Find the Arc Length of a Function with Calculus
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- Опубліковано 24 сер 2024
- I will show you how to find the arc length of a function using calculus. It's very easy. You only need to use two formulas that involve integrals. After you integrate, you will get the arc length of the function from point A to point B on the x-axis. This video is ideal for students currently taking Calculus 1 or Calculus 2 in either high school or university.
please make more Cal 2 videos. We need you
remember this for calc 3 and during your last unit of calc 2 there should be parametrization (most important thing for calc 3 that I slacked off on because it was the end of semester)
This is VERY well explained. Gold medal.
I'm happy that you enjoyed it!
This guy should be highly recommend on you tube
Hehe thank you!
This is very good, he made me realize what I have been looking for for some months now. more blessings to you
Thank you very much! Please kindly subscribe and share! You can find all of my Calculus II videos here: ua-cam.com/play/PLeTO6OT3-FKmuCeO97iKt_Aibx-a938JA.html
Thanks so much! Great video, really helped me out for an exam :).
I'm really glad to hear that Sun! Please kindly subscribe or share! I really appreciate it.
you saved me sir
You're so welcome Stephen! Please kindly subscribe and share with classmates, and you can find the rest of my Calculus videos in the playlist here: ua-cam.com/play/PLeTO6OT3-FKmuCeO97iKt_Aibx-a938JA.html
Thankyou this is very helpful ❤
You're welcome! I'm glad you like it! You can find the rest of my Calculus videos in this playlist: ua-cam.com/play/PLeTO6OT3-FKmuCeO97iKt_Aibx-a938JA.html
Well done! 😀
Thanks so much Henkoegema! You can find all of my Calculus II videos in the following link (don't forget to share and kindly subscribe!): ua-cam.com/play/PLeTO6OT3-FKmuCeO97iKt_Aibx-a938JA.html
Thank you ❤
You're welcome Temwananimumba :)!! I'm really glad you enjoyed my video! I would really appreciate if you could share with your classmates or kindly subscribe ~ you can find all of my Calculus II videos in this link: ua-cam.com/play/PLeTO6OT3-FKmuCeO97iKt_Aibx-a938JA.html
Quote that thing
How if, Y = 1 - x^1/2 , and x = 0 until x= 1.
How long that curve.
Hi Vincen! Please use the formula mentioned in the video and let me know what you got!
Hi, how can I find the arc of length of a function with 2 points ( , )( , )?
Hi Zainab, can you give me an example of what you mean?
do you offer personal online tutorials?
Hi Nomsaphiri! I don't offer personal online tutorials, but please feel free to ask my questions in the comments. You can find the rest of my Calculus 2 videos here: ua-cam.com/play/PLeTO6OT3-FKmuCeO97iKt_Aibx-a938JA.html
@@QuocDatPhung thankyou this is very helpful
did you forget 1+ to add in last example cx formula has it and you just subtracted f(2)-f(1)?
No I did not forget. I did add +1 at 12:06. Let's see why:
The integrand 1+(1/4)y^6 - 1/2+1/(4y^6) = (1/4)y^6 + 1/2+1/(4y^6) and I wrote it correctly. Let me know if you see it now.