rewriting the RHS as sqrt(4x-4) - 2, it should work then. Everything gets mangled when you have a negative in the first term of a binomial. It still works, but you need to be very careful with the signs. It's much easier to just rearrange first.

  • @lania.m
    @lania.m 8 місяців тому +1

    So by squaring the radical X-2 +3 will not undo the x-2 under the root ? The very first problem

    • @johnssolutionset
      @johnssolutionset  7 місяців тому

      that's correct - squaring a square root undoes the square root but leaves the x-2 as it is :)

  • @capbar
    @capbar 7 місяців тому +3

    Im gonna cry i still dont get it, how do u do the 2AB part

    • @johnssolutionset
      @johnssolutionset  7 місяців тому

      The 2AB part is one of the most challenging aspects of this whole thing! Here are two videos just focusing on that:
      ua-cam.com/video/whA4Baz5y-M/v-deo.html
      ua-cam.com/video/OkHMg0H_6xo/v-deo.html
      Once you master the 2AB part, return to the radical exercises. It should be much easier. Hang in there! Once you get it, things flow.

    • @T.M.R_564
      @T.M.R_564 2 місяці тому

      it is easy
      what u have to do is when u expand the (A+B)^2 First A^2 + and then multiply the values inside the brackets by 2 and the again B^2 as the square of the last value
      just memorize it then it will be easy.
      😀 god bless....

  • @bodeschelhaas1563
    @bodeschelhaas1563 7 місяців тому

    On the equation rule when do you know to use + or subtracting in the beginning for (a+b)^2 =a^2-2ab+b^2

    • @johnssolutionset
      @johnssolutionset  7 місяців тому

      It depends on the sign between the two terms. The two rules are (a+b)^2 =a^2+2ab+b^2 and (a-b)^2 =a^2-2ab+b^2, so note that the sign between the a and b is the same as the sign before the 2ab.

  • @1vandeleon629
    @1vandeleon629 Рік тому +1

    i love you man

  • @eloheministris3812
    @eloheministris3812 9 місяців тому +1

    I have an one doubt xsquare +24x+144=48x+64 then xsquare-24x+80=0 how? What about 48x after the equal symbol

    • @johnssolutionset
      @johnssolutionset  9 місяців тому

      I subtracted (48x+64) from both sides to get -24x+80 on the left and 0 on the right ☺️ ☺️

    • @eloheministris3812
      @eloheministris3812 9 місяців тому

      Thanks bro I understood

    • @eloheministris3812
      @eloheministris3812 9 місяців тому

      I am hesitat to ask this i have difficulties in division can you please teach division for me.i don't how to divide fast 3 digit and 2 digit can you please teach that please bro .this is my humble request to you

    • @johnssolutionset
      @johnssolutionset  9 місяців тому

      I'm not too good at fast division myself! I'd do some searches on UA-cam and see what comes up. Let me know if you come up with anything useful - I'd love to watch it.

  • @vjlaxmanan6965
    @vjlaxmanan6965 2 роки тому +1

    I wud've got rid of the factor 3 in the last step :( in (a) .

    • @johnssolutionset
      @johnssolutionset  2 роки тому

      That would have eventually given the right answer but required just a little more work! ☺

  • @INDIANATHEIST526
    @INDIANATHEIST526 2 роки тому +1

    Saw thumbnail and guessed squaring immediately

    • @johnssolutionset
      @johnssolutionset  2 роки тому

      Squaring indeed, but one must be sure to include the "2AB" term in the middle - the biggest mistake with these is not including the 2AB term from (A+B)^2.

  • @touhami3472
    @touhami3472 2 роки тому

    Calculus without rules is not mathematc.
    1fest equation is equivalent to :
    6sqrt(x-2)=3x-6 equivalent to
    4(x-2)=(x-2)^2 and x>=0.
    2nd equivalent to :
    sqrt(2x-4)+2= sqrt(3x+4).
    In this way, we can square both sides because they are positives (same sign).

    • @johnssolutionset
      @johnssolutionset  2 роки тому +1

      I agree that it's easier to square when the sign is positive - good point

    • @user-ky5dy5hl4d
      @user-ky5dy5hl4d 8 місяців тому +1

      @@johnssolutionset At 2:43 it is not plus ''6 squared''. You should say: + negative 6 squared, for you have (-6) squared and you are saying as if six is positive.

    • @johnssolutionset
      @johnssolutionset  8 місяців тому

      @@user-ky5dy5hl4d True! I was a little sloppy there. It should have indeed said (-6) squared. Thanks for pointing that out!

    • @user-ky5dy5hl4d
      @user-ky5dy5hl4d 8 місяців тому

      @@johnssolutionset Please, keep in mind that I did not want to be mischevious but it comes from my studies of physics where our professor demanded precise expressions. And I am not a mathemathician but I like mathematics. Now, at post school age I still like physics and I do amateur physics and people like you help me with refreshing math. But if you could, please, see what I ponder about and that is the nature of time. The World does not have the definition of time. And also: what causes the speed of light? I thank you for your effort with putting up with math for others.

  • @patches393
    @patches393 Рік тому +1

    that what i got

  • @pradyumnanayak9844
    @pradyumnanayak9844 2 роки тому

    Namaste🙏.

  • @patches393
    @patches393 Рік тому +1

    x=4

    • @johnssolutionset
      @johnssolutionset  Рік тому

      x=4 is one solution, but you're missing the second solution: x=20

  • @rakenzarnsworld2
    @rakenzarnsworld2 2 роки тому +1

    a) x=2
    b) x=4

    • @sberacatalin2250
      @sberacatalin2250 2 роки тому

      Conditions for existence of square????? Conditions for this compatibility??????? 2 and 4 it's o.k. in the up conditions???!!! Strange! Very strange!

    • @johnssolutionset
      @johnssolutionset  2 роки тому

      Halfway there - you're missing solutions in both of these. Both 6 and 2 are answers to (a), and both 4 and 20 are solutions to (b).

    • @johnssolutionset
      @johnssolutionset  2 роки тому

      @@sberacatalin2250 it's ok - everything's ok here.

  • @giuseppemalaguti435
    @giuseppemalaguti435 2 роки тому +1

    a) 6,2....b)12+8i,12-8i..... Ho sbagliato b.... che risulta 4,20

    • @johnssolutionset
      @johnssolutionset  2 роки тому

      Good catch! I wouldn't be so cruel to include complex answers on this video because it came technically before they are introduced in the class.