DT Convolution-Simple Example Part 2

Shows how to compute the discrete-time convolution of two simple waveforms.
This video was created to support EGR 433:Transforms & Systems Modeling at Arizona State University. Links to other videos can be found at www.engineering... and sites.google.co...
This video is made available under the Creative Commons BY-SA license.

[@sandratobias2158]

This is one of the best examples of DT convolution I've seen so far. Thank you!!!!!!

[@courtneygreer961]

I watched ALOT of videos and this one helped me the most!! THANK YOU!!

[@anokhias]

At 7:00 he does a mistake where he writes 2 instead of 3 on x-axis. To know if your final answer is write, just check the original signals. Final end points must always be the sum of original end points of two signals.

[@ArmanAKAWaver]

This is honestly REALLY helpful. What the lecturer spent 2 weeks explaining, I learnt in 30 mins from watching this 2 part video. Thanks a lot! (Arman - UK)

[@Marcello91Brigante]

tnx man,really helped me out :)

[@muhammadmubeeniqbal3614]

Best explaination of convo THANKS

[@marekhonek1607]

Thanks a lot for very clear explanation!

[@TheAthenan]

Thank you for helping me to finish my homework :)

[@sdw4527]

Very helpful! My professor has such a strong accent, it's hard to understand his lectures.

[@MagnusonX]

That seems to be very common in the U.S.

[@PedramNG]

U explain so well man ... thank u so much sir

[@metamud8686]

This explains clearly how to compute the convolution, but I still don't understand what it means. I see the two signals, I see the graph of the convolution, but what does that convolution mean? Is it where the one signal "best matches" the other signal? What does it mean when there is a 'peak' in the convolution signal? What do min and max of the convoluted signal mean? What can I do with this???

[@Malik-qh7wq]

I usually don't comment, but thank you very much!!

[@Okami87]

Great video sir!

[@khaledalhorani7965]

Thanks a million.

[@PinkyNgcobo]

Thank you so much...

[@aaajojoaaa]

you are the best, thank you

[@EvilSapphireR]

THANK YOU!

[@adrianceballos8372]

Thanks!!

[@sreyesreddy8494]

You can choose for one of the above gifts

[@bingbongboi2401]

Thank you!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

[@engcaiobarros]

I think you made a mistake in minute 4:30 - Y[n] = 0 not when n < 4 but when n

[@veysel231]

thanks

[@youmah25]

شكرا

[@saadasm9746]

you saved my life, Thank you boss

[@cikAYU92]

thanks. likeee!
i'm from Malaysia :)

[@sallminrexha]

He is multiplying x[k] with h[2-k] so 2*(-2)=-2 just like he states at x[k]h[2-k] graph

[@congkhanh2310]

Sorry! Why don't you find Y[+-5]?

[@mateusmaia9627]

values less than n = -4 or even bigger will be the product of x[k]h[n-k], which is Y[n], equal to zero. n= -4 means a delay for 4 units(to the left), its just to chek out the pictures on the video and you will see :D

[@asefafzali72]

thAnks sir , so much usefull / from afghanistan

[@simonstanev2923]

10x