Physics 16.6 Torsion (6 of 14) Torsional Pendulum (Potential Equivalent of SHM)

Поділитися
Вставка
  • Опубліковано 1 лют 2017
  • Visit ilectureonline.com for more math and science lectures!
    In this video I will equate the simple harmonic motion of a block attached to a spring to the rotational equivalent of the torsional pendulum.
    Next video in this series can be found at:
    • Physics 16.6 Torsion ...

КОМЕНТАРІ • 52

  • @arturocejudo9478
    @arturocejudo9478 4 роки тому +15

    Fricken love this guy. He has been carrying me for almost 2 years xD

  • @Sid_music
    @Sid_music 2 роки тому +12

    You have a very amazing way of explaining things! I hope you stay happy forever!

    • @MichelvanBiezen
      @MichelvanBiezen  2 роки тому +5

      Thank you. Glad you liked the video. (happiness is a product of our inner thoughts and the thoughts we entertain, and not from our circumstances. I am still trying to learn how to do that) 🙂

  • @thatgoose2639
    @thatgoose2639 4 роки тому +4

    Thanks for your videos Micheal. I'm using these videos in real world problems. Need to brush up on some of the basics.

  • @danzhang992
    @danzhang992 2 роки тому +5

    I subscribed because these videos were really helpful with my physics assignment. Would definitely recommend your channel.

    • @MichelvanBiezen
      @MichelvanBiezen  2 роки тому +1

      Welcome aboard! Glad you found our videos! 🙂🙂

  • @daphenomenalz4100
    @daphenomenalz4100 3 роки тому +1

    I saw questions on these topics so went to your videos for explanation, thank you very much

  • @MAK74737
    @MAK74737 3 роки тому +1

    i love you so much michel sir .. i have now got full concepts about torsion oscillator .. love you sir again and again

  • @sabineal-fleiti1468
    @sabineal-fleiti1468 3 роки тому +1

    All my thanks to you sir, it's very helpful and I'm gonna always refer to your channel 💝😻

  • @wangzihan778
    @wangzihan778 5 років тому +3

    Very clear!

  • @MDAviaton
    @MDAviaton 2 місяці тому

    Thank you sir, you did an excellent job explaining

  • @ftmhaidar5181
    @ftmhaidar5181 2 роки тому +3

    Hi, Thank you for your video. i have few questions: so the dtheta2/dt2 is the second derivative of the angle? also, how do you find the first derivative of angular velocity? ( is that basically the theta (t)=theta max *sin(wt)?)

    • @MichelvanBiezen
      @MichelvanBiezen  2 роки тому +1

      The answer to your first question is yes. The answer to your second question is: first find the angle with respect to time via the sin of cos function. Then take the first derivative to find angular velocity. Then take the second derivative to find angular acceleration. You'll need to know how to find the derivative of a cos and a sin function.

  • @juanperinatserrano5294
    @juanperinatserrano5294 4 роки тому +1

    Hi, I am doing a research project about the torsional pendulum. I will be finding 'k' through an experiment.
    My teacher has asked me before doing the experiment to give him a literature value of 'k' so I can then compare the experiment result with such literature value. I cant find the literature value of 'k' anywhere. Can you help me?

  • @wendidyyiii1466
    @wendidyyiii1466 2 роки тому +2

    this video is amazingly clear

  • @fatinaxis1618
    @fatinaxis1618 Рік тому +1

    Stay magical forever, Sir. May AllaH grant your wishes.

  • @bradfordtownsend9698
    @bradfordtownsend9698 7 років тому +6

    Excellent, thank you

    • @Saemsen78
      @Saemsen78 5 років тому

      For you to see / ua-cam.com/video/D04aqDi_who/v-deo.html

  • @kps5629
    @kps5629 5 місяців тому +1

    Really useful series of videos, thanks a lot. I have a question concerning the units of the torsional constant. If torque is N*m and give the equation torque= constant * angle, should not the unit be N*m/rad?

    • @MichelvanBiezen
      @MichelvanBiezen  5 місяців тому +2

      Radian is actually a "non-unit" and can therefore be left off. But for clarity, and the avoidance of confusion it is a good idea to add it. (But many books don't)

    • @kps5629
      @kps5629 5 місяців тому +1

      Thank you so much !

  • @skhasnattarifzim9043
    @skhasnattarifzim9043 6 років тому +3

    thank you sir

  • @AsilKhalifa
    @AsilKhalifa 8 місяців тому +2

    Sir, when the torsional pendulum setup is immersed in water, because there would be an opposing force due to viscosity, the time period would increase. Is my thinking correct?

  • @mpesks
    @mpesks 4 роки тому

    like you explanation!

  • @yes338
    @yes338 Рік тому +1

    hi may i ask if Period and mass of the torque disc is inversely proportional? (Since for the torsional pendulum, since Period is equal to (2 pi)(square root of K divided by I), and I is proportional to mass and radius) If this is the case, does it mean that the higher the mass the ower the period? thanks so much and loveee ur videos by the way!

    • @MichelvanBiezen
      @MichelvanBiezen  Рік тому +2

      The period is proportional to the square root of the mass.

    • @yes338
      @yes338 Рік тому +1

      @@MichelvanBiezen thank you!

  • @nuriziyak
    @nuriziyak Рік тому +1

    Firstly, thank you so much for your contents. I have a question: I see the equation of x as x ( t ) = A cos ( ω t + ϕ ) in my textbook and some sources in the internet. But as in that video and some other sources it is written with sinus. What is the difference? How would we decide to use which trigonometric function?

    • @MichelvanBiezen
      @MichelvanBiezen  Рік тому +2

      The choice of sin or cos only depends on the initial conditions at t = 0. If the displacement is maximum at t = 0 choose cos. If the displacement is zero at t = 0, and moving in the positive direction use sin. This will not affect the period, frequency, etc.

    • @nuriziyak
      @nuriziyak Рік тому +1

      @@MichelvanBiezen I got it! Thank you so much for your efforts. :)

  • @andersonalvessouza9067
    @andersonalvessouza9067 5 років тому

    Thank you.

  • @Dave-bf2lc
    @Dave-bf2lc 4 роки тому

    awesome!

  • @sakhemcetywa6847
    @sakhemcetywa6847 3 роки тому

    Thank you

  • @dataar7441
    @dataar7441 4 роки тому +1

    Thankkkkk you

  • @uasserkamal2002
    @uasserkamal2002 2 роки тому +1

    sir , in 2:35 this moment of inetia for a cylinder not a flat disk

    • @MichelvanBiezen
      @MichelvanBiezen  2 роки тому +2

      The moment of inertia is the same for a flat disk and for a cylinder.

  • @Mercento
    @Mercento 5 років тому

    @1:10 the solution to the differentiation equation, is it possible to show us the steps of how it is done?

  • @jakehate
    @jakehate 3 роки тому

    very helpful thanks :)

  • @ZoyaKhan-we8zi
    @ZoyaKhan-we8zi 7 років тому +4

    thank you sooo much sir

    • @Saemsen78
      @Saemsen78 5 років тому

      For you to see / ua-cam.com/video/D04aqDi_who/v-deo.html

    • @ajaypatil2887
      @ajaypatil2887 3 роки тому

      Hii

  • @fakharzaman102
    @fakharzaman102 6 місяців тому +1

    Good

  • @omarzedan1727
    @omarzedan1727 3 роки тому

    يخربيت العظمه