Evaluate the six trig functions by when given one value and constraint
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- Опубліковано 5 лют 2025
- 👉 Learn how to evaluate the six trigonometric functions given some constraints. When given the value of one trigonometric function, we can use a right triangle with one of its legs on the x-axis and the other leg, perpendicular to the x-axis is drawn such that the reference angle is at the origin. The x-coordinate of the given point represents the adjacent of the reference angle while the y-coordinate represent the opposite of the reference angle. The hypothenuse is the line joining from the origin to the terminal side of the 'opposite' line.
Using the Pythagoras theorem, we can obtain any of the unknown sides of the right triangle. Having the opposite, the adjacent and the hypothenuse of the reference angle of the right triangle, we can then evaluate the other trigonometric functions accordingly within the given constraint.
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Seven years later and his video's are still getting at least somebody through Pre-Calc. Thank you.
They're getting me through pre-calc, too
Same
Literally
💯
Same
Very helpful, but I had to say, that was a very effective "stop talking" face at 0:36
+Joesolo13 haha had to go back and watch
Also scored big with the "Too much talking" remark at the end.
best video ever, literally saved my score and helped me to understand something that's taken me retaking the class twice in order to understand.
my teacher describes it in such a confusing way, I didn’t know it was that simple to understand thank you sm
hahah! i was so confused and freaked out when he said Ahmad... i thought he was talking to me! haha Ahmad stop talking and focus, you letting me down hahah
haha that would freak me out first
Amad got ROAStED
haha
Thank you! You explained better than my teacher lol
Why was there a 5 placed? I get the triangle is a perfect square but... what does that have to do with the 5?
My favorite teacher! You are so helpful! 谢谢 ^0^
This made it way easier to understand for me! Thanks
If you didn't post these videos, I'd fail my college class. Thank you!
For real tho
you're the man, awesome teacher
where u get that gadamn 5 .....3:02
Thank you soooooo MUCH! you saved my homework today!
Hi! My question is why how did you find 5 ? or how is it 5?
Pythagoras theorem
it equals to 25 then √25 is equal to 5.
1:26 justin got that "pay attention" callout
Shouldn't cot be 3/-4--not -3/4?
Awesome Video! Wish my teacher was as good.
Thankyou so much I am liking every video now on
you are very welcome!
great explanation! very helpful
Happy to be able to help
That was awesome 👍
how can you tell in which quadrant sine is less than 0? confused about the constraints :(
sine represents the y value on the unit circle so y is negative below the x-axis so 3rd and 4th quadrants
just draw a pic then you will see
Would this method work the same for cos 21/29 with the same constraints?
Cool, but like why 5, I’m not getting how you got that?
saME
@@thatskapKelly so what he did was did put the pathag theory which was 3^2+(-4)^2=c^2 then after doing that out you get 25. After that you square 25 to get 5
@@PBailey11 thank you so much!😭💙
if x is -4 then we cannot have triangle in the 4th quadrant. It should be either in 2nd or 3rd quadrant
What's going to be the reference angle for -9/2pi?
i love you honestly
Thank you very much
Very welcome!!
Sir but what velu of thita
I watched all of your videos and I still cannot determine which quadrant to put the triangle in. Please help !
Depends on your angle or constraint. Do you have a specific problem you cannot figure out?
yes, I have tried every way you have explained but it does not make sense to me.
For example i have two problems.
SEC thehta=-5, TAN tetha >0
TAN thetha=7/24, SEC tetha
can you please help, i hope you got my question?
T Sal I don’t think he got your question bro
@@PubStarFlash F
The hypotenuse must be a positive number? I am confused...
Distance is always positive
how did you get 5
what if there are no constraints?
Thanks so much :D
Ty!!!
I know this video is quite old, but what if it is not a perfect square?
*trianfle
@@colinspencer5654 You can use the pythagorean theorem to solve for the missing side.
Wow they didn't bother to teach us this method in class
I don't understand how you are coming up with sin(theta)
sine is negative in either the 3rd or 4th quadrant, here is a video that may help better explain ua-cam.com/video/U96qqKGTmOU/v-deo.html
Justin is probably cool
he is cool
That 21 bothers me
Who's here in 2021?
im in alg 2 why they putting me thru this bruh 😭😭😭😭
I dont understand 😭🙏
Still confused lol
Stud