I can't thank you enough for spending the time to put together such a thorough explanation of a Goodman diagram. It's been a while since my machine design course in college and this was a great refresher. Keep up the good work
Hi, im from Europe and my question is: how can be the safety factor be as high as 2,5,8? Or maybe just the difference of EU/US standards and i just need to use in EU the reciprocal of these safety factors?
I m confused as to how the Yield Line is determined. The value of Sigma, sub m I understand, but the sigma a of the Yield Line, I'm not sure how that value was determined.
+John Cullen The reliability factor comes from the normal standard distribution - some data has shown that strength varies stochastically with a standard deviation of about 8% of the mean value. If you use that standard deviation, you can calculate how much you need to reduce the stress level to maintain a 95% confidence that you're below the actual strength of the material. A single-tailed 95% confidence interval with a standard deviation of 0.08 puts you at a correction factor of 0.868. If you google around, you'll find more complete explanations with graphics.
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Thanks a lot Dr, Cyders!!! you show the basic understand of Goodman Diagram and application. Wonderful and great Video Note!
I can't thank you enough for spending the time to put together such a thorough explanation of a Goodman diagram. It's been a while since my machine design course in college and this was a great refresher. Keep up the good work
Speeding944T Cheers! Glad it was helpful!
Thank you very much Dr. Cyders for sharing this knowledge by simplifying it to very basic level.
Excellent lecture on fatigue, really helped me understand the chapter in the Shigley textbook. First rate!!
Dr. Cyders, thanks for the demo - I had forgotten some of this, and was a great review.
+Satyan Chandra Cheers! Glad it was helpful
The video is super useful. Thank You!
Thank you very much for sharing the knowledge!..it is a very clear explanation of the Goodman diagram.
Thank you Dr. Cyders!
Great job Sir .i wish i could put more likes for your videos ! they are helping me a lot.
You are an amazing one sir ! Thank you so much for your well explanation !
Thanks Dr. Cyders
Hi, im from Europe and my question is: how can be the safety factor be as high as 2,5,8? Or maybe just the difference of EU/US standards and i just need to use in EU the reciprocal of these safety factors?
I m confused as to how the Yield Line is determined. The value of Sigma, sub m I understand, but the sigma a of the Yield Line, I'm not sure how that value was determined.
thank you doctor
..exelent job, indeed thanks so much
Please can you explain me the origin of the equation σ=256963N^-0.146
hii sir, how to find the correction factors for size, loading, Sfinsh, temp and reliability
If you look in Norton or Shigley there are formulas that you can follow and make the right decision
Nice video Sir.. I don't understand one point.
How you have calculated the value of FOS=6.4 @ D=0.533in??
+Ayaz Mehmood: N=S_f(N)/Sig_a =35900/5650=6.4 ..? Is it right?
why the volume is low?
That it means the @ symbol?. I've seen in several books.
You mean lowercase Sigma? It is the symbol for normal stress. Lowercase Tau is the symbol for shear stress.
Can anyone share how C(reliability) of 95% comes out to .868 not .950?
Thanks
+John Cullen The reliability factor comes from the normal standard distribution - some data has shown that strength varies stochastically with a standard deviation of about 8% of the mean value. If you use that standard deviation, you can calculate how much you need to reduce the stress level to maintain a 95% confidence that you're below the actual strength of the material. A single-tailed 95% confidence interval with a standard deviation of 0.08 puts you at a correction factor of 0.868. If you google around, you'll find more complete explanations with graphics.
+Dr. Cyders Thank you!!!
+Dr. Cyders Thanks! that helps a lot
Thanks Dr. Cyders