G-log and Lambert w function method. Which is the quicker and less cumbersome?

This equation which is a combination of exponential and linear functions can be solved using two methods, the G-log method and the Lambert w function method. Which method is faster and less complicated? You will find out in the video.
#glogmethod
#lambertwfunctionmethod
#exponentialandlinearfunctionequation

[@barteqw]

We can easily notice the Lambert w function is correlated with glog function by following formulas:
1) w(x)=-glog(-1/x)
2) glog(x)=-w(-1/x)

[@justmathsbymike]

Really? That's interesting. I will research this further. Thanks for the info. I appreciate.

[@ugomikechinonso]

great video

[@justmathsbymike]

Welcome

[@frontmarkfamily9429]

The lambert w function method is eaier. thanks

[@justmathsbymike]

Thanks

[@Abby-hi4sf]

around @7:16 you have W [ -ln5/5 ] . I think you can write 1/5 as 5^-1 and 5 = e^ln5 so 5^-1 = e^-ln5
then W[ (-ln5./5)] = W [ (-ln5)(e^-ln5) ] = -ln5

[@justmathsbymike]

True

[@GodwinPeculiar-or3zs]

Please under what topic is this question?

[@justmathsbymike]

Under exponential equation