What a coincidence (: I was actually deriving this version of the beta function earlier today!! However, I didn't use the trick involving absolute values to convert odd functions to even functions. Instead I simply integrated over the first quadrant since both limits are 0 and ∞. This way, we can avoid doing 4*(1/4)*4 and the limits of φ would just be 0 and π/2. By the way I really love your videos!! They never fail to make me appreciate the beauty of mathematics. Thank you for the amazing content!!
At 0:20, my mom came back from behind. She thought I am watching a Drama Show, LMAO!!! She was like: YOU ARE ALLOWED TO WATCH ONLY EDUCATIONAL VIDEOS ON UA-cam!!!! NO MONKEY DANCERS :) I closed UA-cam ATM, and I am back to watch Papa again.....BTW, good video Papa [No offence Papa...I only narrated something funny].
At 6:30 wouldn't e^(-x) be positive for mostly only real numbers though? We are taking x and y as complex arguments, because of the gamma, but yet at this part of the video we assume that something that works on the reals works on complex numbers? I'm confused
I couldn't find a closed form to it. If you can the integral of 1/arcsin(x) is non elementary, however, then then entire integral is. I did find a form that is neater for computations, though! 'In(sin(x/2)) - x*cot(x/2) + ln(x)*cot(x/2) - integral(cot(x/2)/x)dx' Notice that the sub k = sin(x/2) into the last term yields 1/arcsin(k). Hence my prior statement
Thanks to you I learned to integrate the *D i e g o Ma r a d o n a* integral = ∫ eeeeeeeeeee^x (For more understanding of this complex formula search "MARADONA EEEE EEEHH" in youtube)
![Factorial's Asymptotic Expansion - DERIVING STIRLING'S FORMULA! [ +Desmos Insights ]](http://i.ytimg.com/vi/-k7s_nXGuO0/mqdefault.jpg)
![Factorial's Asymptotic Expansion - DERIVING STIRLING'S FORMULA! [ +Desmos Insights ]](/img/tr.png)
![Eulerian Integral of the First Kind - Deriving the BETA FUNCTION! [ The non-trigonometric Version ]](http://i.ytimg.com/vi/bYS64NrR9vQ/mqdefault.jpg)
Integral from - 1 to - 1 of absolute value of x is the special papa flammy constant
You'd make a great brand ambassador for Hagoromo chalk! 😁
lol
What a coincidence (: I was actually deriving this version of the beta function earlier today!!
However, I didn't use the trick involving absolute values to convert odd functions to even functions.
Instead I simply integrated over the first quadrant since both limits are 0 and ∞.
This way, we can avoid doing 4*(1/4)*4 and the limits of φ would just be 0 and π/2.
By the way I really love your videos!! They never fail to make me appreciate the beauty of mathematics. Thank you for the amazing content!!
Thank you, this is a very important function to us in statistics. We appreciate your effort to get us to understand this subject.
:))
At 6:34, the double integral should be over ℝ^2, not ℝ
Beat function derivation? Is papa planning to derive his way to something fire?
Made me think of Jack Kerouac
Beta not Beat
You have *beaten* this function!
Thanks for the video papa, I was lacking in calcium until this moment, I have consumed and been sustained
Papa flammy the only papa who will give you spicy memes and spicy maths
5:27 "...but that's *absolutely* dope..."
that meme though :v
At 0:20, my mom came back from behind. She thought I am watching a Drama Show, LMAO!!!
She was like: YOU ARE ALLOWED TO WATCH ONLY EDUCATIONAL VIDEOS ON UA-cam!!!! NO MONKEY DANCERS :)
I closed UA-cam ATM, and I am back to watch Papa again.....BTW, good video Papa [No offence Papa...I only narrated something funny].
mathematician: uses phi for polar coordinate
physicist: laughs in weird azimuthal angle notation
*Beta function; 5:50 from -1 to 1
So is there also expressions for gamma(x) + gamma(y) and gamma(x) ^gamma(y) to make a gamma algebra sort of thing?
At 6:30 wouldn't e^(-x) be positive for mostly only real numbers though? We are taking x and y as complex arguments, because of the gamma, but yet at this part of the video we assume that something that works on the reals works on complex numbers? I'm confused
Was about to type let t=sin^2(u), but then you mentioned the sub and need for the flammy way xD
Seen this representation before in the principal of mathematical analysis by Rudin, but not the derivation
0:21 DIRECTIVE 4: [CLASSIFIED]
hey papa what’s the best way to send you spicy integral requests?
Flammable Maths okay thank you papa :v
(Limit as ---->infinity of 1/x +1)st.*Refreshes:,,fuck fourth ”* RIP
Schönes Video wie immer. Was denkst du an die Problemen von der Internationalen Mathematik Olympiade? Ich würde gerne wissen.
You forgot to substitute the r at 13:16
What is the state of the current situation with bprp and dr. Peyam?
Fucked!
He made a video on it as well as a community post about it
Wherr is the jacobian after subsitution
@@PapaFlammy69 ahhhh got u
U didnt say so i assumed u frogat
Bruh, why aren't you inegrating Zeta(bruh) d(e^bruh)?
M.R Wakawaka Let e^bruh = t => bruh = ln(t). Then the integral is the same as the integral of ζ[ln(t)] dt
@@angelmendez-rivera351 which is?
hello flammy can you integrate this:
(x-ln(x))/(sin(x)+1)
Why doesn't he heart these kinds of requests?
I couldn't find a closed form to it. If you can the integral of 1/arcsin(x) is non elementary, however, then then entire integral is. I did find a form that is neater for computations, though!
'In(sin(x/2)) - x*cot(x/2) + ln(x)*cot(x/2) - integral(cot(x/2)/x)dx'
Notice that the sub k = sin(x/2) into the last term yields 1/arcsin(k). Hence my prior statement
"Čau" was better than "see ya"
I am Indian. This is easy for me .
Maybe you should invent a symbol to represent "bruh" so you can solve integrals with respect to "bruh",idk
@@PapaFlammy69 Also,did I hear "easy peasy lemon squeezy" at 13:49?
I miss d(phi) jokes (defy)
An welcher Uni studierst du?
Fubini and polar the shyte ;)
Thanks to you I learned to integrate the *D i e g o Ma r a d o n a* integral = ∫ eeeeeeeeeee^x
(For more understanding of this complex formula search "MARADONA EEEE EEEHH" in youtube)
You probably won't get it if you don't know who Maradona is, or if you're not from Argentina.
It's complex math (and a lot of meth and m e r c a) (?
He used expensive chalk too
All of sin function of your 2nd board are actually dying xD
2:37 incorrect ... that's better!
Yee
>Mfw beat function
I'AM BRAZILIAN, I DON'T SPEAK ENGLISH
First!!!😊