Exponential Equation 1/x=27^x | Solving Exponential Equations | Exponential Equations | India math.

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  • Опубліковано 1 гру 2024

КОМЕНТАРІ • 61

  • @AhmedAli-re1gm
    @AhmedAli-re1gm Рік тому +5

    تحياتى لك من مصر .. طريقتك ممتازة وتحترم عقل الطالب المبتدئ .. رائع استمر .. تمنياتى لك بالتوفيق

    • @onlineMathsTV
      @onlineMathsTV  Рік тому +1

      Wow!!! Thanks a million for this encouraging words @Ahmed Ali.
      We will put in our best possibility in order not to fail people like you and others who believe in our little beginning.
      We all @onlinemathstv in Nigeria love you and all Egyptians sir.
      much respect from Naija to you sir....💖💖💖💕❤️❤️💕💕

  • @Vadirajknvadairaj
    @Vadirajknvadairaj 9 місяців тому

    Very nice mathematical lecture lt helps a lot

  • @scienceandrailwaychannel679
    @scienceandrailwaychannel679 8 місяців тому

    Amazing and thanks you

  • @ProfeJulianMacias
    @ProfeJulianMacias Рік тому +2

    Great teaching

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Really? thanks a million for finding out tutorial helpful sir. We aim at giving people like you who appreciate little effort the best in this channel.
      We all @onlinemathstv love you for sharing this sir....💖💖💖

  • @quantumxgaming439
    @quantumxgaming439 Рік тому +1

    Good question

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Many thanks for this acknowledgement sir/ma.
      Respect👍👍👍

  • @Mohammad1Ahmad
    @Mohammad1Ahmad Рік тому +2

    bravo👍

    • @onlineMathsTV
      @onlineMathsTV  Рік тому +1

      Thanks master....
      We love you from the the depth of our hearts for watching and commenting sir...💕💕💕💖💖💖

  • @hogec_enlightenmentarena6975
    @hogec_enlightenmentarena6975 Рік тому +3

    👏Nice bro

  • @elharratimohamed2332
    @elharratimohamed2332 Рік тому

    Super exelent tres bien sehr gut perfekto جيد جدا

  • @danielfranca1939
    @danielfranca1939 Рік тому

    Nice explanation Jakes....👍👍👍

    • @onlineMathsTV
      @onlineMathsTV  Рік тому +1

      Thanks @Daniel Franca for always watching our videos and also commenting.
      We all @ONLINEMATHSTV love you from the depth of our hearts.💖💖💖

  • @Aloksbil
    @Aloksbil Рік тому +2

    Brilliant

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Thanks a million sir.
      Much love from all of us @onlinemathstv...💖💖💕💕❤️

  • @sulimanibra5332
    @sulimanibra5332 Рік тому

    Fine

  • @Aziakpono-nh8gy
    @Aziakpono-nh8gy Рік тому +2

    Kudos master

  • @fellipearrais1090
    @fellipearrais1090 Рік тому +1

    Parabéns pelo canal, excelentes abordagens.

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Many thanks to you sir.
      Much love from all of us @onlinemathstv.💕💕💕

  • @josechrlistian7971
    @josechrlistian7971 Рік тому +2

    Muito bom!👏

  • @crickw4456
    @crickw4456 Рік тому

    Very nice, keep it up ❤👉🇵🇰

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Thank you and we will do as you have encouraged us sir.
      As you keep visiting this channel, we will try our possible best not to disappoint you.
      Thanks and we love you sir💖💖❤️❤️💕💕

  • @jesusbedoya52
    @jesusbedoya52 Рік тому

    👏👏👏

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Respect sir.
      Thanks for cheering onlinemathstv up sir.
      We love you because this is a big encouragement to onlinemathstv.
      Much love💖💖💖💕💕💕

  • @honey-qqq
    @honey-qqq Рік тому +1

    👍🌹

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Many thanks to you for this comment sir.
      We all @onlinemathstv love you for finding our content fascinating....💖💖💖

  • @ashwanibeohar8172
    @ashwanibeohar8172 Рік тому +2

    By seeing the eqn it is clear that x= 1/3

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Bravo 👍👍👍
      Respect sir 🙏🙏🙏

  • @ekanshsingh056
    @ekanshsingh056 8 місяців тому

    X=1/3 solved just within 2 second

  • @chaparral82
    @chaparral82 Рік тому

    1/3 just looking

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      The the master. You are good at what you boss.
      Respect sir🙏🙏🙏

    • @chaparral82
      @chaparral82 Рік тому

      @@onlineMathsTV 🤣

  • @ChristelleHilaire-lb6pu
    @ChristelleHilaire-lb6pu Рік тому

    ×=+27^2

  • @vishwambharmahant9485
    @vishwambharmahant9485 Рік тому

    1/3

  • @Birol731
    @Birol731 Рік тому +4

    My way of solution is:
    1/x= 27ˣ
    (1/x)¹/ˣ= 27ˣ/ˣ
    (1/x)¹/ˣ= 27
    1/x=u
    uᵘ= 27
    27= 3³, so:
    uᵘ= 3³
    u=3
    1/x=3
    x= 1/3 is the answer 🙏

    • @onlineMathsTV
      @onlineMathsTV  Рік тому +2

      Great and a nice approach master. Bravo....!!!👍👍👍
      You are good at it sir.
      Respect🙏🙏🙏

  • @s.h.munasingha2590
    @s.h.munasingha2590 Рік тому

    X=1/3

  • @FractAlkemist
    @FractAlkemist Рік тому

    Solved with a simple GA written in Python; X = 0.3333333333333333 .
    1/X = 3.0 , 27**X = 3.0 , difference = 0.0 , solving the equation.
    Program run time 3 seconds.

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      But that is AI, we need human solving it here. You can not make use of the AI in the examination hall.

    • @FractAlkemist
      @FractAlkemist Рік тому

      @@onlineMathsTV Get used to it. In a few years AI gonna be running everything.

    • @NYlivinginTN
      @NYlivinginTN Рік тому

      ​@@FractAlkemistno, current AI is limited to inputs. It lacks creativity. AI cannot imagine.

    • @FractAlkemist
      @FractAlkemist Рік тому

      @@NYlivinginTN Have you used ChatGPT recently?

  • @sans1331
    @sans1331 Рік тому

    1/x=27^x
    raise both sides to 1/x
    y=1/x
    y^y=27
    i know that 3^3=27, but thats too close to guess-and-check, so allow me to use this neat method i found online
    1. find any number, like 5
    2. take 5th root of 27, call it a
    3. take a’th root of 27, call it a2
    and keep going
    4. to increase efficiency, every 2 iterations, take the mean of the 2, b, and use that in the next iteration
    a=27^1/5=1.9331…
    a1=27^1/a=5.5007…
    b=(a+a1)/2=3.7169…
    a2=27^1/b=2.4271…
    a3=27^1/a2=3.8880…
    b1=(a2+a3)/2=3.1576…
    with iterations approaching infinity, this gets us to 3
    y=3=1/x
    *x both sides
    3x=1
    /3 both sides
    x=1/3

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Although appeared complex but I think I have learnt a new approach to this challenge from Sans.
      Thanks for sharing this unique approach with Onlinemathstv sir.
      Respect...👍👍👍

  • @JimmyBaevsky
    @JimmyBaevsky Рік тому

    Hello"
    Equation with unknown vatiable as a member of usual algebraic expression and in power element principally can't resolved in algebra and needs special functions. So it's not algebraic task.😂

    • @onlineMathsTV
      @onlineMathsTV  Рік тому +1

      ok sir, thanks for the observation.
      Respect 👌👌👌

    • @JimmyBaevsky
      @JimmyBaevsky Рік тому

      @@onlineMathsTV I think you're kidding, Sir

  • @ChristelleHilaire-lb6pu
    @ChristelleHilaire-lb6pu Рік тому

    Marry me I love you Lord blesses you

  • @waterbuffalo867
    @waterbuffalo867 Рік тому

    x = 1/3
    27^(1/3) = 3 or the cube root of 27 (means 3 x 3 x 3 = 27, so we take one 3 out of three 3)

  • @danielfranca1939
    @danielfranca1939 Рік тому

    Nice explanation Jakes....👍👍👍

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Thanks for dropping this wonderful and encouraging comment.
      Much love...💖💖💖