Find the Arc Length of a Function with Calculus

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  • Опубліковано 24 сер 2024
  • I will show you how to find the arc length of a function using calculus. It's very easy. You only need to use two formulas that involve integrals. After you integrate, you will get the arc length of the function from point A to point B on the x-axis. This video is ideal for students currently taking Calculus 1 or Calculus 2 in either high school or university.

КОМЕНТАРІ • 28

  • @disagaharasgama7994
    @disagaharasgama7994 6 місяців тому +12

    please make more Cal 2 videos. We need you

    • @user-th4ri8dt9s
      @user-th4ri8dt9s 5 місяців тому

      remember this for calc 3 and during your last unit of calc 2 there should be parametrization (most important thing for calc 3 that I slacked off on because it was the end of semester)

  • @HappyDishHappyLife
    @HappyDishHappyLife Рік тому +8

    This is VERY well explained. Gold medal.

  • @MaharaMsefula
    @MaharaMsefula 3 місяці тому +1

    This guy should be highly recommend on you tube

  • @user-wr5pw1bi6w
    @user-wr5pw1bi6w 11 місяців тому +1

    This is very good, he made me realize what I have been looking for for some months now. more blessings to you

    • @QuocDatPhung
      @QuocDatPhung  11 місяців тому +1

      Thank you very much! Please kindly subscribe and share! You can find all of my Calculus II videos here: ua-cam.com/play/PLeTO6OT3-FKmuCeO97iKt_Aibx-a938JA.html

  • @sun650
    @sun650 Рік тому +3

    Thanks so much! Great video, really helped me out for an exam :).

    • @QuocDatPhung
      @QuocDatPhung  Рік тому +2

      I'm really glad to hear that Sun! Please kindly subscribe or share! I really appreciate it.

  • @stephenboadu1225
    @stephenboadu1225 Рік тому +3

    you saved me sir

    • @QuocDatPhung
      @QuocDatPhung  Рік тому +3

      You're so welcome Stephen! Please kindly subscribe and share with classmates, and you can find the rest of my Calculus videos in the playlist here: ua-cam.com/play/PLeTO6OT3-FKmuCeO97iKt_Aibx-a938JA.html

  • @tanishakatoch7064
    @tanishakatoch7064 7 місяців тому +1

    Thankyou this is very helpful ❤

    • @QuocDatPhung
      @QuocDatPhung  7 місяців тому +1

      You're welcome! I'm glad you like it! You can find the rest of my Calculus videos in this playlist: ua-cam.com/play/PLeTO6OT3-FKmuCeO97iKt_Aibx-a938JA.html

  • @henkoegema6390
    @henkoegema6390 5 місяців тому +1

    Well done! 😀

    • @QuocDatPhung
      @QuocDatPhung  5 місяців тому +1

      Thanks so much Henkoegema! You can find all of my Calculus II videos in the following link (don't forget to share and kindly subscribe!): ua-cam.com/play/PLeTO6OT3-FKmuCeO97iKt_Aibx-a938JA.html

  • @temwananimumba-7508
    @temwananimumba-7508 3 місяці тому +1

    Thank you ❤

    • @QuocDatPhung
      @QuocDatPhung  3 місяці тому +1

      You're welcome Temwananimumba :)!! I'm really glad you enjoyed my video! I would really appreciate if you could share with your classmates or kindly subscribe ~ you can find all of my Calculus II videos in this link: ua-cam.com/play/PLeTO6OT3-FKmuCeO97iKt_Aibx-a938JA.html

  • @quorbsky3237
    @quorbsky3237 Рік тому +4

    Quote that thing

  • @vincenciussufijanhadi1287
    @vincenciussufijanhadi1287 Рік тому +2

    How if, Y = 1 - x^1/2 , and x = 0 until x= 1.
    How long that curve.

    • @QuocDatPhung
      @QuocDatPhung  Рік тому +1

      Hi Vincen! Please use the formula mentioned in the video and let me know what you got!

  • @Zainab-ft2vj
    @Zainab-ft2vj 4 місяці тому +2

    Hi, how can I find the arc of length of a function with 2 points ( , )( , )?

    • @QuocDatPhung
      @QuocDatPhung  4 місяці тому +1

      Hi Zainab, can you give me an example of what you mean?

  • @nomsaphiri9620
    @nomsaphiri9620 Рік тому +1

    do you offer personal online tutorials?

    • @QuocDatPhung
      @QuocDatPhung  Рік тому +2

      Hi Nomsaphiri! I don't offer personal online tutorials, but please feel free to ask my questions in the comments. You can find the rest of my Calculus 2 videos here: ua-cam.com/play/PLeTO6OT3-FKmuCeO97iKt_Aibx-a938JA.html

    • @nomsaphiri9620
      @nomsaphiri9620 Рік тому +1

      @@QuocDatPhung thankyou this is very helpful

  • @pratikkulkarnibodybuilding2433
    @pratikkulkarnibodybuilding2433 4 місяці тому

    did you forget 1+ to add in last example cx formula has it and you just subtracted f(2)-f(1)?

    • @QuocDatPhung
      @QuocDatPhung  4 місяці тому +2

      No I did not forget. I did add +1 at 12:06. Let's see why:
      The integrand 1+(1/4)y^6 - 1/2+1/(4y^6) = (1/4)y^6 + 1/2+1/(4y^6) and I wrote it correctly. Let me know if you see it now.