Thanks for your lesson. I have a query about designing the linear system for the collaborative robot (JAKA Zu5), which has a mass of 23kg. As you taught, I will be using the entire load capacity of 50kg, and the stroke length remains at 1000mm. However, I'm unsure whether the system will still function properly with a robot arm length of approximately 950mm. My goal is to implement a 7-axis system to lift the robot. Your insights on this matter are highly appreciated. Thanks again for the valuable content.
Hi Le Minh nhat, Here are my insights on Linear actuator for moving robot 1. As i can see the Robot JAKA Zu 5 has a payload of 5 kg. Please also consider in your calculation. 2. Robot reach is 954 mm, mean there will be heavy cantilever load on Linear guide. Because of shifting to centre of gravity. Calculate and select the linear guide size accordingly. 3. Axial load: calculate dynamic load according to required acceleration, also selection motor capacity accordingly 4. Maybe you will need ball screw with a customized float joint. This i have covered in upcoming next part of the series (part 8) 5. You will also need perfect linear actuator alignment base. (In next part of this series.)
Thank you for replying to me! I really appreciate your insights on the Linear actuator for moving robot. Your points make a lot of sense, and I will definitely take them into consideration while working on my project with the collaborative robot that has a wide range of movement and can potentially affect the linear guide. I will factor in the payload of the Robot JAKA Zu 5, which is 5 kg, in my calculations. Considering the robot's reach of 954 mm, I understand the importance of calculating and selecting the appropriate linear guide size to handle the heavy cantilever load caused by the shifting center of gravity. Calculating the dynamic load based on the required acceleration and selecting the motor capacity accordingly is crucial to ensure the linear actuator performs optimally. I'm looking forward to your upcoming part 8 of the series, where you cover the use of a ball screw with a customized float joint, which could be beneficial for my project. I'll also make sure to pay attention to the perfect alignment of the linear actuator base, as you mentioned in the next part of your series. If possible, I would be extremely grateful if you could consider making a video about dynamic load, particularly in the context of my project with the collaborative robot. Your expertise and insights would be incredibly valuable for me and others who are working on similar projects. Thank you once again for your helpful comments and advice!
Hi Le Minh Nhat, You welcome. I'm glad!! This channel contents are helping in real world project development, sure I'll consider more dynamic loading related machine projects in future.
Thank you very much for your videos. As a freshman student learning about machine design, I have learned a lot from your videos. They are really useful for me.
Aap bohot achhese explain karte ho bhaiyya.Thank you very much.mujhe meri company me koi bhi selection ke bare me nhi batata hai.due to company politics. But maain aapke vedio dekh dekh ke sikh rahi hu.Thank you very much.🙏
Maybe because this is my first experience on UA-cam as a creator, as well we have to understand this is a non trending specific nice channel, it will take time to grow linearly. But your love is enough motivation for me to keep patience, and make content which is really important and helpful 😊
Thank you very much for your videos, can you make separate videos for load in different directions on - LM and BS or Actuators in that if you use animation that will very helpful how loads capacity selection from catlogue..
You can design a timing pulley in solidworks with simple tools extruded cut and circular pattern. But do you have a timing belt teeth shape profile.? First you should make a selection of timing belt and pulley then look for timing belt or pulley shape profile in manufacturer catalogue
Thanks for the video. The value of load calculated from the "P" formula does not comes out 216.54 N, as you got from online calculator. Can you please check if there is some mistake? Thanks in advance
Bro excellent work even though I have good knowledge on the subjects am not able to teach others effectively as i don't know the skill of video editing could you please provide me some knowledge on that ?
Video editing is easy skill, you can learn it on UA-cam, i'm using Davinci resolve but for these videos. mainly is being creative at how to show a concept on screen. how to do visual communication, thinking from viewer perspective. (Its comes from only by doing it and keep improving little by little)
Hi.. Thank you so much for the videos. I had one doubt. My gear ratio is 1.3 and lead of ball screw is 10mm. Question is how to calculate distance travelled for one full rotation of motor pulley. I need answer in mm not rotation per minute. I mean don't include time. Looking for your reply.
Okay, so if ball screw is directly connected to motor (No gearbox) then when motor will rotate one full turn 360 deg (1 revolution) ball screw will also rotate same 1 revolution, and one full revolution of ball screw means 1 lead - 10 mm (if your case) Now, if there is gearbox in between motor and ball screw (1:3 ratio) then when motor will rotate 3 full revolutions, gearbox will transfer only 1 revolution to the ball screw. so, motor 3 rotation equal to 1 lead (10 mm), means motor 1 revolution equal to 10/3 mm. 3.333 mm
Hi good evening.. I'm very happy with your reply. I understood your answer. But please clear me. Is it correct that lead divided by gear ratio will be the travel distance for one revolution of motor pulley. Shall I take like this.@@mastermechanicaldesign
Yes Calculated SOF is too large as compared to required. So it's completely fine. You may go for lower size, but i don't. because the size of the LM block i have considered is 15. In 15 size mounting bolts size would be M4. If you will go for like 10 (in miniature series) thread size you will probably get M3 or M2.5, which is not robust overall. So for this kind of applications at least go for block size 15 Moreover. The main purpose of these calculations are verification. Not for calculating the exact sizing.
5:48 you are wrong, C is the least precision grade, the most precision grade is UP, it stands for Ultra Precision. SP - Super Precision. I suggest re-recording as it is clear you never bought a high precision grade
Yes, in Hiwin, C is a normal grade, And in my videos there are some few typos mistakes with examples calculations and also few mis-wording (just a few) which i can't eliminate 100% humanly without a big team, but I'm doing everything as alone and I'm working hard on it. I'll also bring an upgraded version of these videos later. And It will take some time. So please bear with me. As for Now i would say. The concepts and procedures i have explained are correct, and simplified to understand.
Thanks for your lesson.
I have a query about designing the linear system for the collaborative robot (JAKA Zu5), which has a mass of 23kg. As you taught, I will be using the entire load capacity of 50kg, and the stroke length remains at 1000mm. However, I'm unsure whether the system will still function properly with a robot arm length of approximately 950mm. My goal is to implement a 7-axis system to lift the robot. Your insights on this matter are highly appreciated.
Thanks again for the valuable content.
Hi Le Minh nhat, Here are my insights on Linear actuator for moving robot 1. As i can see the Robot JAKA Zu 5 has a payload of 5 kg. Please also consider in your calculation.
2. Robot reach is 954 mm, mean there will be heavy cantilever load on Linear guide. Because of shifting to centre of gravity. Calculate and select the linear guide size accordingly. 3. Axial load: calculate dynamic load according to required acceleration, also selection motor capacity accordingly
4. Maybe you will need ball screw with a customized float joint. This i have covered in upcoming next part of the series (part 8) 5. You will also need perfect linear actuator alignment base. (In next part of this series.)
Thank you for replying to me! I really appreciate your insights on the Linear actuator for moving robot. Your points make a lot of sense, and I will definitely take them into consideration while working on my project with the collaborative robot that has a wide range of movement and can potentially affect the linear guide.
I will factor in the payload of the Robot JAKA Zu 5, which is 5 kg, in my calculations.
Considering the robot's reach of 954 mm, I understand the importance of calculating and selecting the appropriate linear guide size to handle the heavy cantilever load caused by the shifting center of gravity.
Calculating the dynamic load based on the required acceleration and selecting the motor capacity accordingly is crucial to ensure the linear actuator performs optimally.
I'm looking forward to your upcoming part 8 of the series, where you cover the use of a ball screw with a customized float joint, which could be beneficial for my project.
I'll also make sure to pay attention to the perfect alignment of the linear actuator base, as you mentioned in the next part of your series.
If possible, I would be extremely grateful if you could consider making a video about dynamic load, particularly in the context of my project with the collaborative robot. Your expertise and insights would be incredibly valuable for me and others who are working on similar projects. Thank you once again for your helpful comments and advice!
Hi Le Minh Nhat, You welcome. I'm glad!! This channel contents are helping in real world project development, sure I'll consider more dynamic loading related machine projects in future.
Thank you very much for your videos. As a freshman student learning about machine design, I have learned a lot from your videos. They are really useful for me.
Thank you so Much Ben Dang ❤️❤️
Aap bohot achhese explain karte ho bhaiyya.Thank you very much.mujhe meri company me koi bhi selection ke bare me nhi batata hai.due to company politics. But maain aapke vedio dekh dekh ke sikh rahi hu.Thank you very much.🙏
You are most welcome Twinkal, Ha companies me log knowledge sharing ko le kr khud ko thoda insure feel krta hai.
Awesome sir,
I have become fan of your work, i didn't such informative video on UA-cam about mechanical design,, ....
Thanks
I'm glad 😊
I can't understand why such less view on ur channel.
Ur content is very informative
Maybe because this is my first experience on UA-cam as a creator, as well we have to understand this is a non trending specific nice channel, it will take time to grow linearly.
But your love is enough motivation for me to keep patience, and make content which is really important and helpful 😊
👍@@mastermechanicaldesign
Thank you for providing such good content
Helpful for fresher
It's my pleasure
Your content is different that is helpful for us.
Thank you Kanhiya ji
You're the man!
I liked your video 😍
Thank you so much brother... This information is very important.. all videos is helpful for us ☺️
Most welcome 😊
Thank you very much for your videos, can you make separate videos for load in different directions on - LM and BS or Actuators in that if you use animation that will very helpful how loads capacity selection from catlogue..
Noted, Omkara
Plz make video on bearing design and selection process with lubrication, thermal effect
Definitely
Can you make video on selection of lm guide actuator in software like THK
Brother, I have a doubt please explain, What spec reducer (gearbox) should I use for the Fiber Laser Cutting Machine attaching the servo motor
I don't have experience with this application, but for servo motor- planetary gearbox is a best choice
Bro NHK ko single actuator type kovload calculation jasrey Garna sakencha in order to select single axi actuator
how to design timing belt pully in solid works for 10mm pitch ,20 teeth
You can design a timing pulley in solidworks with simple tools extruded cut and circular pattern. But do you have a timing belt teeth shape profile.? First you should make a selection of timing belt and pulley then look for timing belt or pulley shape profile in manufacturer catalogue
Can you please take example for manual calculation
Conveyer motor selection pr video bnaiye..,
Jarur. Just after this series
👌 nice bro i am getting some knowledge about the selection of LM rail.
Glad to hear that
Thanks for the video. The value of load calculated from the "P" formula does not comes out 216.54 N, as you got from online calculator. Can you please check if there is some mistake? Thanks in advance
Yes, there could be some written mistakes in calculations. Please consider the value you are getting.
Please do calculations on software of thk regarding lm guide actuator selection
Okay, noted !!
@@mastermechanicaldesign thank you so much sir
Bro excellent work even though I have good knowledge on the subjects am not able to teach others effectively as i don't know the skill of video editing could you please provide me some knowledge on that ?
Video editing is easy skill, you can learn it on UA-cam, i'm using Davinci resolve but for these videos. mainly is being creative at how to show a concept on screen. how to do visual communication, thinking from viewer perspective. (Its comes from only by doing it and keep improving little by little)
Hi.. Thank you so much for the videos.
I had one doubt.
My gear ratio is 1.3 and lead of ball screw is 10mm. Question is how to calculate distance travelled for one full rotation of motor pulley. I need answer in mm not rotation per minute. I mean don't include time.
Looking for your reply.
Okay, so if ball screw is directly connected to motor (No gearbox) then when motor will rotate one full turn 360 deg (1 revolution) ball screw will also rotate same 1 revolution, and one full revolution of ball screw means 1 lead - 10 mm (if your case)
Now, if there is gearbox in between motor and ball screw (1:3 ratio) then when motor will rotate 3 full revolutions, gearbox will transfer only 1 revolution to the ball screw. so, motor 3 rotation equal to 1 lead (10 mm), means motor 1 revolution equal to 10/3 mm. 3.333 mm
Hi good evening..
I'm very happy with your reply. I understood your answer.
But please clear me. Is it correct that lead divided by gear ratio will be the travel distance for one revolution of motor pulley. Shall I take like this.@@mastermechanicaldesign
I think I need three ball screw, with motor and linear guide of 1000 mm, where can I buy the complete set? Thank you very much
I'm not about your geographic location, try to search for misumi, smc or festo. Are they available in ur place. Or any local manufacturer
Power pack design karna bataye important topic pump and motor selection kaise karna hai
Video ka plan kr rha hu
can you tell me where to find the background music?
YT studio music
Where do you get all the tables? Can you share it
Manufacturer catalogue
What if i am using 2 bearing blocks what will change in calculations?
Load distirbution will become simple. just half and half load on each
Sir one doubt at last online calculated static saftey factor 74.77 to chart value 3 -5.
How u to compare and say it's ok.😅
Yes Calculated SOF is too large as compared to required. So it's completely fine. You may go for lower size, but i don't. because the size of the LM block i have considered is 15. In 15 size mounting bolts size would be M4. If you will go for like 10 (in miniature series) thread size you will probably get M3 or M2.5, which is not robust overall. So for this kind of applications at least go for block size 15
Moreover. The main purpose of these calculations are verification. Not for calculating the exact sizing.
1.Shall I use block lifting purpose , LM Rail ,Block using hanging condition.
2.Pls share LM mounting position & angles, Not used position.
1. Yes, Block can be used for hanging condition,
Subbed 👍
5:48 you are wrong, C is the least precision grade, the most precision grade is UP, it stands for Ultra Precision. SP - Super Precision. I suggest re-recording as it is clear you never bought a high precision grade
Yes, in Hiwin, C is a normal grade,
And in my videos there are some few typos mistakes with examples calculations and also few mis-wording (just a few) which i can't eliminate 100% humanly without a big team, but I'm doing everything as alone and I'm working hard on it. I'll also bring an upgraded version of these videos later. And It will take some time. So please bear with me.
As for Now i would say.
The concepts and procedures i have explained are correct, and simplified to understand.
@@mastermechanicaldesignthe torch barrier for many engineers.. we can understand bro… keep doing your good work..
Sir kindly provide calculation pdf seperately
Okay. But i would take some time.
Bhai, hindi m video banao pls
💥 *Promo SM*
😊