Physics 16.6 Torsion (6 of 14) Torsional Pendulum (Potential Equivalent of SHM)
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- Опубліковано 1 лют 2017
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In this video I will equate the simple harmonic motion of a block attached to a spring to the rotational equivalent of the torsional pendulum.
Next video in this series can be found at:
• Physics 16.6 Torsion ...
Fricken love this guy. He has been carrying me for almost 2 years xD
You have a very amazing way of explaining things! I hope you stay happy forever!
Thank you. Glad you liked the video. (happiness is a product of our inner thoughts and the thoughts we entertain, and not from our circumstances. I am still trying to learn how to do that) 🙂
Thanks for your videos Micheal. I'm using these videos in real world problems. Need to brush up on some of the basics.
I subscribed because these videos were really helpful with my physics assignment. Would definitely recommend your channel.
Welcome aboard! Glad you found our videos! 🙂🙂
I saw questions on these topics so went to your videos for explanation, thank you very much
You are welcome!
i love you so much michel sir .. i have now got full concepts about torsion oscillator .. love you sir again and again
Happy to help
All my thanks to you sir, it's very helpful and I'm gonna always refer to your channel 💝😻
Thank you we appreciate that.
Very clear!
Thank you sir, you did an excellent job explaining
Hi, Thank you for your video. i have few questions: so the dtheta2/dt2 is the second derivative of the angle? also, how do you find the first derivative of angular velocity? ( is that basically the theta (t)=theta max *sin(wt)?)
The answer to your first question is yes. The answer to your second question is: first find the angle with respect to time via the sin of cos function. Then take the first derivative to find angular velocity. Then take the second derivative to find angular acceleration. You'll need to know how to find the derivative of a cos and a sin function.
Hi, I am doing a research project about the torsional pendulum. I will be finding 'k' through an experiment.
My teacher has asked me before doing the experiment to give him a literature value of 'k' so I can then compare the experiment result with such literature value. I cant find the literature value of 'k' anywhere. Can you help me?
this video is amazingly clear
Glad you like it.
Stay magical forever, Sir. May AllaH grant your wishes.
Thank you. 🙂
Excellent, thank you
For you to see / ua-cam.com/video/D04aqDi_who/v-deo.html
Really useful series of videos, thanks a lot. I have a question concerning the units of the torsional constant. If torque is N*m and give the equation torque= constant * angle, should not the unit be N*m/rad?
Radian is actually a "non-unit" and can therefore be left off. But for clarity, and the avoidance of confusion it is a good idea to add it. (But many books don't)
Thank you so much !
thank you sir
Sir, when the torsional pendulum setup is immersed in water, because there would be an opposing force due to viscosity, the time period would increase. Is my thinking correct?
That is correct.
@@MichelvanBiezen thanks sir
like you explanation!
hi may i ask if Period and mass of the torque disc is inversely proportional? (Since for the torsional pendulum, since Period is equal to (2 pi)(square root of K divided by I), and I is proportional to mass and radius) If this is the case, does it mean that the higher the mass the ower the period? thanks so much and loveee ur videos by the way!
The period is proportional to the square root of the mass.
@@MichelvanBiezen thank you!
Firstly, thank you so much for your contents. I have a question: I see the equation of x as x ( t ) = A cos ( ω t + ϕ ) in my textbook and some sources in the internet. But as in that video and some other sources it is written with sinus. What is the difference? How would we decide to use which trigonometric function?
The choice of sin or cos only depends on the initial conditions at t = 0. If the displacement is maximum at t = 0 choose cos. If the displacement is zero at t = 0, and moving in the positive direction use sin. This will not affect the period, frequency, etc.
@@MichelvanBiezen I got it! Thank you so much for your efforts. :)
Thank you.
awesome!
Thank you
Thankkkkk you
sir , in 2:35 this moment of inetia for a cylinder not a flat disk
The moment of inertia is the same for a flat disk and for a cylinder.
@1:10 the solution to the differentiation equation, is it possible to show us the steps of how it is done?
very helpful thanks :)
Glad it helped!
thank you sooo much sir
For you to see / ua-cam.com/video/D04aqDi_who/v-deo.html
Hii
Good
Thank you
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