@The Adel a chemistry degree would require one to know all this. Calling himself an organic chemistry tutor is still correct because you need to know all of this for it. any degree that will require organic chemistry will require Math, chemistry, physics, thermo, statics, statistics, material science.
@@PokeMultiverse correct, majors in college that require you to take organic chemistry such as BIO, chem, and some engineering majors also require you to take enough calculus that you’ll cover newtons law of cooling.
i feel bad for anyone who disliked this video. I pay 12k a year to go to class not understand anything just to come home and learn everything I need to know in 20 minutes from this guy. IS it the way I would like it to be? no not really but it is what it is and pass I will. nothing to dislike here you are an amazing teacher and I wish my professors were all like you. Thank you
Yes see so many selfish people..90k+ views and just 1k likes..people just watch the vid and then close YT..forgetting to like..unlike me, I like his vids first and then watch it coz I know it surely gonna help me
Watched this video an hour before my exam, it came and I got all full 10 marks, thank you so much sir. College would be better if we had a way to clone you and make you the professors in all universities.
Thank you so much! I understood it so much better after your clear explanation! I'm actually doing this in a Maths class so will hopefully be looking out for more Maths help from you :)
Supreme professor! I was talking about frozen water and wondering how long would it take to go back to liquid phase ,next day I saw your video and what I say there's is a supernatural power behind these calculus. Never knowing I could use differentials! Amazing chemico_ physical world!
Awesome video and great instruction. I actually did this over the weekend with a bottle of soda and worked through this formula first, got my solution and then took another bottle and took the temp every 15mins for 2hrs 45mins and I came within .7 degrees of the math answer which I chalked up to opening and closing the fridge door to get the bottle's temp.
I love that during this topic in both precalculus and calculus1, we were only given "Ae^kt" and never told about ANY of this temperature stuff, whatsoever. Nobody thought it would be beneficial to let us know.
@@MegumiJA Derivatives help us find instantaneous rate of change. We would like to know the instantaneous rate of change of the temperature with respect to time. The rate of change of the temperature with respect to time is proportional to some constant (-k, the decay constant, because we are cooling) and the difference between the starting temperature of the object and the surrounding temperature. Hope this helps!
MR. Organic Chemistry Tutor, thank you for a massive analysis of the classical Newton Law of Cooling and its relationship to initial and final temperature.
I don't know if you figured it out, but he explains the reason he did that. We are trying to figure out how much LONGER it is going to take going from 80 degrees to 70 degrees.
Amir Hanna, no he did not as he is correct. T0 in this case is 80 because we are rinding the time from 80 to 70 degrees, here we are beginning at 80. That is why. Imagine we are starting at 80 not 100, as we already know 100 to 80 takes 12 mins. If we find 80 to 70, which he does, we can add it to 12 to find 100 to 70, thus we let 80 be T0
It doesn't create a difference. Suppose, after integration, he had a constant on both LHS and RHS, LHS + m = RHS + n We can now subtract m on both sides, LHS = RHS +n - m Now as n and m are both arbitrary constants, we can let n - m = c Thus, LHS = RHS + c So he just skipped this one step of adding constants on both sides. Hope this helps :)
Can you discuss this A temperature with an initial temperature of 70° is placed in a room with a controlled temperature of 22 degrees after 3 minutes the thermometer with 60 degreesdetermine how long will the thermometer reads 30° determine also on the reading after 8 minutes
can u help me to solve this using same methods u describe here?..A substance takes 3 min in cooling from 50C to 45 C and takes 5 min in cooling from 45C to 40C. What is the temperature of surrounding?
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I like how he doesn't skip any step however simple it is..
This is his secret sauce, never skipping anything means that the thing you don't know how to do will always be covered
I like how the Organic Chemistry tutor does not only tutor organic chemistry.
@The Adel He did bachelor's in Chemistry, I read that while ago on his pateron site
Its amazing what he teaches a truly talented and hardworking intellectual.
he tutors your whole high school math and science curriculum
@The Adel a chemistry degree would require one to know all this. Calling himself an organic chemistry tutor is still correct because you need to know all of this for it. any degree that will require organic chemistry will require Math, chemistry, physics, thermo, statics, statistics, material science.
@@PokeMultiverse correct, majors in college that require you to take organic chemistry such as BIO, chem, and some engineering majors also require you to take enough calculus that you’ll cover newtons law of cooling.
i feel bad for anyone who disliked this video. I pay 12k a year to go to class not understand anything just to come home and learn everything I need to know in 20 minutes from this guy. IS it the way I would like it to be? no not really but it is what it is and pass I will. nothing to dislike here you are an amazing teacher and I wish my professors were all like you. Thank you
18 thousand views and ONLY 115 likes?? C'mon people, we've all benefitted from TOCT's videos. He worked hard making these, PLEASE LEAVE A LIKE!
this is facts. this man is the best teacher i've ever had
Yes see so many selfish people..90k+ views and just 1k likes..people just watch the vid and then close YT..forgetting to like..unlike me, I like his vids first and then watch it coz I know it surely gonna help me
U r right bro..
After 2 years of upload I am watching this video with just 1k+ likes
damn feels weird seeing ur own comment 7 months later
Ok I liked
Watched this video an hour before my exam, it came and I got all full 10 marks, thank you so much sir. College would be better if we had a way to clone you and make you the professors in all universities.
You are lucky 😁
Me rn, dunno bout full 10 tho
I love your work. Thank you. You have saved my degree.
Your tutorial videos really help me a lot in my exams. Thank you for everything. I will never survive in my engineering subject without you.
Are you studying engineering
this guy has replaced my math's professor. I dont even go to classes anymore bc its all here lol
Thank you so much! I understood it so much better after your clear explanation! I'm actually doing this in a Maths class so will hopefully be looking out for more Maths help from you :)
Supreme professor! I was talking about frozen water and wondering how long would it take to go back to liquid phase ,next day I saw your video and what I say there's is a supernatural power behind these calculus. Never knowing I could use differentials! Amazing chemico_ physical world!
Physically have no idea how my engineering maths lecturers made this so complicated - Thank you !
Awesome video and great instruction. I actually did this over the weekend with a bottle of soda and worked through this formula first, got my solution and then took another bottle and took the temp every 15mins for 2hrs 45mins and I came within .7 degrees of the math answer which I chalked up to opening and closing the fridge door to get the bottle's temp.
Awesome comment. The theoretical answer does now always correspond with the real-world answer. This actually brings in a nice discussion on error.
Better than Khan Academy especially the voice 10/10
Khan academy video focus on concept only and not simplifying and explaining
stop hating on khan academy. that man made like a million videos and is trying his best
thnks, super easy to understand your concept. I solved my coursera problem because your lecture. Really appreciate it!
any concept i dont get, this guy has a video on it. bro is a legend.
i’m not even in physics anymore i’m just trying to make a fancy tea
I love that during this topic in both precalculus and calculus1, we were only given "Ae^kt" and never told about ANY of this temperature stuff, whatsoever. Nobody thought it would be beneficial to let us know.
I love you man
-Much love from a stressed & depressed calculus student ;)
me rn i want this to end (not my life)
your videos have taught me my entire college algebra course thank you sir
It's really nice to study when it's understandable
Thank you for this. This video is the best explanation for Newton's Law of Cooling that I have found. Excellent job.
It seems as if you are the real newton, meaning to say you are a great tutor , you have rescued me
you have now idea how helpful this is to me. thank you for this vid!!
I AM GRATEFUL TO LEARN FROM THIS CHANNEL. IT HELPED ME MASSIVELY DURING EXAMS.
literally so helpful for my assignment. Thank you!
The derivation had me laughing out loud. That’s incredible. So cool
hi, may i ask, why do we need to derivative the formula
@@MegumiJA Derivatives help us find instantaneous rate of change. We would like to know the instantaneous rate of change of the temperature with respect to time. The rate of change of the temperature with respect to time is proportional to some constant (-k, the decay constant, because we are cooling) and the difference between the starting temperature of the object and the surrounding temperature.
Hope this helps!
@@SeanBenson23 it helps a lot, thank you so much!!
Thank you for deriving it too. Liked
MR. Organic Chemistry Tutor, thank you for a massive analysis of the classical Newton Law of Cooling and its relationship to initial and final temperature.
Thank you so much! your videos help simplify math.
I legit still have no idea how this works but the example did help me on one problem
very well done. good luck in all your endeavors
Thanks alot man...crystal cleared
Thank you once again...Now I have confidence
thank u sir......💐
This was really helpful, much appreciated.
Thank u so much this was really helpful👍
you literally just saved my life omg
👍 nicely done
This guy is a legend
Very good lecturer
The unsung hero of STEM students far and wide..
This is great sir , thank you
Can you (please) make a video about Simple Chemical Conversion?
top notch teaching
This is an awesome video!
Very Meaningful.thanks
litterly awsome not even single doubt
You are so good.
YOU ARE A LIFE SAVER
Explaining good👍
Thank you. You simplified a monster.......😂😂😂😂😂😂
6:15
My teacher--2 hours
You----23 minute💀💀
You are blessed Sir🙌
Very helpful for students like me.
6:05 I though that its 100-50 not 80-50. Could u please explain in that part... Thanks. In advance
He corrects himself shortly after.
I don't know if you figured it out, but he explains the reason he did that. We are trying to figure out how much LONGER it is going to take going from 80 degrees to 70 degrees.
Amir Hanna, no he did not as he is correct. T0 in this case is 80 because we are rinding the time from 80 to 70 degrees, here we are beginning at 80. That is why. Imagine we are starting at 80 not 100, as we already know 100 to 80 takes 12 mins. If we find 80 to 70, which he does, we can add it to 12 to find 100 to 70, thus we let 80 be T0
Can anyone explain me why when he integrated 1/(T-T_s) to be ln(T-T_s) he didn't add the constant C , but when he integrated -k he added the constant?
It doesn't create a difference. Suppose, after integration, he had a constant on both LHS and RHS,
LHS + m = RHS + n
We can now subtract m on both sides,
LHS = RHS +n - m
Now as n and m are both arbitrary constants, we can let n - m = c
Thus, LHS = RHS + c
So he just skipped this one step of adding constants on both sides. Hope this helps :)
@@kushagrashrivastava9452 yeah i got it some time ago but thanks so much for your time anyway!
@@kushagrashrivastava9452 the friend who helped me used the same words ,, he just skipped one step " :)
Fantastic question
Thanks much much!♥♥♥♥
I'm a freakin art student why do I have to go through this suffering.... you saved my from failing physics
Can you discuss this
A temperature with an initial temperature of 70° is placed in a room with a controlled temperature of 22 degrees after 3 minutes the thermometer with 60 degreesdetermine how long will the thermometer reads 30° determine also on the reading after 8 minutes
Perfect👌
forever grateful
this helped a lot
Mark Wahlberg is that you?
12:28 for diff eq!
Thanks a lot sir
What is the formula for law of heating?
If what you said is true, then why does the object reach room temperature. Wouldn't it take an infinite amount of time?
great vid
Isnt the first equation e^kt (not e^-kt)?
How do I find K of real materials?
6:04 why is the initial temperature equal to 80 there and not 100?
nvm lol 21.52 - 12 minutes = 9.52 minutes LONGER
I should probably finish the video before asking for help
@@alexhagdahl3321 thanks for your comment I was turning my brain upside down tryin to figure out why i got 21,52 instead of 9,52
what if the object is placed in water?? will Ts still be a constant??
it is good content
wow respect from nepal
thank you
80 X 12?
good guy
what is dt? I knows its delta time but how do I find delta time.
Thanks
what if you don't have the time for an object at x degrées to cool to y degrées?
Thankyuuuu
✍✍✍noted with thanks!!!
Why did you use e
this is cool
excuese sir,i don't know your name,what is your name?
All the billionaires in the world, and you deserve to be one of them
18:04 why does the dT dissapear from the equation?
plz explain if u got that point
where did you get the 80 from?in the first beginning, I don't get it.
i think it should be 100
it is because at 12 minutes the object cools to 80 degrees as stated in the problem
at T(12) the object has already cooled to 80 degrees
If this man says natural log wrong again I'm gonna freak
why T0 is =80 i dont get it
2 min silence for those who can't find this vid
can u help me to solve this using same methods u describe here?..A substance takes 3 min in cooling from 50C to 45 C and takes 5 min in cooling from 45C to 40C. What is the temperature of surrounding?
34.6 C
Austin Lee how’d you do it
Disliking his videos feels like a sin🥲
Your first example is wrong. Try checking it. At t=9.5mins the temperature will be 50 not 70.
It should be 2.16 minutes for the temperature to be 70.
at t=0 the T must be 100C and t=12 T must be 80C. Am I right??
watching this while don't have any idea about derivative. me stop school 😨😨😨😣😵💫😵 whats going here
Any UTP students here ?
💖✨
sir onde brought me here
nah turning the T0 into =80 is a bad idea