This is not 5 volt to 1.5 volt ok. This is 3.7 volt to 1.5 volt. And I think that no need to use complex circuite. Only use 4007 diode 2nos or 1nos serials that's all. It will be work more than your circuite. Thanks.10:53
There is a problem in that, from battery voltage 4.1v to 1.5v you have to drop 2.6v. With each diode 0.7v drop you need 3.7 diodes(2.6/0.7) . Which means that is tough to get. But this circuit it will be accurate 1.5v. For simple voltage drops what is told is good but not with more voltage. Hope you understand
3.7 -1.4 = 2.3v to the clock. This will not work for the clock that accepts 1.5v ok. Instead of 2 resistor, I connected the 547 transistor to 50k pot and measured how much max I can apply and I discovered the clock can only take up to 1.8v. Above 1.85v, the mechanism will start going crazy, the clock makes a lot of noise and you may damage the clock
Добрый день. На сколько хватает одного заряда такого аккумулятора.
Спасибо)
Very long life if you are using original Li-ion battery with 2000mAh
Good one, it will be better if you could add the circuit diagram
It contains only 3 components, that is why I didn't add the circuit diagram
How are you going to recharge it?
We have to manually recharge. We can attach a TP4056 charging module, but it will reduce its portabiliy
Very nice
Thanks
❤❤❤❤❤ nice video ❤❤❤❤Thank
Thank you too
Very good sir
Thanks
Show me something on 5volt convet to 1.5 volt with diagrams thanks
Dc-dc step down or buck moduleis the best choice. please have a look at this amzn.to/40asbC4
How you calculated the 10k and 8.2k
Voltage divider network using resistor for base biasing the transistor.
Red coloured wire for +ve volt and black wire for -ve volt. Follow correct electronic principles
Sure sir, when assembling I do not have those color wires
This is not 5 volt to 1.5 volt ok. This is 3.7 volt to 1.5 volt. And I think that no need to use complex circuite. Only use 4007 diode 2nos or 1nos serials that's all. It will be work more than your circuite. Thanks.10:53
There is a problem in that, from battery voltage 4.1v to 1.5v you have to drop 2.6v. With each diode 0.7v drop you need 3.7 diodes(2.6/0.7) . Which means that is tough to get. But this circuit it will be accurate 1.5v. For simple voltage drops what is told is good but not with more voltage. Hope you understand
I thought it was 5v to 1.5v , but when i watched the video i came to know it was 3.7 to 1.5V but it was a cool implementation.
Theories shows ok. But practicaly not always ok. 2 diode formula is working approx 2 years in my wall clock. Ok.
So ur giving 2.6v to the quartz clock. Still it was running. Wow that is a new information to me. Thanks. I will try
3.7 -1.4 = 2.3v to the clock. This will not work for the clock that accepts 1.5v ok. Instead of 2 resistor, I connected the 547 transistor to 50k pot and measured how much max I can apply and I discovered the clock can only take up to 1.8v. Above 1.85v, the mechanism will start going crazy, the clock makes a lot of noise and you may damage the clock